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Physics 201: Lecture 1
Physics 201: Lecture 1

... at its CM. The wire defines the rotation axis, and the moment of inertia I about this axis is known. The wire acts like a “rotational spring.” When the object is rotated, the wire is twisted. This produces a torque that opposes the rotation. In analogy with a spring, the torque produced is proport ...
PS03H - willisworldbio
PS03H - willisworldbio

... • _____ and ____ are not the same. • Weight is a _____ and mass is a measure of the amount of ______ an object contains. • Weight and mass are related. Weight increases as mass increases. • The weight of an object usually is the gravitational force between the object and ______. • The weight of an ...
Document
Document

... Air bags in cars. Catching an egg. Boxing, Figure 6.6 Soft collisions, Figure 6.3. ...
Stacey Carpenter
Stacey Carpenter

... Do a mini-activity. Pair the students. Have one student hold up a hand and the other push on it with their hand without touching. Impossible, of course. You can't have a force without a counter-force. Another mini-activity. Give each pair of students a spring scale. Instruct one student to hold one ...
Newton`s Laws Multiple Choice: 1. The resistance of an object to
Newton`s Laws Multiple Choice: 1. The resistance of an object to

Physics 207: Lecture 2 Notes
Physics 207: Lecture 2 Notes

... Find the tension in each segment of the rope and the magnitude of F. T4  Assume the pulleys are massless and frictionless. T1  Assume the rope is massless. T3 T2 The action of a massless frictionless pulley is to change the direction of a T5 F tension. M Here F = T1 = T2 = T3 Equilibrium means S F ...
as a PDF
as a PDF

Ch 6 Forces
Ch 6 Forces

Student Text, pp. 88-96
Student Text, pp. 88-96

Dear David Weber
Dear David Weber

... Designations of values are given in the caption signature to fig. 2. For angles  and iEa in work [1] are also given formulas, which depend on the ecliptic angles of orbits: Ωa, iеа etc. As a result of approximation of observation data S. Newcomb [2] has presented ecliptic angles as polynomials of ...
The net force
The net force

... When an object moves through air or any other fluid, the fluid exerts drag force on the moving object. The force is called. Unlike the friction between surfaces, however, this force depends upon the speed of the object, becoming larger as the speed increases. It also depends upon the size and the sh ...
Newton`s Second Law
Newton`s Second Law

... A force is a push or pull. An object at rest needs a force to get it moving; a moving object needs a force to change its velocity. ...
Chapter 6
Chapter 6

... respectively, of all fatal and non-fatal occupational injuries in the USA. Redfern et al (2001). Biomechanics of ...
05_InstructorGuideWin
05_InstructorGuideWin

... its importance in biology, this text also discusses drag in liquids, using Stokes’s law as a prototype for the drag force in liquids. The “big picture” you want students to see in Chapter 5 is: ...
Chapter 7: Circular Motion and Gravitation
Chapter 7: Circular Motion and Gravitation

... to the net force on an object in uniform circular motion. Any type of force or combination of forces can provide this net force. – Example: Friction between a race car’s tires and a circular track is a centripetal force that keeps the car in a circular path. – Example: Gravitational force is a centr ...
Forces Packet
Forces Packet

... everything on Earth is gravity. Gravity is a very specific acceleration that pulls objects toward each other. It is represented by the variable “g” and because it is acceleration it is measured in units of m/s2. Earth’s gravity is 9.8 m/s2. The gravity of Earth pulls all objects on the surface towar ...
Document
Document

Chapter 7
Chapter 7

... If car moves slower than "design" speed, which vector represents frictional force acting on car from contact with road (neglect air resistance) ...
quantities and units for centrifugation in the
quantities and units for centrifugation in the

’ m = 22.0 kg       µ
’ m = 22.0 kg µ

... Thus, in uniform circular motion there must be a net force to produce the centripetal acceleration. The centripetal force is the name given to the net force required to keep an object moving on a circular path. The direction of the centripetal force always points toward the center of the circle and ...
Lecture13-10
Lecture13-10

... Jeff of the Jungle swings on a vine that is 7.20 m long. At the bottom of the swing, just before hitting the tree, Jeff’s linear speed is 8.50 m/s. (a) Find Jeff’s angular speed at this time. (b) What centripetal acceleration does Jeff experience at the bottom of his swing? (c) What exerts the forc ...
Chapter 4 and Chapter 5
Chapter 4 and Chapter 5

... Free Fall – motion going down due to gravity Weight –downward force due to gravity, Newtons weight = mass,kg X gravitational acceleration(g) Air Friction , Newton– force that opposes the free fall and slows down any falling object ; Parachute provides air friction. The larger the area of the parachu ...
Review the study notes and homework for the hour tests and
Review the study notes and homework for the hour tests and

... (5.5) and (5.6) as formulas for the speed and period, respectively of an object in a circular orbit. Chapter 6 Work and Energy Summary is on p.186. Know how to find the work done by a constant force and the MKS units of work (J). Know that kinetic energy (Equation 6.2) is the energy of motion and ho ...
Review the study notes and homework for the hour tests and
Review the study notes and homework for the hour tests and

... (5.5) and (5.6) as formulas for the speed and period, respectively of an object in a circular orbit. Chapter 6 Work and Energy Summary is on p.186. Know how to find the work done by a constant force and the MKS units of work (J). Know that kinetic energy (Equation 6.2) is the energy of motion and ho ...
Abstract
Abstract

... power braking test. Breath can be described by the mechanics of gases. Every person that studies Taekwon-do will at some point of their carrier come across the problem of braking hard objects and will wonder where to gain the strength needed to successfully complete such a test. As we all know, acco ...
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Rigid body dynamics

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