PHYS101 Second Major – zero version Q1. A stone of mass 1.0 kg
... An object of mass m1 = 2.0 kg is moving with a velocity of 4.0 m/s along the x-axis on a frictionless horizontal surface and collides with another object of mass m2 = 3.0 kg initially at rest. After collision both masses continue to move on the frictionless surface as shown in Figure 7. If m1 moves ...
... An object of mass m1 = 2.0 kg is moving with a velocity of 4.0 m/s along the x-axis on a frictionless horizontal surface and collides with another object of mass m2 = 3.0 kg initially at rest. After collision both masses continue to move on the frictionless surface as shown in Figure 7. If m1 moves ...
The Law of Conservation of Mechanical Energy
... Find the velocity that a bullet of mass 1.00 X 10-2 kg would have to have so that it has the same momentum as a lighter bullet of mass 1.8 X 10-3 kg and velocity 325 m/s. Question 3 (To be solved in class) A golfer strikes a golf ball of mass 0.05 kg and the time of impact between the golf club and ...
... Find the velocity that a bullet of mass 1.00 X 10-2 kg would have to have so that it has the same momentum as a lighter bullet of mass 1.8 X 10-3 kg and velocity 325 m/s. Question 3 (To be solved in class) A golfer strikes a golf ball of mass 0.05 kg and the time of impact between the golf club and ...
1. Mass, Force and Gravity
... projectile will fall in the first second of motion. But this implies that if the (horizontal) muzzle velocity were 8,000 meters per second, the downward fall of the cannonball would be just matched by the earth’s surface falling away, and it would never hit the ground! This is just the motion, famil ...
... projectile will fall in the first second of motion. But this implies that if the (horizontal) muzzle velocity were 8,000 meters per second, the downward fall of the cannonball would be just matched by the earth’s surface falling away, and it would never hit the ground! This is just the motion, famil ...
Examples and problems to the system of particles
... factory floor by a constant force exerted on the m1 at an angle α= 25° to the horizontal. The µ1 = 0,11 (coefficient of kinetic friction between the heavier crate and the floor) and µ2 = 0,18 (coefficient of kinetic friction between the lighter crate and the floor). What should the magnitude of the ...
... factory floor by a constant force exerted on the m1 at an angle α= 25° to the horizontal. The µ1 = 0,11 (coefficient of kinetic friction between the heavier crate and the floor) and µ2 = 0,18 (coefficient of kinetic friction between the lighter crate and the floor). What should the magnitude of the ...
33-6 Radiation Pressure
... Electromagnetic waves have linear momentum as well as energy exerted a radiation pressure on an object by shining light on it. the pressure must be very small like a camera flash every photographic flash could be like a punch. Finding an expression for the pressure by shining a beam ...
... Electromagnetic waves have linear momentum as well as energy exerted a radiation pressure on an object by shining light on it. the pressure must be very small like a camera flash every photographic flash could be like a punch. Finding an expression for the pressure by shining a beam ...
The Two Body Problem
... earth’s moon is considered. The force on the moon due to the sun has a greater magnitude than that on the moon due to the earth. The moon basically orbits the sun while the earth perturbs its motion to speed up and slow down and to weave inside of and outside of the earth’s orbit. None-the-less, the ...
... earth’s moon is considered. The force on the moon due to the sun has a greater magnitude than that on the moon due to the earth. The moon basically orbits the sun while the earth perturbs its motion to speed up and slow down and to weave inside of and outside of the earth’s orbit. None-the-less, the ...
Current_Classes_files/HW Chpt 9 Lin Momentm
... 12) In the two-dimensional elastic collision of a particle with a stationary particle that has the same mass, the trajectories of the two particles after the collision are at right angles to each other. Explain why this should be so. 13) In space there is nothing for the rocket to "push against" so ...
... 12) In the two-dimensional elastic collision of a particle with a stationary particle that has the same mass, the trajectories of the two particles after the collision are at right angles to each other. Explain why this should be so. 13) In space there is nothing for the rocket to "push against" so ...