Latitude and Longitude - Harvard University Laboratory for
... and the size of the sun becomes important. • The diameter of the sun and moon are 32’, over half a degree. • To get the highest precision – particularly near sunrise and sunset, must make corrections ...
... and the size of the sun becomes important. • The diameter of the sun and moon are 32’, over half a degree. • To get the highest precision – particularly near sunrise and sunset, must make corrections ...
The negative equivalent mass of gravitational fields
... A model of the density profile of Jupiter as a function of radius is discussed in The Cambridge Encyclopedia of Astronomy, Crown Publishers, page 215 in the 1977 edition. This model shows that the average density is reached at a radius of about 50,000 km from the center of the planet. This would im ...
... A model of the density profile of Jupiter as a function of radius is discussed in The Cambridge Encyclopedia of Astronomy, Crown Publishers, page 215 in the 1977 edition. This model shows that the average density is reached at a radius of about 50,000 km from the center of the planet. This would im ...
The Changing Earth Atmosphere
... atmosphere. These 2 regions are hotter than the underlying photosphere where the bulk of the energy flux is emitted. This heating primarily arises from magnetic fields on the surface of a star which diminish over time due to the slowing of the rotation of stars due to magnetic breaking with the magn ...
... atmosphere. These 2 regions are hotter than the underlying photosphere where the bulk of the energy flux is emitted. This heating primarily arises from magnetic fields on the surface of a star which diminish over time due to the slowing of the rotation of stars due to magnetic breaking with the magn ...
TWO DIFFERENT ALTITUDES
... 7. The altitude of __________ is the same as the observer's ___________. 8. In the Los Angeles area, the altitude of Polaris is _________. 9. The horizontal line that surrounds the observer is the _____________. 10. The sky seems to meet the earth or ocean at the ____________. 11. An object with an ...
... 7. The altitude of __________ is the same as the observer's ___________. 8. In the Los Angeles area, the altitude of Polaris is _________. 9. The horizontal line that surrounds the observer is the _____________. 10. The sky seems to meet the earth or ocean at the ____________. 11. An object with an ...
Science Problems for Calculus I - Bard Math Site
... 15. As part of a chemistry experiment, 0.250 moles of butyl chloride (C4 H9 Cl) are dissolved in water. The butyl chloride reacts with the water, producing butyl alcohol and hydrochloric acid. Initially, this reaction consumes butyl chloride at a rate of 0.030 moles/min. Let t be the time in minutes ...
... 15. As part of a chemistry experiment, 0.250 moles of butyl chloride (C4 H9 Cl) are dissolved in water. The butyl chloride reacts with the water, producing butyl alcohol and hydrochloric acid. Initially, this reaction consumes butyl chloride at a rate of 0.030 moles/min. Let t be the time in minutes ...
Recitation Ch6
... that the arm moves with constant speed during each swing. A typical arm is 70.0 cm long, measured from the shoulder joint. (a) What is the acceleration of a 1.0 gram drop of blood in the fingertips at the bottom of the swing? (b) Make a free-body diagram of the drop of blood in part (a). (c) Find th ...
... that the arm moves with constant speed during each swing. A typical arm is 70.0 cm long, measured from the shoulder joint. (a) What is the acceleration of a 1.0 gram drop of blood in the fingertips at the bottom of the swing? (b) Make a free-body diagram of the drop of blood in part (a). (c) Find th ...
Celestial Position Lines
... 4. Longitude by meridian passage of the sun 5. Longitude by chronometer 6. Intercept ...
... 4. Longitude by meridian passage of the sun 5. Longitude by chronometer 6. Intercept ...
ExamIIIRev
... height h2 as shown. What is the final kinetic energy of the mass m when it is at its final height h2? (NOTE! This question is asking for the KE, not the speed v). ...
... height h2 as shown. What is the final kinetic energy of the mass m when it is at its final height h2? (NOTE! This question is asking for the KE, not the speed v). ...
N (North) Equator Latitude and Declination
... declination is its angular distance above the celestial equator. The declination is also 90 degrees minus the angle the star makes with the earth’s axis; Since the North Star (Polaris) lies on this axis, we can say that the declination is the complement of the star’s angular distance from the North ...
... declination is its angular distance above the celestial equator. The declination is also 90 degrees minus the angle the star makes with the earth’s axis; Since the North Star (Polaris) lies on this axis, we can say that the declination is the complement of the star’s angular distance from the North ...
Habitable Zones around Evolved Stars
... Reimers’ relation: Mdot = -dM*/dt = η 4e-13 LR/M solar masses/year from fitting observations – it is, however, strongly affected by selection bias. The Padova “Bowen & Willson (1991)” formula is not the same as our current formula (derived from later models with different selection criteria). Wachte ...
