Lecture 1 and 2a - Thermochemistry
... because diamond is not the standard state of carbon. The enthalpy value for C(diamond) is 1.8kJ/mol. Example: Calculate the enthalpy change for the following reaction using standard enthalpy values found in a table of thermodynamic values. 2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(g) ΔHºrxn = Solution: Loo ...
... because diamond is not the standard state of carbon. The enthalpy value for C(diamond) is 1.8kJ/mol. Example: Calculate the enthalpy change for the following reaction using standard enthalpy values found in a table of thermodynamic values. 2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(g) ΔHºrxn = Solution: Loo ...
PDF document
... there is no kinetic-spectrophotometric method for the determination of acetylsalicylic acid in the literature. Spectrophotometry is the technique of choice even today due to its inherent simplicity. It is frequently used in the laboratories of the developing countries to overcome a variety of analyt ...
... there is no kinetic-spectrophotometric method for the determination of acetylsalicylic acid in the literature. Spectrophotometry is the technique of choice even today due to its inherent simplicity. It is frequently used in the laboratories of the developing countries to overcome a variety of analyt ...
AP Chemistry
... (D) 1.0 M CH3COOH (E) 1.0 M NaCl (B) 1.0 M H2SO4 (C) 1.0 M H3PO4 1213. Although structural isomers C3H7OH and C2H5OCH3 exhibit different properties, which of the following would be expected to be the same for both compounds? (A) Heats of fusion (D) Molecular masses (B) Melting points (E) Heats of va ...
... (D) 1.0 M CH3COOH (E) 1.0 M NaCl (B) 1.0 M H2SO4 (C) 1.0 M H3PO4 1213. Although structural isomers C3H7OH and C2H5OCH3 exhibit different properties, which of the following would be expected to be the same for both compounds? (A) Heats of fusion (D) Molecular masses (B) Melting points (E) Heats of va ...
Mixing Problems – Part I d dt V(t) = dV dt = dV dt
... the mass function m ( t ) for the mixing problem where the filling and draining rates are equal is made up of a constant term, which is the stationary solution value V0 · cin , and an exponential decay term in which the difference between the initial mass and the “long-term” mass of salt dies away t ...
... the mass function m ( t ) for the mixing problem where the filling and draining rates are equal is made up of a constant term, which is the stationary solution value V0 · cin , and an exponential decay term in which the difference between the initial mass and the “long-term” mass of salt dies away t ...
Discussion 9, Mahaffy et al., Chapter 15
... a. Oxidation is loss of electrons (acts as a reducing agent) b.Reduction is gain of electrons (acts as a oxidizing agent) Assigning Oxidation numbers c. Oxidation number is 0 for atoms in an element. d.The sum of all oxidation numbers in a molecule or ion must add up to the total charge. e. In compo ...
... a. Oxidation is loss of electrons (acts as a reducing agent) b.Reduction is gain of electrons (acts as a oxidizing agent) Assigning Oxidation numbers c. Oxidation number is 0 for atoms in an element. d.The sum of all oxidation numbers in a molecule or ion must add up to the total charge. e. In compo ...
CHAPTER-7 EQUILIBRIUM Equilibrium state- When
... Ka x Kb = Kw = ionic product of water=1 x 10-14 Buffer solution :The solutions which resist change in pH on dilution or with the addition of small amounts of acid or alkali are called Buffer Solutions. common ion effect: It can be defined as a shift in equilibrium on adding a substance that pr ...
... Ka x Kb = Kw = ionic product of water=1 x 10-14 Buffer solution :The solutions which resist change in pH on dilution or with the addition of small amounts of acid or alkali are called Buffer Solutions. common ion effect: It can be defined as a shift in equilibrium on adding a substance that pr ...
Chapter 14 - Moore Public Schools
... • If a reaction mixture containing both reactants and products is not at equilibrium, how can we determine in which direction it will proceed? • The answer is to compare the current concentration ratios to the equilibrium constant. • The concentration ratio of the products (raised to the power of th ...
... • If a reaction mixture containing both reactants and products is not at equilibrium, how can we determine in which direction it will proceed? • The answer is to compare the current concentration ratios to the equilibrium constant. • The concentration ratio of the products (raised to the power of th ...
2009 - NESACS
... 51. Carbon in the Universe comes from 3 He-4 nuclei fusing to create a C-12 atom—A very slow process requiring 100 million K deep inside giant red star core where H is all consumed and He is in abundance. Unstable Be-8 is crucial in creating C-12 but for a split second, 2 He−4 particles fuse to make ...
... 51. Carbon in the Universe comes from 3 He-4 nuclei fusing to create a C-12 atom—A very slow process requiring 100 million K deep inside giant red star core where H is all consumed and He is in abundance. Unstable Be-8 is crucial in creating C-12 but for a split second, 2 He−4 particles fuse to make ...
Exam 2
... unsimpliÞed answers will not be given full marks. • show all working in your answers to numerical questions. No credit will be given for an incorrect answer unless it is accompanied by details of the working. • make sure chemical equations are balanced and that the formulas for individual substances ...
... unsimpliÞed answers will not be given full marks. • show all working in your answers to numerical questions. No credit will be given for an incorrect answer unless it is accompanied by details of the working. • make sure chemical equations are balanced and that the formulas for individual substances ...
