Rotational and Projectile Motion
... When the vfinal - vinitial vector is moved to the circle, you can see the direction of the vector points toward the center of the circle. Regardless of where on the circle the vectors are chosen, the ∆v difference vector will always point toward the center of the circle. The conclusion is that the a ...
... When the vfinal - vinitial vector is moved to the circle, you can see the direction of the vector points toward the center of the circle. Regardless of where on the circle the vectors are chosen, the ∆v difference vector will always point toward the center of the circle. The conclusion is that the a ...
VOLCANOES AND PLATE TECTONICS
... a. Newton’s Third Law of Motion (ACTION/REACTION) i. “If one object EXERTS A FORCE on another object, then the second object exerts a FORCE OF EQUAL STRENGTH in the OPPOSITE DIRECTION on the first object.” 1. For every ACTION there is an equal but opposite REACTION. ...
... a. Newton’s Third Law of Motion (ACTION/REACTION) i. “If one object EXERTS A FORCE on another object, then the second object exerts a FORCE OF EQUAL STRENGTH in the OPPOSITE DIRECTION on the first object.” 1. For every ACTION there is an equal but opposite REACTION. ...
Conservation of Momentum AIM To determine the momentum of a
... From this information and the measured masses of the two trolleys, find the momentum after the "explosion. Compare the sum of these values with the total initial momentum and comment on this result in terms of the law of conservation of momentum (you should state this law). 1. Using Newton's second ...
... From this information and the measured masses of the two trolleys, find the momentum after the "explosion. Compare the sum of these values with the total initial momentum and comment on this result in terms of the law of conservation of momentum (you should state this law). 1. Using Newton's second ...
Practice Questions Chapters 3
... line, since their magnitudes are different, the sum will not be zero. If they point in different directions, then you can always decompose one vector into two components: one along the other vector and one perpendicular to the other vector. In this case, the perpendicular component can never be elim ...
... line, since their magnitudes are different, the sum will not be zero. If they point in different directions, then you can always decompose one vector into two components: one along the other vector and one perpendicular to the other vector. In this case, the perpendicular component can never be elim ...
Chapter 8- Rotational Motion
... The angular momentum of the merry-go-round and people combination will be conserved because there are no external torques on the combination. This situation is a totally inelastic collision, in which the final angular velocity is the same for both the merry-go-round and the people. Subscript 1 repre ...
... The angular momentum of the merry-go-round and people combination will be conserved because there are no external torques on the combination. This situation is a totally inelastic collision, in which the final angular velocity is the same for both the merry-go-round and the people. Subscript 1 repre ...