... Reimers’ relation: Mdot = -dM*/dt = η 4e-13 LR/M solar masses/year from fitting observations – it is, however, strongly affected by selection bias. The Padova “Bowen & Willson (1991)” formula is not the same as our current formula (derived from later models with different selection criteria). Wachte ...
Stellar Structure — Polytrope models for White Dwarf density profiles
... and so the density and mass profiles inside a white dwarf obtained. The two boundary conditions are taken to be almost at r = 0 (not quite at r = 0 as RHS of Eq. (6) diverges there). Take this small value of r to be r = δ. Then the mass boundary condition is trivial, m(δ) = 0. This leaves only one n ...
... and so the density and mass profiles inside a white dwarf obtained. The two boundary conditions are taken to be almost at r = 0 (not quite at r = 0 as RHS of Eq. (6) diverges there). Take this small value of r to be r = δ. Then the mass boundary condition is trivial, m(δ) = 0. This leaves only one n ...
AST 443/PHY 517 Homework 1
... Which, if any, are observable (zenith distance <60o )? Which, if any, are above the horizon? 4. Which of these 5 stars can be observed at some time on this night from Cerro Tololo? At what times? 5. Which of these 5 stars is closest to the moon? What is the angular distance? 6. The sidereal time at ...
... Which, if any, are observable (zenith distance <60o )? Which, if any, are above the horizon? 4. Which of these 5 stars can be observed at some time on this night from Cerro Tololo? At what times? 5. Which of these 5 stars is closest to the moon? What is the angular distance? 6. The sidereal time at ...
Estimate the Kelvin-Helmholtz timescale for a 5 solar mass star on
... [A discussion along the following lines earns a few bonus marks: The collapse that occurs is not of the entire star, but only of the helium core. A fair estimate of the mass of this core is about 0.3 x the stellar mass (the Schoenberg-Chandrasekhar limit), and a fair estimate of the size of the core ...
... [A discussion along the following lines earns a few bonus marks: The collapse that occurs is not of the entire star, but only of the helium core. A fair estimate of the mass of this core is about 0.3 x the stellar mass (the Schoenberg-Chandrasekhar limit), and a fair estimate of the size of the core ...
The Celestial sphere
... Constellations are the areas that the sky is divided up into. There are 88 constellations in the whole celestial sphere. Asterisms are found in the constellations; they are the pictures observed by man in the stars. These also appear to be on the celestial sphere. 1. The stars in a constellation are ...
... Constellations are the areas that the sky is divided up into. There are 88 constellations in the whole celestial sphere. Asterisms are found in the constellations; they are the pictures observed by man in the stars. These also appear to be on the celestial sphere. 1. The stars in a constellation are ...
ASTR120 Homework 6 − Solutions
... a. Since Enceladus and Dione have a 1 : 2 ratio of orbital periods, the time between successive oppositions would be the orbital period of Dione -- 65.7 hours b. For this part, we want to use the small angle formula. According to the text, the linear diameter of Dione is 1.0 x 106 m. Enceladus is 2. ...
... a. Since Enceladus and Dione have a 1 : 2 ratio of orbital periods, the time between successive oppositions would be the orbital period of Dione -- 65.7 hours b. For this part, we want to use the small angle formula. According to the text, the linear diameter of Dione is 1.0 x 106 m. Enceladus is 2. ...
–1– Homework 4 Solutions 1. Fun physics with mean molecular
... b.Would a pure helium balloon float in the atmosphere of Jupiter? The atmosphere of Jupiter is 90% molecular Hydrogen and 10% Helium (by number, not weight). Calculate the net force on the balloon (you will have to look up the mass and radius of Jupiter) as a function of the surrounding atmospheric ...
... b.Would a pure helium balloon float in the atmosphere of Jupiter? The atmosphere of Jupiter is 90% molecular Hydrogen and 10% Helium (by number, not weight). Calculate the net force on the balloon (you will have to look up the mass and radius of Jupiter) as a function of the surrounding atmospheric ...
Measuring the Heavens: Parallax
... The distance L from the sun to earth is the radius of the earth’s orbit. The parallax angle is measured by sighting the star at different times of the year. We want to find the distance D to the star. A complete circle is 360°. The angle is a fraction of that. Likewise, the sun-earth distance L ...
... The distance L from the sun to earth is the radius of the earth’s orbit. The parallax angle is measured by sighting the star at different times of the year. We want to find the distance D to the star. A complete circle is 360°. The angle is a fraction of that. Likewise, the sun-earth distance L ...
Physics 127 Descriptive Astronomy Homework #2
... A-4. As viewed from Provo (latitude = +40°), a star transits (crosses the celestial meridian) south of the zenith at an altitude of 63°. What is the star's declination? What is the declination of a star which passes through Provo's zenith? Since the altitude of the celestial equator, where it inters ...
