
12. MATHEMATICAL PHYSICS
... true"!). In relativity we must change Newton's II law F = ma since m is not constant. We can use the momentum instead : F = ma = m(v-u) = mv - mu and then impulse = Ft = change in momentum = p = mv - mu which for an infinitely short time dt becomes: Fdt = dp and dividing with dt then: F = dp/dt (f ...
... true"!). In relativity we must change Newton's II law F = ma since m is not constant. We can use the momentum instead : F = ma = m(v-u) = mv - mu and then impulse = Ft = change in momentum = p = mv - mu which for an infinitely short time dt becomes: Fdt = dp and dividing with dt then: F = dp/dt (f ...
Fall 2008 - BYU Physics and Astronomy
... Problem 6. Two students play with an extra-long Slinky. The student on the left end sends waves to the other student by shaking her end back and forth. After the waves die down, both students take a step backwards and try it again. How will the speed of the waves now compare to the previous waves? ...
... Problem 6. Two students play with an extra-long Slinky. The student on the left end sends waves to the other student by shaking her end back and forth. After the waves die down, both students take a step backwards and try it again. How will the speed of the waves now compare to the previous waves? ...
Chapter 7 Impulse and Momentum
... Chapter 7 is about the COLLISION of two masses. Both masses are needed to understand their interaction. Newton's 3rd Law plays a very important part. Collisions involve two new concepts: Impulse and Momentum. Impulse concept leads to the Momentum definition. Also applied to two (or more) masses blow ...
... Chapter 7 is about the COLLISION of two masses. Both masses are needed to understand their interaction. Newton's 3rd Law plays a very important part. Collisions involve two new concepts: Impulse and Momentum. Impulse concept leads to the Momentum definition. Also applied to two (or more) masses blow ...
sample lab report
... the pulley, keeps moving along the track at a constant speed. (This balances out the friction force.) Then hook the string to the cart. 3. Activate the “smart pulley” program in Logger Pro. Adjust the photogate so the spokes in the pulley cut through the photogate beam. Part 1: Varying total mass wi ...
... the pulley, keeps moving along the track at a constant speed. (This balances out the friction force.) Then hook the string to the cart. 3. Activate the “smart pulley” program in Logger Pro. Adjust the photogate so the spokes in the pulley cut through the photogate beam. Part 1: Varying total mass wi ...
Stacey Carpenter - University of Hawaii
... The constant of proportionality was later determined experimentally. It is called G. G = 6.710-11 m3/(kgs2) You can use G to calculate the gravitational force between two objects if you know their masses and the distance between their centers of mass. F = Gm1m2/d2 The units for G work with m1m2 ...
... The constant of proportionality was later determined experimentally. It is called G. G = 6.710-11 m3/(kgs2) You can use G to calculate the gravitational force between two objects if you know their masses and the distance between their centers of mass. F = Gm1m2/d2 The units for G work with m1m2 ...
1 - hrsbstaff.ednet.ns.ca
... 52. In an effort to create a cannonball-style splash, eight-year old Matthew runs off the edge of the board of the high dive at 4.6 m/s and falls 2.3 m to the water below. a. Determine the time for Matthew to fall the 2.3 m to the water. (0.685s) b. What horizontal distance from the edge of the boar ...
... 52. In an effort to create a cannonball-style splash, eight-year old Matthew runs off the edge of the board of the high dive at 4.6 m/s and falls 2.3 m to the water below. a. Determine the time for Matthew to fall the 2.3 m to the water. (0.685s) b. What horizontal distance from the edge of the boar ...
40 N m
... A bowling ball of mass 7.25kg and radius 10.8cm rolls without slipping down a lane at 3.1m/s. Calculate the total Kinetic Energy of the ball. The lane is 18m long. Hope many rotations does the ball make on the way down the lane? ...
... A bowling ball of mass 7.25kg and radius 10.8cm rolls without slipping down a lane at 3.1m/s. Calculate the total Kinetic Energy of the ball. The lane is 18m long. Hope many rotations does the ball make on the way down the lane? ...
General Physics II
... Magnetic Force on a Moving Charge • A charged particle moving within a magnetic field will in general experience a force that we call a “magnetic force.” This magnetic force has the following properties: • If the charged particle is at rest, there is no force. • If the charged particle moves parall ...
... Magnetic Force on a Moving Charge • A charged particle moving within a magnetic field will in general experience a force that we call a “magnetic force.” This magnetic force has the following properties: • If the charged particle is at rest, there is no force. • If the charged particle moves parall ...
Linear Momentum
... If the momentum before an interaction is zero, then (assuming no interfering force, such as friction or gravitational force) the momentum afterward is equal to zero. In this case, the momentum before the interaction with the fire extinguisher is zero. After the extinguisher is fired, the momentum o ...
... If the momentum before an interaction is zero, then (assuming no interfering force, such as friction or gravitational force) the momentum afterward is equal to zero. In this case, the momentum before the interaction with the fire extinguisher is zero. After the extinguisher is fired, the momentum o ...
Laws of Motion Conservation Laws Gravity
... In the absence of an applied force, an object at rest remains at rest. An object in motion remains in motion with a constant velocity. C3-04, C3-02, C3-12 © 2007 Pearson Education Inc., publishing as Pearson Addison-Wesley ...
... In the absence of an applied force, an object at rest remains at rest. An object in motion remains in motion with a constant velocity. C3-04, C3-02, C3-12 © 2007 Pearson Education Inc., publishing as Pearson Addison-Wesley ...
doc - atmo.arizona.edu
... Nonspherical “drops” like ice crystals are of course more complicated and won’t be treated in any detail here. Ice crystals like snow flakes can fall much more slowly that predicts above because they lie flat such that the stagnation pressure is much higher for a given mass particle because they hav ...
... Nonspherical “drops” like ice crystals are of course more complicated and won’t be treated in any detail here. Ice crystals like snow flakes can fall much more slowly that predicts above because they lie flat such that the stagnation pressure is much higher for a given mass particle because they hav ...