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Transcript
10.1 Radical Expressions and Functions
A radical expression is any expression that can be written in the form
𝑛
βˆšπ‘Ž where n is the index (an integer β‰₯ 2), and a is the radicand. If the
index is 2, it is usually not written. The √
sign.
symbol is called the radical
In working with radical expressions, it is necessary to divide them into
two groups: those with an even index and those with an odd index.
Expressions with an Even Index
ο‚· The radicand must be a nonnegative number (positive or zero).
It can’t be negative. The even root of a negative number is
β€œundefined” or a β€œnonreal number.”
βˆšβˆ’3 [read β€œthe square root of negative 3”] is a nonreal number
4
βˆšβˆ’2 [read β€˜the fourth root of negative 2”] is a nonreal number
ο‚· There are two roots:
𝑛
The principal (positive) root is represented using √
𝑛
The negative root is represented using βˆ’ √
If you want both roots, write
𝑛
√
.
.
𝑛
and βˆ’ √
OR
𝑛
±βˆš
√49 = 7 because 72 = 49
4
√81 = 3 because 34 = 81
βˆ’βˆš81 = βˆ’9 because (–9)2 = 81
4
βˆ’ √16 = βˆ’2 because (–2)4 = 16
Expressions with an Odd Index
ο‚· The radicand can be any real number (positive, negative or zero).
ο‚· There is only one root.
The root is positive if the radicand is positive.
The root is negative if the radicand is negative.
𝑛
Roots are represented using √ .
3
√64 = 4 because 43 = 64
3
βˆšβˆ’64 = βˆ’4 because (–4)3 = –64
Radical Functions
A radical relation equates a radical expression in one variable to a
second (dependent) variable.
3
𝑦 = √π‘₯
𝑦 = √2π‘₯ + 5
If a radical relation is a radical function, it can be written using
function notation.
𝑓(π‘₯) = √π‘₯
3
𝑔(π‘₯) = √2π‘₯ + 5
A radical function is written in the form 𝑓(π‘₯) = 𝐴(π‘₯ ) where 𝐴(π‘₯) is
a radical expression with the variable x in the radicand.
3
𝑓(π‘₯ ) = √5π‘₯ not a radical function because x is not part of the radicand
3
𝑓(π‘₯ ) = π‘₯ √5 is a better way to write this
3
𝑔(π‘₯ ) = 5 √π‘₯ is a radical function
𝑝(𝑑) = βˆšπ‘‘ + 3 is a radical function
Be careful when identifying the radicand. It is only that part of the
expression inside the radical sign.
𝑓(π‘₯ ) = √2x the radicand is 2
Better is 𝑓(π‘₯ ) = π‘₯√2
𝑔(π‘₯ ) = √2π‘₯ the radicand is 2x
β„Ž(π‘₯ ) = √2π‘₯ + 5 the radicand is 2x+5
𝑗(π‘₯ ) = √2π‘₯ + 5 the radicand is 2x
Domain of a Radical Function
The domain of a function is the set of all real-number values for the
independent variable that give a real–number result. Any value that
doesn’t give such a result is excluded from the domain and is referred to
as a restricted value.
In radical expressions with an odd index, the radicand can be any real
number. So, radical functions defined by odd roots have no restricted
values. The domain for these functions is all real numbers.
{π‘₯ |π‘₯ is a real number} or (βˆ’βˆž, ∞)
In radical expressions with an even index, the radicand must be positive
or zero. These expressions are not defined for any negative number. So,
those real numbers that result in a negative radicand are restricted
values and must be excluded from the domain.
Finding the Domain Algebraically
ο‚· Set up an inequality of the form
radicand β‰₯ 0
ο‚· Solve the inequality.
ο‚· Solutions to the inequality are the domain.
4
Example: Find the domain for 𝑓(π‘₯) = √3π‘₯ + 1.
3π‘₯ β‰₯ 0
π‘₯ β‰₯ 0
The radicand is 3x.
The domain is all real numbers greater than or equal to 0.