... A-4. As viewed from Provo (latitude = +40°), a star transits (crosses the celestial meridian) south of the zenith at an altitude of 63°. What is the star's declination? What is the declination of a star which passes through Provo's zenith? Since the altitude of the celestial equator, where it inters ...
AST 443/PHY 517 Homework 1 Solutions
... 4. Which of these 5 stars is closest to the moon? What is the angular distance? Sirius, at about 44.3 degrees 5. The sidereal time at midnight advances by 3m 56s each day. What are the best days to observe these targets? See column (3) above. 6. What is the minimum zenith distance for each star? Se ...
... 4. Which of these 5 stars is closest to the moon? What is the angular distance? Sirius, at about 44.3 degrees 5. The sidereal time at midnight advances by 3m 56s each day. What are the best days to observe these targets? See column (3) above. 6. What is the minimum zenith distance for each star? Se ...
Meteorology Study Guide
... ____________________________ 1. A radiator (heater) heating a room ____________________________ 2. Your hand holding an ice cube ____________________________ 3. Boiling a large pot of water ____________________________ 4. The seatbelts in a car getting hot on a sunny day ____________________________ ...
... ____________________________ 1. A radiator (heater) heating a room ____________________________ 2. Your hand holding an ice cube ____________________________ 3. Boiling a large pot of water ____________________________ 4. The seatbelts in a car getting hot on a sunny day ____________________________ ...
Chandra Sees the Atmosphere of a Neutron Star - Chandra X
... similar to diamond (3.5 gm/cc), and a temperature of nearly 2 million Kelvin. The surface gravity on the neutron star is 100 billion times stronger than on Earth, which causes the atmosphere to be incrredibly thing even with such a high temperature.” How much carbon is there? Problem 1 – What are th ...
... similar to diamond (3.5 gm/cc), and a temperature of nearly 2 million Kelvin. The surface gravity on the neutron star is 100 billion times stronger than on Earth, which causes the atmosphere to be incrredibly thing even with such a high temperature.” How much carbon is there? Problem 1 – What are th ...
Four Homework Assignments
... this opacity is representative, calculate a very approximate diffusion time in years out of the Sun. (c) Interpret your result and comment on what it might mean. 6. For degenerate electrons at high densities and “low” temperatures, the pressure is given by the formula: Pdeg = 0.99 × 1013 ...
... this opacity is representative, calculate a very approximate diffusion time in years out of the Sun. (c) Interpret your result and comment on what it might mean. 6. For degenerate electrons at high densities and “low” temperatures, the pressure is given by the formula: Pdeg = 0.99 × 1013 ...
2 - BYU Physics and Astronomy
... A-2. An observer notes that the stars neither rise nor set but move right to left, parallel to her horizon. What is her location? ...
... A-2. An observer notes that the stars neither rise nor set but move right to left, parallel to her horizon. What is her location? ...
No Slide Title
... The NCP is located above the north point on the horizon. The angular distance is equal to your latitude. The zenith is located an angular distance equal to your latitude from the CE, i.e., the declination of the zenith is your latitude. Any vertical line on your SC-1 (north-south) is a meridian. App ...
... The NCP is located above the north point on the horizon. The angular distance is equal to your latitude. The zenith is located an angular distance equal to your latitude from the CE, i.e., the declination of the zenith is your latitude. Any vertical line on your SC-1 (north-south) is a meridian. App ...
Air mass (astronomy)
In astronomy, air mass (or airmass) is the optical path length through Earth’s atmosphere for light from a celestial source. As it passes through the atmosphere, light is attenuated by scattering and absorption; the more atmosphere through which it passes, the greater the attenuation. Consequently, celestial bodies at the horizon appear less bright than when at the zenith. The attenuation, known as atmospheric extinction, is described quantitatively by the Beer–Lambert–Bouguer law.“Air mass” normally indicates relative air mass, the path length relative to that at the zenith at sea level so, by definition, the sea-level air mass at the zenith is 1. Air mass increases as the angle between the source and the zenith increases, reaching a value of approximately 38 at the horizon. Air mass can be less than one at an elevation greater than sea level; however, most closed-form expressions for air mass do not include the effects of elevation, so adjustment must usually be accomplished by other means.In some fields, such as solar energy and photovoltaics, air mass is indicated by the acronym AM; additionally, the value of the air mass is often given by appending its value to AM, so that AM1 indicates an air mass of 1, AM2 indicates an air mass of 2, and so on. The region above Earth’s atmosphere, where there is no atmospheric attenuation of solar radiation, is considered to have“air mass zero” (AM0).Tables of air mass have been published by numerous authors, including Bemporad (1904), Allen (1976),and Kasten and Young (1989).