Slide 1
... what way the columns are dependent. That's what the null space is doing. – Now, what is the nullspace? – These are two vectors in the null space. They're independent. Are they a basis for the null space? What's the dimension of the null space? ...
... what way the columns are dependent. That's what the null space is doing. – Now, what is the nullspace? – These are two vectors in the null space. They're independent. Are they a basis for the null space? What's the dimension of the null space? ...
Problems 3.6 - Number Theory Web
... So AX = B is soluble for X if and only if B is a linear combination of the columns of A, that is B ∈ C(A). However by the first part of this question, B ∈ C(A) if and only if dim C([A|B]) = dim C(A), that is, rank [A|B] = rank A. 15. Let a1 , . . . , an be elements of F , not all zero. Let S denote ...
... So AX = B is soluble for X if and only if B is a linear combination of the columns of A, that is B ∈ C(A). However by the first part of this question, B ∈ C(A) if and only if dim C([A|B]) = dim C(A), that is, rank [A|B] = rank A. 15. Let a1 , . . . , an be elements of F , not all zero. Let S denote ...
PHASE PORTRAITS OF LINEAR SYSTEMS For our purposes phase
... 1.3.2. A single negative eigenvalue with one eigenvector. As for the case of a single positive eigenvalue with one eigenvector, we get one eigenline and curves that are halves of parabolic ones with outward arrows. They are tangent to the single eigenline at the origin and have the same slope as the ...
... 1.3.2. A single negative eigenvalue with one eigenvector. As for the case of a single positive eigenvalue with one eigenvector, we get one eigenline and curves that are halves of parabolic ones with outward arrows. They are tangent to the single eigenline at the origin and have the same slope as the ...
