File 3
... The atomic nucleus In addition to the “discovery” of the nucleus and of the proton, Rutherford also noted the need of a “neutral” particle in the atomic nucleus, due to the disagreement between the atomic number of an atom (number of positive charges) and its mass computed in atomic mass units. In ...
... The atomic nucleus In addition to the “discovery” of the nucleus and of the proton, Rutherford also noted the need of a “neutral” particle in the atomic nucleus, due to the disagreement between the atomic number of an atom (number of positive charges) and its mass computed in atomic mass units. In ...
Dual Nature of Radiation and Matter
... plate to an electroscope. He observed that the zinc plate lost its charge when it was illuminated by ultraviolet light. Further, the uncharged zinc plate became positively charged when it was irradiated by ultraviolet light. Positive charge on a positively charged zinc plate was found to be further ...
... plate to an electroscope. He observed that the zinc plate lost its charge when it was illuminated by ultraviolet light. Further, the uncharged zinc plate became positively charged when it was irradiated by ultraviolet light. Positive charge on a positively charged zinc plate was found to be further ...
section on Compton effect
... x-ray tube V by lm hc>eV. The wavelengths of the lines are characteristic of the element. becomes eV hf hc>lm or lm hc>eV 1.2407 106 V 1 m 1.24 103 V 1 nm. Thus, the Duane-Hunt rule is explained by Planck’s quantum hypothesis. (Notice that the value of lm can be used to determine ...
... x-ray tube V by lm hc>eV. The wavelengths of the lines are characteristic of the element. becomes eV hf hc>lm or lm hc>eV 1.2407 106 V 1 m 1.24 103 V 1 nm. Thus, the Duane-Hunt rule is explained by Planck’s quantum hypothesis. (Notice that the value of lm can be used to determine ...
Motion Along a Straight Line at Constant
... The electric field is given by F = QV/d & the magnetic field given by F = BQv Only ions with a particular velocity will allow QV/d = BQv & hence only ions with that particular velocity make it through the slit. Note that it is also independent of charge since the Qs cancel ...
... The electric field is given by F = QV/d & the magnetic field given by F = BQv Only ions with a particular velocity will allow QV/d = BQv & hence only ions with that particular velocity make it through the slit. Note that it is also independent of charge since the Qs cancel ...
Quanta and Waves - Calderglen High School
... When an object is heated it can radiate large amounts of energy as infrared radiation. We can feel this if we place a hand near, but not touching, a hot object. When an object is heated it starts to glow a dull red, followed by bright red, then orange, yell ow and finally white. At extremely high te ...
... When an object is heated it can radiate large amounts of energy as infrared radiation. We can feel this if we place a hand near, but not touching, a hot object. When an object is heated it starts to glow a dull red, followed by bright red, then orange, yell ow and finally white. At extremely high te ...
Lecture notes 7: Strong and weak interactions
... Energy source of the Sun The energy source of the Sun lies in the fusion of four protons to one helium nucleous, as proposed by Hans Bethe in the late 1930’s. Since the binding energy per nucleon is greater in helium than in a proton by a factor 0.007 such that the mass of the four individual proton ...
... Energy source of the Sun The energy source of the Sun lies in the fusion of four protons to one helium nucleous, as proposed by Hans Bethe in the late 1930’s. Since the binding energy per nucleon is greater in helium than in a proton by a factor 0.007 such that the mass of the four individual proton ...
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... Most of the particles passed right through A few particles were deflected VERY FEW were greatly deflected ...
... Most of the particles passed right through A few particles were deflected VERY FEW were greatly deflected ...