JF Physical Chemistry 2010-2011. JF CH 1101: Introduction to
... equilibrium at a certain temperature the concentrations of NH3 (g), H2(g) and N2(g) are 0.94 M, 1.60 M and 0.52 M respectively. The numerical value of the equilibrium constant Kc for the reaction is: (a) 0.415 ; (b) 1.13; (c) 1.06; (d) 0.664; (e) 1.27. Correct answer: a. 2. Calculate the concentrati ...
... equilibrium at a certain temperature the concentrations of NH3 (g), H2(g) and N2(g) are 0.94 M, 1.60 M and 0.52 M respectively. The numerical value of the equilibrium constant Kc for the reaction is: (a) 0.415 ; (b) 1.13; (c) 1.06; (d) 0.664; (e) 1.27. Correct answer: a. 2. Calculate the concentrati ...
C:\My Documents\My Documents\Teaching\chem130\hunt
... This set of review questions is designed to help you prepare for the first midterm exam, which will include the following two basic chemistry topics: (1) chemical reactions and stoichiometry (mole relationships, chemical equations and chemical reaction, sequential reactions, limiting reactants, net ...
... This set of review questions is designed to help you prepare for the first midterm exam, which will include the following two basic chemistry topics: (1) chemical reactions and stoichiometry (mole relationships, chemical equations and chemical reaction, sequential reactions, limiting reactants, net ...
Final Exam Review 2010 UbD
... 76. Define “limiting reactants” _______________________________________________________________ How do you determine the limiting reactant for a chemical reaction? ____________________________ 77. Define “ percent yield” ___________________________________________________________________ What is the ...
... 76. Define “limiting reactants” _______________________________________________________________ How do you determine the limiting reactant for a chemical reaction? ____________________________ 77. Define “ percent yield” ___________________________________________________________________ What is the ...
Use the following answers for questions 10
... When the concentration of substance B in the reaction above is doubled, all other factors being held constant, it is found that the rate of the reaction remains unchanged. The most probable explanation for this observation is that (A) the order of the reaction with respect to substance B is 1 (B) s ...
... When the concentration of substance B in the reaction above is doubled, all other factors being held constant, it is found that the rate of the reaction remains unchanged. The most probable explanation for this observation is that (A) the order of the reaction with respect to substance B is 1 (B) s ...
AlcoholsandEthersNote
... Naming Ethers : the larger of the two hydrocarbon chains is considered the parent chain (its name at the end). The smaller hydrocarbon chain has its name at the front with the ending changed to “-oxy” to denote the presence of the oxygen atom. A number is used to indicate which carbon on the parent ...
... Naming Ethers : the larger of the two hydrocarbon chains is considered the parent chain (its name at the end). The smaller hydrocarbon chain has its name at the front with the ending changed to “-oxy” to denote the presence of the oxygen atom. A number is used to indicate which carbon on the parent ...
Packet 4
... When diluting a concentrated acid it is often found that combining water and the acid is a very exothermic process, i.e. one that releases energy. In some cases this energy can be very significant and may even cause the water present to turn into the gaseous state (steam). As the steam leaves the sy ...
... When diluting a concentrated acid it is often found that combining water and the acid is a very exothermic process, i.e. one that releases energy. In some cases this energy can be very significant and may even cause the water present to turn into the gaseous state (steam). As the steam leaves the sy ...
Review AGº = -RTlnKº Calculate the equilibrium constant Kc at 25 ºC
... entropy, and free energy of an overall reaction. Hess’s Law: ΔH for a process is equal to the sum of ΔH for any set of steps, i.e., for any path that equals the overall process. (also works for ΔG and ΔS because they are state functions, too) Often the steps are the formation reactions to make subst ...
... entropy, and free energy of an overall reaction. Hess’s Law: ΔH for a process is equal to the sum of ΔH for any set of steps, i.e., for any path that equals the overall process. (also works for ΔG and ΔS because they are state functions, too) Often the steps are the formation reactions to make subst ...
Unit 2:
... 2. Suppose that a stable element with atomic number 119, symbol Q, has been discovered. (a) Write the ground-state electron configuration for Q, showing only the valence-shell electrons. (b) Would Q be a metal or a nonmetal? Explain in terms of electron configuration. (c) On the basis of periodic tr ...
... 2. Suppose that a stable element with atomic number 119, symbol Q, has been discovered. (a) Write the ground-state electron configuration for Q, showing only the valence-shell electrons. (b) Would Q be a metal or a nonmetal? Explain in terms of electron configuration. (c) On the basis of periodic tr ...
Chemical Equilibrium is reached when
... However, in 1 L of water we have 55.5 M of water which is very large compared with the concentrations of other species in solution, and we assume that it doesn’t change during the course of a reaction. Kc = [CH3COO-][H3O+]/[CH3COOH] Kc = Kc`[H2O] Note that it is general practice not to include units ...
... However, in 1 L of water we have 55.5 M of water which is very large compared with the concentrations of other species in solution, and we assume that it doesn’t change during the course of a reaction. Kc = [CH3COO-][H3O+]/[CH3COOH] Kc = Kc`[H2O] Note that it is general practice not to include units ...