Study Guide for Physics Final Exam—1st semester
... How fast will it be going? D = ½ at2 v = at a of gravity = 10 m/s2 D = ½ (10)(4.5)2 v = (10)(4.5) D = ½ (10) 20.25 v = 45 m/s D = ½ 202.5 D = 101.24 m 14. A rock is thrown straight out from a cliff. Compared to a rock that is dropped straight down from the same height, which one will hit the ground ...
... How fast will it be going? D = ½ at2 v = at a of gravity = 10 m/s2 D = ½ (10)(4.5)2 v = (10)(4.5) D = ½ (10) 20.25 v = 45 m/s D = ½ 202.5 D = 101.24 m 14. A rock is thrown straight out from a cliff. Compared to a rock that is dropped straight down from the same height, which one will hit the ground ...
07FExamF - TTU Physics
... a. Calculate the spring constant k of the spring. (Hint: This statement is about work or ENERGY, not about force! You can’t use a force relation to calculate k!) A mass m is attached to this spring. It is pulled a distance x = A from its equilibrium position & is released from rest. It undergoes sim ...
... a. Calculate the spring constant k of the spring. (Hint: This statement is about work or ENERGY, not about force! You can’t use a force relation to calculate k!) A mass m is attached to this spring. It is pulled a distance x = A from its equilibrium position & is released from rest. It undergoes sim ...
Study Guide for Ch 6 Test Newtons Laws
... When Cambridge reopened in 1667, Newton was given a minor position at Trinity and began his academic career. His studies in optics led to his invention of the reflecting telescope in the early 1670s. In 1672, his first public paper was presented, on the nature of light and color. Newton longed for p ...
... When Cambridge reopened in 1667, Newton was given a minor position at Trinity and began his academic career. His studies in optics led to his invention of the reflecting telescope in the early 1670s. In 1672, his first public paper was presented, on the nature of light and color. Newton longed for p ...
1988
... sin ), and the final momentum p/ = (–mv cos , mv sin ). The change in momentum p = p/ – p = (–2mv cos , 0). The magnitude of p is just 2mv cos . (We know that the vertical momentum cannot be changed, because when the ball hits the racquet, the force exerted is, surprise surprise, the normal f ...
... sin ), and the final momentum p/ = (–mv cos , mv sin ). The change in momentum p = p/ – p = (–2mv cos , 0). The magnitude of p is just 2mv cos . (We know that the vertical momentum cannot be changed, because when the ball hits the racquet, the force exerted is, surprise surprise, the normal f ...
Unit 7 Work, Energy, Power Book concept questions Work Pg. 278
... is the net work done on the car? (Both = 1.31 x 106 J) 6. A train of mass 2.50 x 104 kg is powered across a level track with a force of 5.0 x 105 N over a distance of 509 m. a) Calculate the work done on and the change in KE of the train 2.55 x 108 J b) If the initial velocity of the train was zero, ...
... is the net work done on the car? (Both = 1.31 x 106 J) 6. A train of mass 2.50 x 104 kg is powered across a level track with a force of 5.0 x 105 N over a distance of 509 m. a) Calculate the work done on and the change in KE of the train 2.55 x 108 J b) If the initial velocity of the train was zero, ...
Gravity Investigation
... eight? Mass is the amount of matter in an object. It does not change based on where an object is. Weight is the force with which gravity is pulling on a mass. We know from Newton’s Second Law that Force = Mass x Acceleration. Since Weight is the Force acting on the object, “W” can be substituted f ...
... eight? Mass is the amount of matter in an object. It does not change based on where an object is. Weight is the force with which gravity is pulling on a mass. We know from Newton’s Second Law that Force = Mass x Acceleration. Since Weight is the Force acting on the object, “W” can be substituted f ...
