Honors Physics Unit 5 Notes
... The relative locations of all particles making up the object remain constant All real objects are deformable to some extent, but the rigid object model is very useful in many situations where the deformation is negligible ...
... The relative locations of all particles making up the object remain constant All real objects are deformable to some extent, but the rigid object model is very useful in many situations where the deformation is negligible ...
T = mv 2 / r
... Uniform Circular Motion, UCM: moving in a circle with a constant speed. Question: Is there a constant velocity when an object moves in a circle with a constant speed? No, the direction changes, therefore the velocity changes. If the velocity changed, the object is actually ACCELERATING even while m ...
... Uniform Circular Motion, UCM: moving in a circle with a constant speed. Question: Is there a constant velocity when an object moves in a circle with a constant speed? No, the direction changes, therefore the velocity changes. If the velocity changed, the object is actually ACCELERATING even while m ...
Rolling Motion: • A motion that is a combination of rotational
... Conservation of Angular Momentum: • If any component of the net external torque on a system is zero, then the component of the angular momentum of the system along that axis is conserved. • If a rotating object can some how changes its moment of inertia by internal forces, then the object will spin ...
... Conservation of Angular Momentum: • If any component of the net external torque on a system is zero, then the component of the angular momentum of the system along that axis is conserved. • If a rotating object can some how changes its moment of inertia by internal forces, then the object will spin ...
Class Notes - St. Bonaventure University
... meter is m, for second s or sec, for kilogram kg. So each time a new unit is introduced, so will be its standard abbreviation. d. ...
... meter is m, for second s or sec, for kilogram kg. So each time a new unit is introduced, so will be its standard abbreviation. d. ...
Newton`s Second Law
... The goal of this experiment is to investigate the relationship between force, mass and acceleration. You will be verifying a powerful physical law well known as Newton's second law. F = ma You will also be comparing the gravitational mass of an object with its inertial mass. Where: m=W/g (gravitati ...
... The goal of this experiment is to investigate the relationship between force, mass and acceleration. You will be verifying a powerful physical law well known as Newton's second law. F = ma You will also be comparing the gravitational mass of an object with its inertial mass. Where: m=W/g (gravitati ...
Chapter 7
... Work W is energy transferred to or from an object by means of a force acting on the object. If the object is accelerated by applying a force, its kinetic energy K increases. Energy transferred to the object is positive work +W. If you decelerate the object by applying a force, you decrease its ...
... Work W is energy transferred to or from an object by means of a force acting on the object. If the object is accelerated by applying a force, its kinetic energy K increases. Energy transferred to the object is positive work +W. If you decelerate the object by applying a force, you decrease its ...
Motion Dukes oHazzard 08t
... Velocity- describes the speed and direction of something • You can change velocity without changing speed if you turn a corner. • If you travel at 10mph on Lombard street your speed stays the same. 2.) Does velocity change? ...
... Velocity- describes the speed and direction of something • You can change velocity without changing speed if you turn a corner. • If you travel at 10mph on Lombard street your speed stays the same. 2.) Does velocity change? ...
Section 1 Powerpoint
... • Force is measured in newtons (N) • One newton is the force that causes a 1kilogram mass to accelerate at a rate of 1 meter per second each second (1 m/s2). ...
... • Force is measured in newtons (N) • One newton is the force that causes a 1kilogram mass to accelerate at a rate of 1 meter per second each second (1 m/s2). ...
Physics Oral Exam Questions: What are some elements of good
... independent variable, x-axis, y-axis, quantitative data, qualitative data, etc. 2. Choose a lab that you performed. Explain the question(s) the lab sought to answer, the procedures, the results, and your conclusion. Analyze the experimental design of the lab. a. Key terms: trials, uncontrolled varia ...
... independent variable, x-axis, y-axis, quantitative data, qualitative data, etc. 2. Choose a lab that you performed. Explain the question(s) the lab sought to answer, the procedures, the results, and your conclusion. Analyze the experimental design of the lab. a. Key terms: trials, uncontrolled varia ...
Force Diagrams
... Compression Fc Draw in the direction the object uses its force to move an object. Magnetic Fm Drawn toward the magnet. ...
... Compression Fc Draw in the direction the object uses its force to move an object. Magnetic Fm Drawn toward the magnet. ...
Force Diagrams
... Compression Fc Draw in the direction the object uses its force to move an object. Magnetic Fm Drawn toward the magnet. ...
... Compression Fc Draw in the direction the object uses its force to move an object. Magnetic Fm Drawn toward the magnet. ...
13.11. Visualize: Solve: Torque by a force is defined as τ = Frsinφ
... Solve: Torque by a force is defined as τ = Frsinφ where φ is measured counterclockwise from the r vector to the r F vector. The net torque on the pulley about the axle is the torque due to the 30 N force plus the torque due to the 20 N force: (30 N)r1 sinφ1 + (20 N)r2 sinφ2 = (30 N)(0.02 m) sin ( − ...
... Solve: Torque by a force is defined as τ = Frsinφ where φ is measured counterclockwise from the r vector to the r F vector. The net torque on the pulley about the axle is the torque due to the 30 N force plus the torque due to the 20 N force: (30 N)r1 sinφ1 + (20 N)r2 sinφ2 = (30 N)(0.02 m) sin ( − ...
Conservation Laws for Systems of Particles
... The above expression is very powerful and allows us to solve, with great simplicity, a large class of problems in rigid body dynamics. Its power lies in the fact that it is applicable in very general situations: In the derivation of equation (16), we have made no assumptions about the motion of the ...
... The above expression is very powerful and allows us to solve, with great simplicity, a large class of problems in rigid body dynamics. Its power lies in the fact that it is applicable in very general situations: In the derivation of equation (16), we have made no assumptions about the motion of the ...
worksheet 3 with scaffolding
... 6. A 50 kg sled is pulled along a snow-covered ground. If the coefficient of friction between the sled and the ground (mu, or ) is 0.10, what force must be applied in order to move the sled from rest to a speed of 6.0m/s in 2.0seconds? Draw a diagram Consider the forces (if applicable): Feartho ...
... 6. A 50 kg sled is pulled along a snow-covered ground. If the coefficient of friction between the sled and the ground (mu, or ) is 0.10, what force must be applied in order to move the sled from rest to a speed of 6.0m/s in 2.0seconds? Draw a diagram Consider the forces (if applicable): Feartho ...