Physics 207: Lecture 2 Notes
... Identify forces and draw a Free Body Diagram Begin to solve 1D and 2D problems with forces in equilibrium and non-equilibrium (i.e., acceleration) using Newton’s 1st and 2nd laws. ...
... Identify forces and draw a Free Body Diagram Begin to solve 1D and 2D problems with forces in equilibrium and non-equilibrium (i.e., acceleration) using Newton’s 1st and 2nd laws. ...
Slide 1 - SFSU Physics & Astronomy
... Time of collision is short enough that external forces may be ignored Inelastic collision: momentum is conserved but kinetic energy is not Completely inelastic collision: objects stick ...
... Time of collision is short enough that external forces may be ignored Inelastic collision: momentum is conserved but kinetic energy is not Completely inelastic collision: objects stick ...
Student notes Chap 1 & 2
... ________ forces in opposite directions – net force occurs in the direction of the _______ force net force – will be the __________ between the two forces because they are in opposite ________ ...
... ________ forces in opposite directions – net force occurs in the direction of the _______ force net force – will be the __________ between the two forces because they are in opposite ________ ...
PowerPoints
... What happens if you are standing on a skateboard or a slippery floor and push against a wall? You slide in the opposite direction (away from the wall), because you pushed on the wall but the wall pushed back on you with equal and opposite force. Why does it hurt so much when you stub your toe? When ...
... What happens if you are standing on a skateboard or a slippery floor and push against a wall? You slide in the opposite direction (away from the wall), because you pushed on the wall but the wall pushed back on you with equal and opposite force. Why does it hurt so much when you stub your toe? When ...
Solutions to Mechanics Problems
... then assume that the student knew that there was no force acting on the rocket from P to Q. However after R, the rocket reverts to its original motion rather than continuing in the direction it was travelling when the rocker turned off. This suggests that the student thought that there WAS a horizon ...
... then assume that the student knew that there was no force acting on the rocket from P to Q. However after R, the rocket reverts to its original motion rather than continuing in the direction it was travelling when the rocker turned off. This suggests that the student thought that there WAS a horizon ...
Core Idea PS2 Motion and Stability: Forces and Interactions How
... interactions force change in motion individual force (strength and direction) static vector sum Newton’s third law macroscale Newton’s second law of motion F = ma (total force = mass times acceleration) macroscopic object mass speed speed of light molecular scale atomic scale subatomic scale ...
... interactions force change in motion individual force (strength and direction) static vector sum Newton’s third law macroscale Newton’s second law of motion F = ma (total force = mass times acceleration) macroscopic object mass speed speed of light molecular scale atomic scale subatomic scale ...
Newton`s Toy Box - Delta Education
... power rate at which work is done; measured in watts (14) pulley simple machine made up of a wheel with a groove in the rim for a rope or cable (15, 16, 21) reference point stationary object used to determine the motion of another nearby object (2, 23) satellite object that travels around, or orbits, ...
... power rate at which work is done; measured in watts (14) pulley simple machine made up of a wheel with a groove in the rim for a rope or cable (15, 16, 21) reference point stationary object used to determine the motion of another nearby object (2, 23) satellite object that travels around, or orbits, ...
Non-Linear Motion
... imagine an x, y coordinate system with its origin at the center of the circle. The radius extends from this origin to the position of the object. The velocity vector (green arrow) shows the speed and direction of the orbiting object at all points along its path. Note that the velocity vector is tang ...
... imagine an x, y coordinate system with its origin at the center of the circle. The radius extends from this origin to the position of the object. The velocity vector (green arrow) shows the speed and direction of the orbiting object at all points along its path. Note that the velocity vector is tang ...
Stress, Strain, Virtual Power and Conservation Principles
... Virtual motions are useful concepts in mechanics of material. They are used both in the analytical formulation of problems and also constitute the foundation of the finite element methodology. Virtual motions are imaginary movements of material points and the method of virtual power consists of dete ...
... Virtual motions are useful concepts in mechanics of material. They are used both in the analytical formulation of problems and also constitute the foundation of the finite element methodology. Virtual motions are imaginary movements of material points and the method of virtual power consists of dete ...
FE REV Q
... Goliath's skull will fracture if an energy of 20 J is imparted to it in a short period and over a small area. David has a stone of mass 0.10 kg and a sling of length 1.0 m. He whirls the stone at the end of the sling and then releases the stone. The stone hits Goliath and comes to rest while in cont ...
... Goliath's skull will fracture if an energy of 20 J is imparted to it in a short period and over a small area. David has a stone of mass 0.10 kg and a sling of length 1.0 m. He whirls the stone at the end of the sling and then releases the stone. The stone hits Goliath and comes to rest while in cont ...
2 Kinetic energy
... The result of the 16 J of work done on the 2 kg object is that it has acquired a speed of 4 m S-' (Figure 8). Now if I try to stop the object, I shall have to apply a force against its motion, i.e. do negative work on it. To look at this another way, the object will do positive work on me, or anythi ...
... The result of the 16 J of work done on the 2 kg object is that it has acquired a speed of 4 m S-' (Figure 8). Now if I try to stop the object, I shall have to apply a force against its motion, i.e. do negative work on it. To look at this another way, the object will do positive work on me, or anythi ...
Rotary Motion
... the distance, r, of the object(s) from the axis of rotation. To test this hypothesis, you will need the data from several groups that positioned the weights at different distances along the rod. If that is not feasible, you will have to repeat Part 3 at least five more times, changing the distance t ...
... the distance, r, of the object(s) from the axis of rotation. To test this hypothesis, you will need the data from several groups that positioned the weights at different distances along the rod. If that is not feasible, you will have to repeat Part 3 at least five more times, changing the distance t ...
Newton`s Laws of Motion Units of Force
... Unit 4: Newton’s Laws of Motion Units of Force: The SI unit for force is the Newton [kg m/s²]. The Imperial unit for force is the pound. Weight and Mass: The weight of an object is equal to the mass of the object times the force of gravity. W = mg, where g = 9.8 m/s² The mass is a measure of how muc ...
... Unit 4: Newton’s Laws of Motion Units of Force: The SI unit for force is the Newton [kg m/s²]. The Imperial unit for force is the pound. Weight and Mass: The weight of an object is equal to the mass of the object times the force of gravity. W = mg, where g = 9.8 m/s² The mass is a measure of how muc ...
10SuExamF
... plus attending class yesterday, should enable you to solve the following: The figure shows a rigid, solid SPHERE of radius R = 1.8 m. The sphere’s mass is M = 4.2 kg. It’s moment of inertia is I = (2/5)M(R)2. (Note: So, it is ISN’T a uniform disk, & the disk moment of inertia, Idisk = (½)MR2 should ...
... plus attending class yesterday, should enable you to solve the following: The figure shows a rigid, solid SPHERE of radius R = 1.8 m. The sphere’s mass is M = 4.2 kg. It’s moment of inertia is I = (2/5)M(R)2. (Note: So, it is ISN’T a uniform disk, & the disk moment of inertia, Idisk = (½)MR2 should ...
Summer Holidays Home Work
... ii) Can a body move with constant in an acierated motion? If yes, Give reason. 3. Give answer in detail: i) What do you understand bya) Displacement time graph. b) Velocity time graph. ii) Draw a displacement time graph for a girl going to school with uniform velocity. How can we calculate uniform v ...
... ii) Can a body move with constant in an acierated motion? If yes, Give reason. 3. Give answer in detail: i) What do you understand bya) Displacement time graph. b) Velocity time graph. ii) Draw a displacement time graph for a girl going to school with uniform velocity. How can we calculate uniform v ...