11-7 Considering Conservation, and Rotational Kinetic Energy
... 11-7 Considering Conservation, and Rotational Kinetic Energy In step 4 of Exploration 11.6, we stated that the angular momentum of the system consisting of Sarah and the merry-go-round was conserved, because no external torques were acting on the system. Let’s justify that statement. We do not have ...
... 11-7 Considering Conservation, and Rotational Kinetic Energy In step 4 of Exploration 11.6, we stated that the angular momentum of the system consisting of Sarah and the merry-go-round was conserved, because no external torques were acting on the system. Let’s justify that statement. We do not have ...
PH2213 : Examples from Chapter 7 : Work and Kinetic Energy Key
... This problem is taken from the sample problems for test 2, where we used Newton’s Laws and equations of motion to solve for the speed at the bottom of the ramp, so you may want to refer to that example. We used g = 9.8 m/s2 in that version of the solution, so let’s do that again here so we should ge ...
... This problem is taken from the sample problems for test 2, where we used Newton’s Laws and equations of motion to solve for the speed at the bottom of the ramp, so you may want to refer to that example. We used g = 9.8 m/s2 in that version of the solution, so let’s do that again here so we should ge ...
The purpose of this course is to introduce the key
... 134. Explain how atomic spectra may be used to determine the composition of stars. 135. Describe the Bohr model of the atom, including his formula for energy levels. 136. Explain why, according to classical physics, atoms should not exist. 137. Describe wave-particle duality and give examples (how h ...
... 134. Explain how atomic spectra may be used to determine the composition of stars. 135. Describe the Bohr model of the atom, including his formula for energy levels. 136. Explain why, according to classical physics, atoms should not exist. 137. Describe wave-particle duality and give examples (how h ...
Section 2 Chapters 5-8 Chapter 5 Energy Conservation of Energy is
... Problem: If a student studies 10 hour under a 100 watt light bulk and electricity cost $.10 per kikowatt hour how much does it cost the student? Answer 100x10 = 1kw hour $0.1 Problem A 3200 lb car goes form 0 to 60 mph in 4 sec. What horse power engine I needed. Answer 60 mph = 88 ft sec and mass of ...
... Problem: If a student studies 10 hour under a 100 watt light bulk and electricity cost $.10 per kikowatt hour how much does it cost the student? Answer 100x10 = 1kw hour $0.1 Problem A 3200 lb car goes form 0 to 60 mph in 4 sec. What horse power engine I needed. Answer 60 mph = 88 ft sec and mass of ...
Lesson Plan: Energy Basics
... said that it had 1.5 horsepower. Although the unit of horsepower is still used today, it does not accurately describe how many horses it replaces. This is because not every horse is the same.) ...
... said that it had 1.5 horsepower. Although the unit of horsepower is still used today, it does not accurately describe how many horses it replaces. This is because not every horse is the same.) ...
Year 11 GCSE Physics Work, Power and
... They tie off the rope when the bucket is just above the ground. As they are making their way downstairs to unload the bucket, a strong wind sets the bucket swinging. Draw a diagram of the path of the swinging bucket. On your diagram: mark with the letter A — where the potential energy is greatest. m ...
... They tie off the rope when the bucket is just above the ground. As they are making their way downstairs to unload the bucket, a strong wind sets the bucket swinging. Draw a diagram of the path of the swinging bucket. On your diagram: mark with the letter A — where the potential energy is greatest. m ...
Work and Energy
... If the force is not constant, then one must sum the work done over each of a series of very small displacements, where the force is approximately constant over each small displacement. In calculus, this process is described in terms of integration. The concept of work is most useful for point partic ...
... If the force is not constant, then one must sum the work done over each of a series of very small displacements, where the force is approximately constant over each small displacement. In calculus, this process is described in terms of integration. The concept of work is most useful for point partic ...
Document
... velocity is zero. The average speed is a scalar quantity and defined as the total distance traveled divided by it takes = 40 km /2 h = 20 km/h The instantaneous velocity vx equals the limiting value of the ratio ∆x/∆t ∆x dx as ∆t approaches zero. ...
... velocity is zero. The average speed is a scalar quantity and defined as the total distance traveled divided by it takes = 40 km /2 h = 20 km/h The instantaneous velocity vx equals the limiting value of the ratio ∆x/∆t ∆x dx as ∆t approaches zero. ...
