STA 130 (Winter 2016): An Introduction to Statistical Reasoning and
... x = (x1 + x2 + . . . + xn )/n would have mean µ and variance σ 2 /n. • But the observed value of x was 8.11. • So, the P-value is the probability, assuming that µ = 7.5, that the value of x would have been 8.11 or more, or 6.89 or less (two-sided) (since 8.11 = 7.5 + 0.61, and 6.89 = 7.5 − 0.61). • ...
... x = (x1 + x2 + . . . + xn )/n would have mean µ and variance σ 2 /n. • But the observed value of x was 8.11. • So, the P-value is the probability, assuming that µ = 7.5, that the value of x would have been 8.11 or more, or 6.89 or less (two-sided) (since 8.11 = 7.5 + 0.61, and 6.89 = 7.5 − 0.61). • ...
Chapter 9
... and say that the expression on the right hand side has the t-distribution with n − 1 degrees of freedom, or simply the tn−1 -distribution. As for the normal distribution, we need tables for looking up values for the tdistribution. The shapes of the t-distributions are dependent on the degree of free ...
... and say that the expression on the right hand side has the t-distribution with n − 1 degrees of freedom, or simply the tn−1 -distribution. As for the normal distribution, we need tables for looking up values for the tdistribution. The shapes of the t-distributions are dependent on the degree of free ...
General Quantities, Besides Yes/No Example: Baby
... • So, the two-sided P-value is the probability that a normal, with mean 0, and sd 222.7, would be as large or larger than the observed value 725, or as small or smaller than −725. • In R: pnorm(725, 0, 222.7, lower.tail=FALSE) + pnorm(−725, 0, 222.7, lower.tail=TRUE). Answer: 0.00113. Much less than ...
... • So, the two-sided P-value is the probability that a normal, with mean 0, and sd 222.7, would be as large or larger than the observed value 725, or as small or smaller than −725. • In R: pnorm(725, 0, 222.7, lower.tail=FALSE) + pnorm(−725, 0, 222.7, lower.tail=TRUE). Answer: 0.00113. Much less than ...
Miami Dade College QMB 2100 Basic Business Statistics Practice
... 52. The mean length of a candy bar is 43 millimeters. There is concern that the settings of the machine cutting the bars have changed. Test the claim at the 0.02 level that there has been no change in the mean length. The alternate hypothesis is that there has been a change. Twelve bars (n = 12) wer ...
... 52. The mean length of a candy bar is 43 millimeters. There is concern that the settings of the machine cutting the bars have changed. Test the claim at the 0.02 level that there has been no change in the mean length. The alternate hypothesis is that there has been a change. Twelve bars (n = 12) wer ...
252onesx0
... Statement of problem: The problem statement is either “Test at the 5% significance level to see if the mean income is at least 20000,” or “Test at the 5% significance level to see if the mean income is less than 20000.” These statements are opposites. Since the first statement contains an implicit e ...
... Statement of problem: The problem statement is either “Test at the 5% significance level to see if the mean income is at least 20000,” or “Test at the 5% significance level to see if the mean income is less than 20000.” These statements are opposites. Since the first statement contains an implicit e ...
