Solving Basic Equations
... becomes 3x – 9 + 3 = 18 – 5x 2. Combine like terms on either side of the equation. -9 and 3 can be added to get -6. 3x – 6 = 18 - 5x 3. Use the addition or subtraction properties of equality to get the variables on one side of the = symbol and the constant terms on the other. 3x and 5x are like term ...
... becomes 3x – 9 + 3 = 18 – 5x 2. Combine like terms on either side of the equation. -9 and 3 can be added to get -6. 3x – 6 = 18 - 5x 3. Use the addition or subtraction properties of equality to get the variables on one side of the = symbol and the constant terms on the other. 3x and 5x are like term ...
Solving Basic Equations
... becomes 3x – 9 + 3 = 18 – 5x 2. Combine like terms on either side of the equation. -9 and 3 can be added to get -6. 3x – 6 = 18 - 5x 3. Use the addition or subtraction properties of equality to get the variables on one side of the = symbol and the constant terms on the other. 3x and 5x are like term ...
... becomes 3x – 9 + 3 = 18 – 5x 2. Combine like terms on either side of the equation. -9 and 3 can be added to get -6. 3x – 6 = 18 - 5x 3. Use the addition or subtraction properties of equality to get the variables on one side of the = symbol and the constant terms on the other. 3x and 5x are like term ...
Problem 9. For real number a, let LaC denote the largest integer less
... Problem 9. For real number a, let bac denote the largest integer less than or equal to a, and let {a}, the fractional part of a, be defined by {a} = a − bac. As examples, b3.6c = 3, {3.6} = 0.6, b−3.6c = −4, and {−3.6} = 0.4. Find all real number solutions (x, y, z) to the system x + byc + {z} bxc + ...
... Problem 9. For real number a, let bac denote the largest integer less than or equal to a, and let {a}, the fractional part of a, be defined by {a} = a − bac. As examples, b3.6c = 3, {3.6} = 0.6, b−3.6c = −4, and {−3.6} = 0.4. Find all real number solutions (x, y, z) to the system x + byc + {z} bxc + ...
HERE
... Mathematical Focus 2 All quadratic equations can be solved by completing the square or by employing the use of the quadratic formula. Solutions of quadratic equations are not always integers, nor are they necessarily real numbers. For these and other reasons, the quadratic formula, derived by comple ...
... Mathematical Focus 2 All quadratic equations can be solved by completing the square or by employing the use of the quadratic formula. Solutions of quadratic equations are not always integers, nor are they necessarily real numbers. For these and other reasons, the quadratic formula, derived by comple ...
Latest Revision 11/12/08
... Mathematical Focus 1 Factoring and using the Zero Product Property can be used to solve many quadratic equations. The quadratic equation x 2 = x + 6 can be solved by factoring and applying the ZeroProduct Property. The Zero-Product Property states: If a · b = 0, then a = 0, b = 0, or a = b = 0. ...
... Mathematical Focus 1 Factoring and using the Zero Product Property can be used to solve many quadratic equations. The quadratic equation x 2 = x + 6 can be solved by factoring and applying the ZeroProduct Property. The Zero-Product Property states: If a · b = 0, then a = 0, b = 0, or a = b = 0. ...