Ch12 Potential energy
... i.The physically important quantity is ΔU U x1 U. x0 Not U x1 or U x 0 . ii.We are free to choose the reference point at any convenient location for the potential energy. iii.Potential energy belongs to the system (Such as ball-Earth) and not of any of the individual objects within the system. C ...
... i.The physically important quantity is ΔU U x1 U. x0 Not U x1 or U x 0 . ii.We are free to choose the reference point at any convenient location for the potential energy. iii.Potential energy belongs to the system (Such as ball-Earth) and not of any of the individual objects within the system. C ...
Spring Simple Harmonic Oscillator Spring constant Potential Energy
... We can’t tell the difference. All we can tell is that the angular frequency has changed. Notice that besides the period oscillation, we can also perceive that ω is changed from the fact that the maximum velocity (= Aω), and the maximum acceleration (= Aω2) is changed, while A is not changed. The gra ...
... We can’t tell the difference. All we can tell is that the angular frequency has changed. Notice that besides the period oscillation, we can also perceive that ω is changed from the fact that the maximum velocity (= Aω), and the maximum acceleration (= Aω2) is changed, while A is not changed. The gra ...
Topic 2 Mechanics Part 3 and 4 projectile, friction,10
... vx and vy . Vx is always constant in magnitude and direction throughout the flight. V y decreases going up due to gravity pushing down. Vy increases going down due to gravity. vy at the top = 0. vx is constant throughout the flight and NOT zero at the top. vy0 = initial velocityy Do not confuse vy0 ...
... vx and vy . Vx is always constant in magnitude and direction throughout the flight. V y decreases going up due to gravity pushing down. Vy increases going down due to gravity. vy at the top = 0. vx is constant throughout the flight and NOT zero at the top. vy0 = initial velocityy Do not confuse vy0 ...
Higher Revision Cards
... Explain why a buoyancy force acts on an object when it is submerged in a fluid. ...
... Explain why a buoyancy force acts on an object when it is submerged in a fluid. ...
Higher Revision Cards A4
... Explain why a buoyancy force acts on an object when it is submerged in a fluid. ...
... Explain why a buoyancy force acts on an object when it is submerged in a fluid. ...
CHAPTER Work and Energy
... 35 ·· Force A does 5 J of work in 10 s. Force B does 3 J of work in 5 s. Which force delivers greater power? PA = (5/10) W = 0.5 W; PB = (3/5) W = 0.6 W; PB > PA. 36 · A 5-kg box is lifted by a force equal to the weight of the box. The box moves upward at a constant velocity of 2 m/s. (a) What is th ...
... 35 ·· Force A does 5 J of work in 10 s. Force B does 3 J of work in 5 s. Which force delivers greater power? PA = (5/10) W = 0.5 W; PB = (3/5) W = 0.6 W; PB > PA. 36 · A 5-kg box is lifted by a force equal to the weight of the box. The box moves upward at a constant velocity of 2 m/s. (a) What is th ...
356 Linear Kinetics
... This example further demonstrates the change in resultant force due to air resistance. Notice that initially air resistance due to the body falling through the air reduces the magnitude of the acceleration but it remains a downward acceleration. Eventually you reach a point where the air resistance ...
... This example further demonstrates the change in resultant force due to air resistance. Notice that initially air resistance due to the body falling through the air reduces the magnitude of the acceleration but it remains a downward acceleration. Eventually you reach a point where the air resistance ...
Kinetic energy - GZ @ Science Class Online
... Unbalanced forces change motion Balanced forces cause no change in speed or direction, since they exert equal, but opposite, push/pull effects on an object. Unbalanced forces can change the speed and/or direction of an object ...
... Unbalanced forces change motion Balanced forces cause no change in speed or direction, since they exert equal, but opposite, push/pull effects on an object. Unbalanced forces can change the speed and/or direction of an object ...
Course: Advanced Placement Physics B Teacher: Mr. Nathan
... Draw a well-labeled free-body diagram Differentiate between static and kinetic friction Demonstrate proficiency in solving problems that involve constant acceleration (elevators, inclined planes, Atwood’s Machine) Apply the use of torques to extended objects and prove that rotational equilibrium is ...
... Draw a well-labeled free-body diagram Differentiate between static and kinetic friction Demonstrate proficiency in solving problems that involve constant acceleration (elevators, inclined planes, Atwood’s Machine) Apply the use of torques to extended objects and prove that rotational equilibrium is ...