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1. I am based on uniform probability. I am what SHOULD happen in an experiment. ANSWER TO #1 Theoretical Probability 2. I represent the set of ALL possible outcomes of an experiment. I can be seen in the form of a tree diagram, a table or even a list. ANSWER TO #2 Sample Space 3. I am based on relative frequency. I am what actually occurs during an experiment. ANSWER TO #3 Experimental Probability 4. I am what you are looking for in an experiment β what you want to happen. I am the first part of the probability of an event ratio. ANSWER TO #4 Favorable Outcome 5. I am everything that could happen in an experiment. I am the second part of the probability of an event ratio. ANSWER TO #5 Possible Outcome 6. I am the chance some event will occur. I am the ratio of the number of favorable outcomes to the number of possible outcomes. ANSWER TO #6 Probability 7. I am one outcome or a collection of outcomes in an experiment. ANSWER TO #7 Simple Event 8. I am an event that consists of two or more simple events. ANSWER TO #8 Compound Event 9. I am a probability model which assigns equal probability to all outcomes in an experiment. I work with theoretical probability. ANSWER TO #9 Uniform Probability 10. I am a method to find the total number of outcomes. I have you multiple the total possible outcomes for each event together. ANSWER TO #10 Counting Principle 11. I am an experiment that is designed to model the action in a given situation. Essentially, I am a method of solving a problem by conducting an experiment that is similar to the situation in the problem. EXAMPLE: You flip a coin to predict if a baby will be a boy or a girl. ANSWER TO #11 Simulation 12. I am when one event does NOT affect the outcome of the other. Our probability can be determined by multiplying the probability of the first event by the probability of the second event. ANSWER TO #12 Independent Events 13. I am when one event DOES affect the outcome of the other. Our probability can be determined by multiplying the probability of the first event by the probability of the second event AFTER the first event occurs. ANSWER TO #13 Dependent Events 14. There are 10 yellow, 6 green, 9 orange, and 5 red cards in a stack of cards turned facedown. Determine P (two yellow cards) ANSWER TO #14 P= π ππ 15. There are 10 yellow, 6 green, 9 orange, and 5 red cards in a stack of cards turned facedown. Determine P (a red card then blue card) ANSWER TO #15 P=0 *there are no blue cards so it is not possible to have both events occur. 16. What is the theoretical probability you will flip heads on a coin? ANSWER TO #16 P= π π 17. You conduct an experiment of flipping a coin. You flip heads twice and tails once. What is the experimental probability of landing on heads? ANSWER TO #17 P= π π 18. Use the counting principle to help you determine how many different pair of shoes you can get from a store that has 6 different styles in 8 sizes. ANSWER TO #18 6 styles x 8 sizes = 48 pairs of shoes 19. I consist of two events in which either one or the other must happen, but they canβt happen at the same time. The sum of these two events is 1 or 100%. EXAMPLE: P (blue eyes) and its complement P (not blue eyes) ANSWER TO #19 Complementary Events 20. What is the probability of landing on a vowel? ANSWER TO #20 π ππ P = which is unlikely 21. Ms. Luna surveyed her class and discovered that 30% of her students have blue eyes. Identify the probability of the complement of this event. ANSWER TO #21 P =70% *(30% blue eyes + 70% not blue eyes = 100%) 22. You flip a coin and toss a cube. What is the probability you will land on tails then roll a 4? ANSWER TO #22 P= π ππ 23. What do you call the likelihood of an event with a 50% π or probability? π ANSWER TO #23 As likely to happen as not 24. A game requires players to roll two number cubes to move the game pieces. The faces of the cubes are labeled 1 through 6. What is the probability of rolling a 2 or 4 on the first number cube and then rolling a 5 on the second? ANSWER TO #24 P= π ππ * Probability of the first event reduces from 2 1 to and the probability of the second 6 3 1 event is so you multiply them together to 6 1 get 18