
Polynomials over finite fields
... Similarly, product of any two elements from U is also from U by distributivity. Let |U| = p, finite. Then U is isomorphic with Z/pZ with respect to. addition and multiplication. In this case p is a prime, otherwise F would have a zero divisor, so U= Fp. And Fp is also called the prime subfield of F. ...
... Similarly, product of any two elements from U is also from U by distributivity. Let |U| = p, finite. Then U is isomorphic with Z/pZ with respect to. addition and multiplication. In this case p is a prime, otherwise F would have a zero divisor, so U= Fp. And Fp is also called the prime subfield of F. ...
Finite Fields
... We now need to link the additive structure of a finite field coming from the vector space interpretation and the multiplicative structure coming from the representation of all nonzero elements by the powers of a primitive element. Theorem 1.14. Let p be a prime and P be an irreducible polynomial of ...
... We now need to link the additive structure of a finite field coming from the vector space interpretation and the multiplicative structure coming from the representation of all nonzero elements by the powers of a primitive element. Theorem 1.14. Let p be a prime and P be an irreducible polynomial of ...