
Geosynchronous Orbit Laboratory
... 8) Do these values for V and r that you found above fit your equation that you found for the Velocity (V) as a function of the radius (r)? Tell why your answer makes sense. What value do you get when you plug the value of r above into the equation you derived from your graph for v. These values of V ...
... 8) Do these values for V and r that you found above fit your equation that you found for the Velocity (V) as a function of the radius (r)? Tell why your answer makes sense. What value do you get when you plug the value of r above into the equation you derived from your graph for v. These values of V ...
Questions - HCC Learning Web
... 8 - 11 A 2.00-kg object is attached to a spring and placed on a horizontal, smooth surface. A horizontal force of 20.0 N is required to hold the object at rest when it is pulled 0.200 m from its equilibrium position (the origin of the x axis). The object is now released from rest with an initial pos ...
... 8 - 11 A 2.00-kg object is attached to a spring and placed on a horizontal, smooth surface. A horizontal force of 20.0 N is required to hold the object at rest when it is pulled 0.200 m from its equilibrium position (the origin of the x axis). The object is now released from rest with an initial pos ...
motion - Images
... Push a car that never moves B Two people push a box in opposite B directions causing the box to go nowhere Two people push a box in opposite directions causing the box to slide slightly to the right. U ...
... Push a car that never moves B Two people push a box in opposite B directions causing the box to go nowhere Two people push a box in opposite directions causing the box to slide slightly to the right. U ...
4 outline
... • Downward force is weight. • a = weight/mass • but an object with twice the mass will have twice the weight… • so the accelerations are the same… • We call this acceleration “g”. • g is about 10m/s/s downward. ...
... • Downward force is weight. • a = weight/mass • but an object with twice the mass will have twice the weight… • so the accelerations are the same… • We call this acceleration “g”. • g is about 10m/s/s downward. ...
HonorsReview
... Similarly throughout the school year we have used many line graphs to determine the relations between different variables. The intention was to derive a relation rather than memorize a formula. When you solve a problem always relate to FBD, energy bar graphs, graphs, or motion diagrams to get a basi ...
... Similarly throughout the school year we have used many line graphs to determine the relations between different variables. The intention was to derive a relation rather than memorize a formula. When you solve a problem always relate to FBD, energy bar graphs, graphs, or motion diagrams to get a basi ...
Earthquake Notes
... 7. The ________________________ of the wave can be used to determine the magnitude of the earthquake. ii. Finding the Epicenter: 1. To locate an earthquake epicenter: a. Scientists first determine the ____________________________ distance from three different seismographs. The longer the time ______ ...
... 7. The ________________________ of the wave can be used to determine the magnitude of the earthquake. ii. Finding the Epicenter: 1. To locate an earthquake epicenter: a. Scientists first determine the ____________________________ distance from three different seismographs. The longer the time ______ ...
Chapter 8 File
... x = displacement of the mass from its unstretched (not too large) (-) sign: the force exerted by the spring is always directed opposite the displacement of the mass. -The value of k is a measure of the stiffness of the spring. -Stiff spring large k -Soft spring small k -A particular type of peri ...
... x = displacement of the mass from its unstretched (not too large) (-) sign: the force exerted by the spring is always directed opposite the displacement of the mass. -The value of k is a measure of the stiffness of the spring. -Stiff spring large k -Soft spring small k -A particular type of peri ...
Use the following to answer question 1
... Use the following to answer question 7: A physics student in a hot air balloon ascends vertically at constant speed. Consider the following four forces that arise in this situation: F1 = the weight of the hot air balloon F3 = the force of the student pulling on the earth F2 = the weight of the stud ...
... Use the following to answer question 7: A physics student in a hot air balloon ascends vertically at constant speed. Consider the following four forces that arise in this situation: F1 = the weight of the hot air balloon F3 = the force of the student pulling on the earth F2 = the weight of the stud ...
Extra Credit Problems
... moves downward at right angles to its initial direction. Find the final speeds of the two masses and the final scattered angle for the 4 kg ball. Answer: V4 kg = 1.673 m/s, V1 kg = 2.967 m/s, 4 kg = 26.310 above the horizontal 14) A chain of length 1.2 meters and total mass 2.5 kg is released from ...
... moves downward at right angles to its initial direction. Find the final speeds of the two masses and the final scattered angle for the 4 kg ball. Answer: V4 kg = 1.673 m/s, V1 kg = 2.967 m/s, 4 kg = 26.310 above the horizontal 14) A chain of length 1.2 meters and total mass 2.5 kg is released from ...
AP Physics C - Heritage High School
... Circular Motion and Rotation Torque r F rF sin • Rotational analog for force – depends on the force applied and the distance from the axis of rotation • If more than one torque is acting on an object then you simply sum the torques to find the net torqu ...
... Circular Motion and Rotation Torque r F rF sin • Rotational analog for force – depends on the force applied and the distance from the axis of rotation • If more than one torque is acting on an object then you simply sum the torques to find the net torqu ...