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Lesson 9.5: Factor x2 + bx + c Goal: Factor trinomials of the form x2 + bx + c. In Lesson 9.2, we learned that (x + 3)(x + 4) = x2 + 4x + 3x + 12 = x2 + 7x + 12 In this lesson, we will reverse this process to factor trinomials of the form x2 + bx + c. FACTORING TRINOMIALS The goal in factoring trinomials is to find two numbers that multiply to give you the back number, but those same two numbers add/subtract to give you the middle number. o The following table will be very beneficial to knowing what operations to put into your parenthesis when factoring based on your problem… Problem Factored Answer + + ( + )( + ) - + ( - )( - ) + - ( + )( - ) *largest # goes w/+ - - ( + )( - ) *largest # goes w/- Examples: a. x2 + 10x + 16 b. x2 + 3y – 10 Factors of 16: 1 x 16 2x8 4x4 Factors of 10: 1 x 10 2x5 Find the set of factors that will add/subtract to equal the middle number (x + 2)(x + 8) (x + 5)(x – 2) c. x2 – 5x + 6 d. x2 – 7x – 18 Factors of 6: 1x6 2x3 Factors of 18: 1 x 18 2x9 3x6 Find the set of factors that will add/subtract to equal the middle number (x – 3)(x – 2) (x + 2)(x – 9) You Try… Factor each trinomial. 57. x2 + 7x + 12 58. x2 + 9x + 8 61. z2 + 2z – 24 62. x2 – 11x – 60 59. x2 – 9x + 20 60. y2 + 4y – 21 ~This concludes Section 9.5…if you have any questions over this material, make sure to bring them to class tomorrow!