
Gaining Momentum
... •An “elastic” collision is one in which the objects “bounce”, and energy is conserved. •An “inelastic” collision is one in which the objects stick together, and energy is lost to heat. ...
... •An “elastic” collision is one in which the objects “bounce”, and energy is conserved. •An “inelastic” collision is one in which the objects stick together, and energy is lost to heat. ...
CHAPTER 5 HW Part 1– WORK, ENERGY AND POWER Work p
... 18. How much work do the breaks of a 920 kg car do in slowing it down from 25 km/hr to 0 km/hr? 19. An outfielder throws a 250 g baseball with an initial speed of 18 m/s. An infielder at the same level catches the ball when the speed is reduced to 12 m/s. How much work was done on the ball by air re ...
... 18. How much work do the breaks of a 920 kg car do in slowing it down from 25 km/hr to 0 km/hr? 19. An outfielder throws a 250 g baseball with an initial speed of 18 m/s. An infielder at the same level catches the ball when the speed is reduced to 12 m/s. How much work was done on the ball by air re ...
How Rockets
... products are ejected by the engine, the total mass of the vehicle lessens. As it does its inertia, or resistance to change in motion, becomes less. As a result, upward acceleration of the rocket increases. In practical terms, Newton’s second law can be rewritten as this: ...
... products are ejected by the engine, the total mass of the vehicle lessens. As it does its inertia, or resistance to change in motion, becomes less. As a result, upward acceleration of the rocket increases. In practical terms, Newton’s second law can be rewritten as this: ...
mDv
... In an inelastic collision (things stick together), m1v1 + m2v2 = (m1 + m2)vf If I throw a 2 kg clay ball forward at 10 m/s, and my friend throws a 1 kg clay ball forward at 20 m/s, what will their speed be when they hit and stick together? For work to occur, only the force that is parallel to the m ...
... In an inelastic collision (things stick together), m1v1 + m2v2 = (m1 + m2)vf If I throw a 2 kg clay ball forward at 10 m/s, and my friend throws a 1 kg clay ball forward at 20 m/s, what will their speed be when they hit and stick together? For work to occur, only the force that is parallel to the m ...
Unit 8 Momentum 6 lessons - science-b
... Newton’s second law of motion, F = ma, can be rewritten by using the definition of acceleration as the change in velocity divided by the time needed to make that change. It can be represented by the following equation: v F = ma = m t ...
... Newton’s second law of motion, F = ma, can be rewritten by using the definition of acceleration as the change in velocity divided by the time needed to make that change. It can be represented by the following equation: v F = ma = m t ...
y 1
... but… – If I put a ball with no velocity there would it stay? – What if it had a little bit of velocity? ...
... but… – If I put a ball with no velocity there would it stay? – What if it had a little bit of velocity? ...