{π‘₯| π‘₯ β‰₯ 0}
or
[0, ∞)
-------------------------------------------------------------------------------------Example: Find the domain for β„Ž(π‘₯) = √5π‘₯ βˆ’ 4 + 1.
The radicand is 5x – 4.
5π‘₯ βˆ’ 4 β‰₯ 0
5π‘₯ β‰₯ 4
π‘₯ β‰₯ 4/5
4
The domain is all real numbers greater than or equal to .
5
4
{π‘₯| π‘₯ β‰₯ }
5
or
4
[ , ∞)
5
Example: Find the domain of the function 𝑔(π‘₯) = √2π‘₯ βˆ’ 5 + 3
The radicand is 2x – 5.
2π‘₯ – 5 β‰₯ 0
2π‘₯ β‰₯ 5
π‘₯β‰₯
5
2
The domain is all real numbers greater than or equal to
5
{π‘₯| π‘₯ β‰₯ }
or
2
5
2
5
[ , ∞)
2
-------------------------------------------------------------------------------------Evaluating Radical Functions
To evaluate radical functions, substitute the given value for the variable
and simplify. Do not leave the expression in radical form. Take the
indicated root rounding to two decimal places if necessary.
Example: For 𝑓 (π‘₯ ) = √5π‘₯ βˆ’ 6 , find 𝑓(2).
𝑓(2) = √5 βˆ™ 2 βˆ’ 6 = √10 βˆ’ 6 = √4 = 2
𝑓(2) = 2
-------------------------------------------------------------------------------------Example: For 𝑔(π‘₯ ) = βˆ’βˆš64 βˆ’ 8π‘₯ , find 𝑔(βˆ’3).
𝑔(βˆ’3) = βˆ’βˆš64 βˆ’ 8 βˆ™ βˆ’3 = βˆ’βˆš64 βˆ’ (βˆ’24)
= βˆ’βˆš64 + 24 = βˆ’βˆš88 β‰ˆ βˆ’9.38
𝑔(βˆ’3) β‰ˆ βˆ’9.38
-------------------------------------------------------------------------------------3
Example: For 𝑓 (π‘₯ ) = √π‘₯ βˆ’ 2 , find 𝑓 (127).
3
3
𝑓(127) = √127 βˆ’ 2 = √125 = 5
𝑓 (127) = 5
-------------------------------------------------------------------------------------3
Example: For 𝑔(π‘₯ ) = √8π‘₯ βˆ’ 8 , find 𝑔(βˆ’7).
3
3
3
𝑔(βˆ’7) = √8 βˆ™ βˆ’7 βˆ’ 8 = βˆšβˆ’56 βˆ’ 8 = βˆšβˆ’64 = βˆ’4
𝑔(βˆ’7) = βˆ’4
𝒏
Simplifying Radical Expressions of the Form βˆšπ’‚π’
Expressions with n even
𝑛
βˆšπ‘Žπ‘› = |π‘Ž| This is the principal π‘›π‘‘β„Ž root and must be positive.
𝑛
βˆ’ βˆšπ‘Žπ‘› = βˆ’|π‘Ž| This is the negative π‘›π‘‘β„Ž root and must be negative.
√(βˆ’6)2 = |βˆ’6| = 6
√25π‘₯ 6 = |5π‘₯ 3 | or 5|x 3 |
√(π‘₯ + 5)2 = |π‘₯ + 5|
4
√(π‘₯ βˆ’ 2)4 = |π‘₯ βˆ’ 2|
8
βˆ’βˆš(βˆ’5)2 = βˆ’|βˆ’5| = βˆ’5
βˆ’ βˆšπ‘¦ 8 = βˆ’|𝑦|
Expressions with n odd
𝑛
βˆšπ‘Žπ‘› = π‘Ž The sign of the root depends upon the sign of the radicand.
3
√53 = 5
3
√(βˆ’7)3 = βˆ’7
5
√(βˆ’3)5 = βˆ’3
3
√8π‘₯ 3 = 2π‘₯