Feedback Lab 4 - Trinity College Dublin
... The estimated difference of 5.12 is not statistically significant at the 5% level; t = 1.7, p = 0.9. Explain the make up of the Pooled Standard Deviation. The sum of squared deviations from the mean is calculated for each sample separately and then pooled, that is, added, and the average squared dev ...
... The estimated difference of 5.12 is not statistically significant at the 5% level; t = 1.7, p = 0.9. Explain the make up of the Pooled Standard Deviation. The sum of squared deviations from the mean is calculated for each sample separately and then pooled, that is, added, and the average squared dev ...
March2006
... We assume here that the population may be modelled using a normal distribution with unknown mean but known variance 2 For example, suppose one wants to investigate IQ of students at StAndrews. As you cannot study the whole population, you need to measure the IQ’s of a random sample of students. I ...
... We assume here that the population may be modelled using a normal distribution with unknown mean but known variance 2 For example, suppose one wants to investigate IQ of students at StAndrews. As you cannot study the whole population, you need to measure the IQ’s of a random sample of students. I ...
Chapter 8: Introduction to Hypothesis Testing
... 15. a. H0: μ < 50 (endurance is not increased). The critical region consists of z-scores beyond z = +1.65. For these data, σM = 1.70 and z = 1.76. Reject H0 and conclude that endurance scores are significantly higher with the sports drink. b. H0: μ = 50 (no change in endurance). The critical region ...
... 15. a. H0: μ < 50 (endurance is not increased). The critical region consists of z-scores beyond z = +1.65. For these data, σM = 1.70 and z = 1.76. Reject H0 and conclude that endurance scores are significantly higher with the sports drink. b. H0: μ = 50 (no change in endurance). The critical region ...
Populations and Samples Chapter 8
... were asked to give themselves and each other a grade on their contribution to the group. A random sample from two of the teams yielded the following results: Q R X Q = 87.5 ...
... were asked to give themselves and each other a grade on their contribution to the group. A random sample from two of the teams yielded the following results: Q R X Q = 87.5 ...