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L33
L33

... • Thus far we have been dealing only with what is called geometrical optics • In geometrical optics we deal only with the behavior of light rays  it either travels in a straight line or is reflected by a mirror, or bent (refracted) when it travels from one medium into another. • However, light is a ...
1 - CNU.edu
1 - CNU.edu

... elbow joint as the axis of rotation. [1.79] N m (b) If the net torque obtained in part (a) is nonzero, in which direction will the forearm and hand rotate? [clockwise] (c) Would the net torque exerted on the forearm and hand? Why? ...
Concept Question: Rotating Rod
Concept Question: Rotating Rod



... incident under the angle Φ=37˚. The pump beam is provided by a Ti:sapphire laser. • The condensate scatters the light superradiantly into two counter-propagating cavity modes. • The atomic momentum distribution is taken via ...
Today: Quantum mechanics
Today: Quantum mechanics

... In a test of eye sensitivity, experimenters used 1 millisecond (0.001 s) flashes of green light. The lowest power light that could be seen was 4x10-14 Watt. How many green (500 nm, 2.5 eV) photons is this? A. 10 photons B. 100 photons C. 1,000 photons D. 10,000 photons Tues. Nov. 17, 2009 ...
L 36 — Modern Physics [2] The Photon Concept How are x
L 36 — Modern Physics [2] The Photon Concept How are x

Diapositiva 1 - Instituto de Astronomía
Diapositiva 1 - Instituto de Astronomía

This worksheet uses the concepts of rotational
This worksheet uses the concepts of rotational

... rotating about its axis, the rotational kinetic energy is given by: K rot  12 I2 . If, in addition, the center of mass of the wheel is translating, then the translational kinetic energy is given by K trans  12 Mv 2 . To find the total kinetic energy of the system, add the individual contributions ...
Lecture 2
Lecture 2

Tuesday, June 26, 2007 - UTA High Energy Physics page.
Tuesday, June 26, 2007 - UTA High Energy Physics page.

Momentum and Impulse
Momentum and Impulse

... The same change in momentum may be the result of a SMALL force exerted for a LONG time, or a LARGE force exerted for a SHORT time. ...
Chapter 3 Problem Set
Chapter 3 Problem Set

... Before we can solve for power we have to convert the time (25 min) into seconds: t = 25 min X 60 sec/min = 1,500 sec Now solving for the power: P = W/t = 253,820 J/1500 sec = 169 w (watts) 24. A boy throws a 4-kg pumpkin at 8 m/sec to a 40-kg girl on roller skates, who catches it. At what speed does ...
The Strong Force and the Internal Structure of Neutrons and Protons
The Strong Force and the Internal Structure of Neutrons and Protons

Angular Momentum
Angular Momentum

... vi = 2 m/s in a circle of radius ri = 0.2 m. The cord is then slowly pulled from below, decreasing the radius of the circle to r = 0.1 m. What is the puck’s speed at the smaller radius? Find the tension in the cord at the smaller radius. May 22, 2017 ...
1-5 Conservation of Angular Momentum
1-5 Conservation of Angular Momentum

PPT - LSU Physics
PPT - LSU Physics

Dynamics of a System of Particles
Dynamics of a System of Particles

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G484 Definitions

Document
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... 13. Loss in PE by Y = gain in PE of X + gain in KE by X plus Y Gain in KE of the system = 5 (10) (2) – 4(10)(2 sin 30o) = 60 J 14. From A to B, friction acts down the incline. Work done by friction = Fs = 2.6 x AB cos 180o = -2.6 x 10/sin 30o = - 52 J From B to C, friction acts up the incline . Work ...
chapter 9 notes physics 2
chapter 9 notes physics 2

... rotation is placed. You typically will choose the location so that the lines of action of one or more of the unknown forces pass through the axis. This will simplify the torque equation making the math easier. Remember the direction of your force indicates whether it is positive or negative with res ...
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A 1

Class: XII Subject: Physics Topic: Electromagnetic Waves No. of
Class: XII Subject: Physics Topic: Electromagnetic Waves No. of

... 14. A radiation of energy E falls normally on a perfectly reflecting surface. The momentum transferred to the surface is a. E/c b. 2 E/c c. Ec d. E/c2 ...
Experiment 9 - WFU Physics
Experiment 9 - WFU Physics

... very likely will fall to some lower orbit. The energy can be emitted in the form of light. This light is visible provided the energy lost by the atom lies in the range of about 2.8 10-19 J to 5.0 10-19 J for each electronic transition. (This is approximately the range of energies per atom which is ...
6.1.5. Number Representation: Operators
6.1.5. Number Representation: Operators

photoeffect
photoeffect

... » There was a threshold frequency for ejection Classical physics failed to explain this, Lenard won the Nobel Prize in Physics in 1905. ...
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Photon polarization

Photon polarization is the quantum mechanical description of the classical polarized sinusoidal plane electromagnetic wave. Individual photon eigenstates have either right or left circular polarization. A photon that is in a superposition of eigenstates can have linear, circular, or elliptical polarization.The description of photon polarization contains many of the physical concepts and much of the mathematical machinery of more involved quantum descriptions, such as the quantum mechanics of an electron in a potential well, and forms a fundamental basis for an understanding of more complicated quantum phenomena. Much of the mathematical machinery of quantum mechanics, such as state vectors, probability amplitudes, unitary operators, and Hermitian operators, emerge naturally from the classical Maxwell's equations in the description. The quantum polarization state vector for the photon, for instance, is identical with the Jones vector, usually used to describe the polarization of a classical wave. Unitary operators emerge from the classical requirement of the conservation of energy of a classical wave propagating through media that alter the polarization state of the wave. Hermitian operators then follow for infinitesimal transformations of a classical polarization state.Many of the implications of the mathematical machinery are easily verified experimentally. In fact, many of the experiments can be performed with two pairs (or one broken pair) of polaroid sunglasses.The connection with quantum mechanics is made through the identification of a minimum packet size, called a photon, for energy in the electromagnetic field. The identification is based on the theories of Planck and the interpretation of those theories by Einstein. The correspondence principle then allows the identification of momentum and angular momentum (called spin), as well as energy, with the photon.
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