VU2 Movement 2008
... Describe non-uniform and uniform motion along a straight line graphically; Analyse motion along a straight line graphically, numerically and algebraically; Describe how changes in movement are caused by the actions of forces; Model forces as external actions through the centre of mass point of each ...
... Describe non-uniform and uniform motion along a straight line graphically; Analyse motion along a straight line graphically, numerically and algebraically; Describe how changes in movement are caused by the actions of forces; Model forces as external actions through the centre of mass point of each ...
f F = mg X
... ❑ Equilibrium – an object which has zero acceleration, can be at rest or moving with constant velocity ...
... ❑ Equilibrium – an object which has zero acceleration, can be at rest or moving with constant velocity ...
Gaining Momentum
... •An “elastic” collision is one in which the objects “bounce”, and energy is conserved. •An “inelastic” collision is one in which the objects stick together, and energy is lost to heat. ...
... •An “elastic” collision is one in which the objects “bounce”, and energy is conserved. •An “inelastic” collision is one in which the objects stick together, and energy is lost to heat. ...
- Possibility
... Lifting through wave zone – simplified methods The objective of the Simplified Method is to give simple conservative estimates of the forces acting on the object in order to verify sufficient crane and rigging capacity. ...
... Lifting through wave zone – simplified methods The objective of the Simplified Method is to give simple conservative estimates of the forces acting on the object in order to verify sufficient crane and rigging capacity. ...
Concept Questions
... I cm about the center of mass starts from rest and moves down an incline tilted at an angle from the horizontal. The center of mass of the cylinder has dropped a vertical distance h when it reaches the bottom of the incline. Let g denote the gravitational constant. The coefficient of static fricti ...
... I cm about the center of mass starts from rest and moves down an incline tilted at an angle from the horizontal. The center of mass of the cylinder has dropped a vertical distance h when it reaches the bottom of the incline. Let g denote the gravitational constant. The coefficient of static fricti ...
Ch 8.1 and 8.2 chap 8.1
... Which truck will experience the greatest impulse? Which truck will experience the greatest force? Which truck will experience the greatest acceleration? Which truck will experience the greatest change in velocity? Which truck would you rather be in during the collision? • Discussion of the questions ...
... Which truck will experience the greatest impulse? Which truck will experience the greatest force? Which truck will experience the greatest acceleration? Which truck will experience the greatest change in velocity? Which truck would you rather be in during the collision? • Discussion of the questions ...
Angular_Momentum
... • F·r is the torque exerted on a particle at radius ‘ r’ We may take the sum of both sides over i particles to get ...
... • F·r is the torque exerted on a particle at radius ‘ r’ We may take the sum of both sides over i particles to get ...
Rotational Motion
... in magnitude to Fhc ,the force on the hanging mass by the cylinder sandwich (via the string) by Newton’s third law. Fhc can be computed by using Newton’s second law on the falling mass. ...
... in magnitude to Fhc ,the force on the hanging mass by the cylinder sandwich (via the string) by Newton’s third law. Fhc can be computed by using Newton’s second law on the falling mass. ...
1. Unless acted on by an external net force, an object
... 19. The 2.0 kg head of an axe strikes a tree horizontally at 40 m/s. The blade penetrates 0.040 m into the tree. What is the average force exerted by the blade on this tree? A. 2. 0 × 101 N B. 2. 0 × 103 N C. 2. 0 × 10 4 N D. 4. 0 × 10 4 N ...
... 19. The 2.0 kg head of an axe strikes a tree horizontally at 40 m/s. The blade penetrates 0.040 m into the tree. What is the average force exerted by the blade on this tree? A. 2. 0 × 101 N B. 2. 0 × 103 N C. 2. 0 × 10 4 N D. 4. 0 × 10 4 N ...
Focus/ Course Title
... Ballistics Article Reaction Paper acceleration due gravity, trajectory, projectile motion Habits of Mind Quality work Read critically Collaborate and cooperate Communicate effectively in writing ...
... Ballistics Article Reaction Paper acceleration due gravity, trajectory, projectile motion Habits of Mind Quality work Read critically Collaborate and cooperate Communicate effectively in writing ...
