Physics 106P: Lecture 1 Notes
... The impulse-momentum theory says that the impulse that acts on an object is given by the change in the momentum of the object, and this change is proportional to the change in velocity. The ball that sticks has a velocity of downward to zero, but the velocity of the ball that bounces goes downward t ...
... The impulse-momentum theory says that the impulse that acts on an object is given by the change in the momentum of the object, and this change is proportional to the change in velocity. The ball that sticks has a velocity of downward to zero, but the velocity of the ball that bounces goes downward t ...
Unit 1 Chapter 1 First encounter with physics I) Write the scientific
... 11. Are the laws used to describe any universal phenomena . ...
... 11. Are the laws used to describe any universal phenomena . ...
of Newton`s Second Law of Motion Video Script
... And we already know that net force equals mass times acceleration. So put the two together and you get this equation to use when two forces act on an object. Don’t forget that the direction of the acceleration will be the same as the direction of the larger force. Maybe we need to work one more prob ...
... And we already know that net force equals mass times acceleration. So put the two together and you get this equation to use when two forces act on an object. Don’t forget that the direction of the acceleration will be the same as the direction of the larger force. Maybe we need to work one more prob ...
EOC_chapter8 - AppServ Open Project 2.4.9
... Mi = 360 kg, including 330 kg of fuel and oxidizer. In interstellar space, it starts from rest at the position x = 0, turns on its engine at time t = 0, and puts out exhaust with relative speed ve = 1 500 m/s at the constant rate k = 2.50 kg/s. The fuel will last for an actual burn time of 330 kg/(2 ...
... Mi = 360 kg, including 330 kg of fuel and oxidizer. In interstellar space, it starts from rest at the position x = 0, turns on its engine at time t = 0, and puts out exhaust with relative speed ve = 1 500 m/s at the constant rate k = 2.50 kg/s. The fuel will last for an actual burn time of 330 kg/(2 ...
Chapter 8 Accelerated Circular Motion continued
... Every particle in the universe exerts an attractive force on every other particle. A particle is a piece of matter, small enough in size to be regarded as a mathematical point. The force that each exerts on the other is directed along the line joining the particles. ...
... Every particle in the universe exerts an attractive force on every other particle. A particle is a piece of matter, small enough in size to be regarded as a mathematical point. The force that each exerts on the other is directed along the line joining the particles. ...
mi05sol
... Consider a block sitting on a surface. The maximum magnitude of fs is fsmax = sN, where N is the normal force. The direction of fs is always parallel to the surface and opposite to the component of applied force parallel to the surface. Once the block starts to move the frictional force decreases t ...
... Consider a block sitting on a surface. The maximum magnitude of fs is fsmax = sN, where N is the normal force. The direction of fs is always parallel to the surface and opposite to the component of applied force parallel to the surface. Once the block starts to move the frictional force decreases t ...
PHYS 342: Modern Physics
... • The velocity of a particle moving with SHM is given by (from conservation of mechanical energy ½ kA2 = ½ mv2 + ½ kx2): k 2 2 v ...
... • The velocity of a particle moving with SHM is given by (from conservation of mechanical energy ½ kA2 = ½ mv2 + ½ kx2): k 2 2 v ...
Chapter 9 Rotational Dynamics continued
... A rigid body is in equilibrium if it has zero translational acceleration and zero angular acceleration. In equilibrium, the sum of the externally applied forces is zero, and the sum of the externally applied torques is zero. ...
... A rigid body is in equilibrium if it has zero translational acceleration and zero angular acceleration. In equilibrium, the sum of the externally applied forces is zero, and the sum of the externally applied torques is zero. ...
Apparently Deriving Fictitious Forces
... ω, in order not to make things too complex, the movement of the observer around the spinning space should not interfere with ω, as it does if he has mass, due to the need to conserve angular momentum. On the other hand, if we consider him as being a ghost, such a being would f ...
... ω, in order not to make things too complex, the movement of the observer around the spinning space should not interfere with ω, as it does if he has mass, due to the need to conserve angular momentum. On the other hand, if we consider him as being a ghost, such a being would f ...
