02.Ch 9 notes
... Impulse is equal to Momentum FΔt = mΔv or F=mΔv/Δt • The greater the time to stop the less the force • The shorter the time to stop the greater the force • This the principle behind air bags ...
... Impulse is equal to Momentum FΔt = mΔv or F=mΔv/Δt • The greater the time to stop the less the force • The shorter the time to stop the greater the force • This the principle behind air bags ...
Conservation of impulse and momentum
... is often applied when particles collide or interact. When particles impact, only impulsive forces cause a change of linear momentum. The sledgehammer applies an impulsive force to the stake. The weight of the stake is considered negligible, or non-impulsive, as compared to the force of the sledgeham ...
... is often applied when particles collide or interact. When particles impact, only impulsive forces cause a change of linear momentum. The sledgehammer applies an impulsive force to the stake. The weight of the stake is considered negligible, or non-impulsive, as compared to the force of the sledgeham ...
chapter02posta
... So far, we have described a moving object by giving its position for each time during its motion. From the position data we can get the velocity and the acceleration at each instant. For a full description, we also need to know the MASS of the object. We get this by using a balance to compare the ob ...
... So far, we have described a moving object by giving its position for each time during its motion. From the position data we can get the velocity and the acceleration at each instant. For a full description, we also need to know the MASS of the object. We get this by using a balance to compare the ob ...
Help Section - AdvancedPlacementPhysicsC
... 1. Problems such as the one at hand require analyzing the statics of rigid bodies. The situation described on the first slide is static as long as the man is not more than one-third of the way up the ladder, because there is no motion. Therefore, the conditions for static equilibrium apply to the s ...
... 1. Problems such as the one at hand require analyzing the statics of rigid bodies. The situation described on the first slide is static as long as the man is not more than one-third of the way up the ladder, because there is no motion. Therefore, the conditions for static equilibrium apply to the s ...
Newton`s Laws
... Lance Berkman swings his bat at a fastball. The impact of the bat on the ball gives it an acceleration of 9000 m/s2. What was the force exerted by the bat at impact if the ball has a mass of 0.25 kg ...
... Lance Berkman swings his bat at a fastball. The impact of the bat on the ball gives it an acceleration of 9000 m/s2. What was the force exerted by the bat at impact if the ball has a mass of 0.25 kg ...
File
... • When an object is thrown up in the air, it has a positive velocity and a negative acceleration. • At the top of its path, the object’s velocity has decreased until it is zero. • When the object begins moving down, it has a negative velocity and its acceleration is still ...
... • When an object is thrown up in the air, it has a positive velocity and a negative acceleration. • At the top of its path, the object’s velocity has decreased until it is zero. • When the object begins moving down, it has a negative velocity and its acceleration is still ...
Slide 1
... Fm rm FM rM must equal the work expended by M : Combining these we get Fm m rm rM mr 2 Mr 2 m M FM M rM rm So the moments on inertia must the same. r And not - mrm MrM F M ...
... Fm rm FM rM must equal the work expended by M : Combining these we get Fm m rm rM mr 2 Mr 2 m M FM M rM rm So the moments on inertia must the same. r And not - mrm MrM F M ...
Honors Physics – Midterm Review 2010
... 5. A baseball is thrown straight upward with a speed of 30.0 m/s. (a) How long will it rise? (b) How high will it rise? (c) How long after it leaves the hand will it return to the starting point? 6. A boat is pointed straight across a river (east) and is moving at a speed of 0.55 m/s relative to the ...
... 5. A baseball is thrown straight upward with a speed of 30.0 m/s. (a) How long will it rise? (b) How high will it rise? (c) How long after it leaves the hand will it return to the starting point? 6. A boat is pointed straight across a river (east) and is moving at a speed of 0.55 m/s relative to the ...
Newton s__Laws_of_Motion - McKinney ISD Staff Sites
... and objects at rest tend to stay at rest unless acted upon by an unbalanced force. Newton’s Second Law: Force equals mass times acceleration (F = ma). Newton’s Third Law: For every action there is an equal and ...
... and objects at rest tend to stay at rest unless acted upon by an unbalanced force. Newton’s Second Law: Force equals mass times acceleration (F = ma). Newton’s Third Law: For every action there is an equal and ...
香港考試局
... Feeling of One’s Weight 19. A lift of mass M carries a man of mass m. (5)moving downwards and decelerating at g/10. When the lift is being hauled upward by a A. (1) only rope, the lift rises with an acceleration a. The tension of the rope is A. m (g - a). B. (m + M) (g + a). C. m (g + a) - Ma. D. m ...
... Feeling of One’s Weight 19. A lift of mass M carries a man of mass m. (5)moving downwards and decelerating at g/10. When the lift is being hauled upward by a A. (1) only rope, the lift rises with an acceleration a. The tension of the rope is A. m (g - a). B. (m + M) (g + a). C. m (g + a) - Ma. D. m ...
Chapter 6 Notes Circular Motion and Gravity
... A curved path requires an inward pull. centripetal force: the force needed to make an object follow a curved path Centripetal force is the force perpendicular to the velocity of an object moving along a curved path. The centripetal force is the force directed toward the center of the curvature of th ...
... A curved path requires an inward pull. centripetal force: the force needed to make an object follow a curved path Centripetal force is the force perpendicular to the velocity of an object moving along a curved path. The centripetal force is the force directed toward the center of the curvature of th ...
lab 3: newton`s second law of motion
... undergoing acceleration. Other experimental and mathematical work, the details of which need not concern us, has established the relationship between acceleration, a, and velocity, V, in a circular system with a circular radius of r: a = V2 / r Newton’s Laws of Motion assume that objects are free to ...
... undergoing acceleration. Other experimental and mathematical work, the details of which need not concern us, has established the relationship between acceleration, a, and velocity, V, in a circular system with a circular radius of r: a = V2 / r Newton’s Laws of Motion assume that objects are free to ...
Circular motion
... At any point in the motion of the object as it travels in the circle, the instantaneous velocity vector is tangent to the circle. And remember that at any point on a circle, the tangent line is perpendicular to the radius drawn to that point. So, in our diagram, the velocity vectors or perpendicular ...
... At any point in the motion of the object as it travels in the circle, the instantaneous velocity vector is tangent to the circle. And remember that at any point on a circle, the tangent line is perpendicular to the radius drawn to that point. So, in our diagram, the velocity vectors or perpendicular ...
Definition of force Force is defined as anything that changes the
... Based on the Newton’s Second Law of motion, a F a 1 m ...
... Based on the Newton’s Second Law of motion, a F a 1 m ...
AAAAA
... If you do both, compare the video analysis to the manually timed graph. b) Predict what the graphs will look like if the hanging mass is increased. If the hanging mass is increased, will the new velocity versus time graph look the same or different from the graph in Part I? Draw your prediction. ...
... If you do both, compare the video analysis to the manually timed graph. b) Predict what the graphs will look like if the hanging mass is increased. If the hanging mass is increased, will the new velocity versus time graph look the same or different from the graph in Part I? Draw your prediction. ...
File
... MATCHING: Know the definitions of the following terms 1. ___ Inertia a. rate of change of the velocity of an object 2. ___ Force b. the total distance an object travels divided by the total time of travel 3. ___ Net force c. physical movement or a change in position relative to a starting point st 4 ...
... MATCHING: Know the definitions of the following terms 1. ___ Inertia a. rate of change of the velocity of an object 2. ___ Force b. the total distance an object travels divided by the total time of travel 3. ___ Net force c. physical movement or a change in position relative to a starting point st 4 ...