mc_fp1-ch - WordPress.com
... and lines of invariant points in a plane and how to find them. Be able to find the determinant of a 2x2 matrix. Know that the determinant gives the area scale factor of the transformation, and understand the significance of a zero determinant. Understand what is meant by an inverse matrix. ...
... and lines of invariant points in a plane and how to find them. Be able to find the determinant of a 2x2 matrix. Know that the determinant gives the area scale factor of the transformation, and understand the significance of a zero determinant. Understand what is meant by an inverse matrix. ...
Matrix Algebra Primer - Louisiana Tech University
... The Rank of a matrix is defined to be the number of linearly independent columns (or rows) of the matrix. Nonsingular (Full Rank) Matrix – Any matrix that has no linear dependencies among its columns (rows). For a square matrix A this implies that Ax = 0 iff x = ...
... The Rank of a matrix is defined to be the number of linearly independent columns (or rows) of the matrix. Nonsingular (Full Rank) Matrix – Any matrix that has no linear dependencies among its columns (rows). For a square matrix A this implies that Ax = 0 iff x = ...
diagnostic tools in ehx
... ► The logged messages can be exported to a file using the ‘Export’ option. The exported file from EHX is an XML file. This can be imported into Excel as a delimited file using the “ “ (speech quotes) as a separator Note: Status messages are logged automatically once the EHX s/w is started ...
... ► The logged messages can be exported to a file using the ‘Export’ option. The exported file from EHX is an XML file. This can be imported into Excel as a delimited file using the “ “ (speech quotes) as a separator Note: Status messages are logged automatically once the EHX s/w is started ...
Eigenvalues and Eigenvectors
... We cannot compute L(x1 , x2 ) until we specify which basis G we used. Let’s assume that G = {gg 1 , g 2 }. Then we know that L(gg 1 ) = 2gg 1 + 0gg 2 = 2gg 1 and L(gg 2 ) = 0gg 1 + 3gg 2 = 3gg 2 . Thus, L(gg k ) just multiplies g k by the corresponding element in the main diagonal of A. Figure 5.1 i ...
... We cannot compute L(x1 , x2 ) until we specify which basis G we used. Let’s assume that G = {gg 1 , g 2 }. Then we know that L(gg 1 ) = 2gg 1 + 0gg 2 = 2gg 1 and L(gg 2 ) = 0gg 1 + 3gg 2 = 3gg 2 . Thus, L(gg k ) just multiplies g k by the corresponding element in the main diagonal of A. Figure 5.1 i ...
