Probability Theory
... Prove that, given that the number of geomagnetic reversals in the first 100 Bernoulli trials is equal to 4 (that is, {S100 = 4}), the joint distribution of (T1 , . . . , T4 ), the vector of the number of 282 ky periods until the 1st., 2nd., 3rd. and 4th. geomagnetic reversals, is the same as the dis ...
... Prove that, given that the number of geomagnetic reversals in the first 100 Bernoulli trials is equal to 4 (that is, {S100 = 4}), the joint distribution of (T1 , . . . , T4 ), the vector of the number of 282 ky periods until the 1st., 2nd., 3rd. and 4th. geomagnetic reversals, is the same as the dis ...
4.3 The Binomial Distribution
... a. Compute P(x = 0) using binomial formula b. Compute P(x ≤ 2) = P(x = 0) + P(x = 1) + P(x = 2) using binomial formula (p. 191) c. Compute the expected value µ of x d. Compute the standard deviation σ of x e. Compute the following probabilities using tables and then calculator…) i. P(x ≤ 4) ii. P(x ...
... a. Compute P(x = 0) using binomial formula b. Compute P(x ≤ 2) = P(x = 0) + P(x = 1) + P(x = 2) using binomial formula (p. 191) c. Compute the expected value µ of x d. Compute the standard deviation σ of x e. Compute the following probabilities using tables and then calculator…) i. P(x ≤ 4) ii. P(x ...
Continuous Probability Distributions
... random variable is one for which we cannot devise some method for counting the possible outcomes. Note that this specifically requires having an infinite number of outcomes. Conditions Let f(x) be the probability density associated with sample point x. We can loosely interpret “density” as a mea ...
... random variable is one for which we cannot devise some method for counting the possible outcomes. Note that this specifically requires having an infinite number of outcomes. Conditions Let f(x) be the probability density associated with sample point x. We can loosely interpret “density” as a mea ...
P - WebAssign
... What is the probability that at least 2 of 4 unrelated persons share the same birthday? Solution: We use Pólya’s problem-solving guidelines for this example. Understand the Problem. We assume that the birthdays of the individuals are independent, and we ignore leap years. We also are not considering ...
... What is the probability that at least 2 of 4 unrelated persons share the same birthday? Solution: We use Pólya’s problem-solving guidelines for this example. Understand the Problem. We assume that the birthdays of the individuals are independent, and we ignore leap years. We also are not considering ...
Sample Midterm 1 (rev 14 Feb) with answers
... Only ii. is true. If A and B are independent, then A is just as likely regardless of whether B or ~B occurs. For example, the outcome of a second coin flip is just as likely to be 'heads' regardless of whether the first coin flip is 'heads' or 'tails'. Option i is the Addition Rule for Mutually Excl ...
... Only ii. is true. If A and B are independent, then A is just as likely regardless of whether B or ~B occurs. For example, the outcome of a second coin flip is just as likely to be 'heads' regardless of whether the first coin flip is 'heads' or 'tails'. Option i is the Addition Rule for Mutually Excl ...
3. Conditional Probability
... Sometimes it is easy to calculate the conditional probability, but may be hard or confusing to compute the probability of the intersection. In such a case, we can turn the conditional probability formula around by multiplying through by the denominator and obtaining: ...
... Sometimes it is easy to calculate the conditional probability, but may be hard or confusing to compute the probability of the intersection. In such a case, we can turn the conditional probability formula around by multiplying through by the denominator and obtaining: ...
STAT 380 Some Discrete Probability Distributions I. Binomial
... train. Historically, 7% of this manufacturer’s cars have required service under this warranty. Consider a new dealer. (a) Determine the probability that the twentieth car sold is the third to require service under this warranty. (b) Determine the expected number of cars sold until the third claim. ...
... train. Historically, 7% of this manufacturer’s cars have required service under this warranty. Consider a new dealer. (a) Determine the probability that the twentieth car sold is the third to require service under this warranty. (b) Determine the expected number of cars sold until the third claim. ...
Section 6.2 ~ Basics of Probability Objective: After this section you
... Section 6.2 ~ Basics of Probability Objective: After this section you will know how to find probabilities using theoretical and relative frequency methods and understand how to construct basic probability distributions. ...
... Section 6.2 ~ Basics of Probability Objective: After this section you will know how to find probabilities using theoretical and relative frequency methods and understand how to construct basic probability distributions. ...
