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Q. Which of these will NOT happen down in the
Eventually, H burns outward in a shell
core, after the nuclear energy source shuts off?
• Heat source moves closer to surface.
A. The core will cool down.
• Layers below surface swell up.
B. Its pressure will decrease.
Starlayers
becomes
larger
C. The “weight” of the •outer
will
then
compress the core. • Surface becomes cooler
Ho
D. The core will become denser and
hotter.
 Red
giant.
wc
E. All of the above will happen.
th
an
Luminosity 
is b
e??
Inert He core
HHe burning
shell
Inert H
Diameter
 Temperature
Fission vs. Fusion
Iron (Fe) is the most stable nucleus.
Fission
Fusion
[Fig. 10.4]
Heavy nucleus (e.g. Uranium)
breaks up into lighter nuclei.
Light nuclei (e.g. Hydrogen)
combine to form heavier
nucleus.
1
Nucleosynthesis: where we came from.
• H, He, Li are only elements formed in initial formation of universe.
• simplest stable combinations of protons, neutrons and electrons
Fusion in stars  increasingly
Periodic Table of the
moreElements
complicated, but more
stable nuclei.
hydrogen
Fusion 
Periodic Table is in order of complexity
Mass (= energy) per Nucleon 
• Up until iron (Fe).
helium
uranium
Fission
Iron
lead
[Fig. 12.17]
Atomic Number (protons+neutrons) 
4 1H  4He
3 4He  12C
12C + 4He  16O, Ne, Na, Mg
Ne  O, Mg
O  Mg, S
Si Fe peak
Min.
Temp.
107 o K
2x108
8x108
1.5x109
2x109
3x109
Fusion in stars 
increasingly more
complicated, but more
stable nuclei.
• Up until iron (Fe).
Mass (= energy) per Nucleon 
Reaction
Atomic Number (protons+neutrons) 
Periodic Table is in order of complexity
2
Reaction
Luminosity 
4 1H  4He
3 4He  12C
12C + 4He  16O, Ne, Na, Mg
Ne  O, Mg
O  Mg, S
Si Fe peak
Min.
Temp.
107 o K
2x108
8x108
1.5x109
2x109
3x109
What we need
are: New
sources of fuel
 Renew nuclear burning.
 More pressure.
 Halt contraction.
Inert He core
HHe burning
shell
Inert H
Diameter
 Temperature
Reaction
4 1H  4He
3 4He  12C
12C + 4He  16O, Ne, Na, Mg
Ne  O, Mg
O  Mg, S
Si Fe peak
Min.
Temp.
107 o K
2x108
8x108
1.5x109
2x109
3x109
What we need
are: New
sources of fuel
Triple-alpha process
H  He (core)
• Contraction heats
center.
• Helium starts to
burn.
3
Reaction
Min. Temp.
4 1H  4He
107 o K
3 4He  12C
2x108
12C
+ 4He  16O, Ne, Na, Mg
Ne  O, Mg
8x108
1.5x109
O  Mg, S
2x109
Si Fe peak
3x109
2 M or less stars
• Following He  C burning,
core never gets hot enough for
further reactions.
Planetary nebula
shell expelled.
Outer layer
= inert hydrogen
Star continues to
shrink. Surface
becomes very hot.
[Fig.12.12]
Solar-mass star
Luminosity 
The future
of the
Sun
Notice changes in scale
Earth’s orbit.
Radius 
Time (billions of yrs.) 
4
But in more massive stars (>2 M)…
nuclear burning in successive shells
Reaction
4
1H

Min. Temp.
4He
107 o K
3 4He  12C
12C
2x108
+ 4He  16O, Ne, Na, Mg
Ne  O, Mg
8x108
1.5x109
O  Mg, S
2x109
Si Fe peak
3x109
“Onion skin” model
• Central core is iron
• Outer layers correspond to
each previous step in nuclear
burning chain.
Inert H
H fusion
He fusion
C fusion
O fusion
Ne fusion
Mg fusion
Si fusion
Inert iron core
[Fig 12.16]
Luminosity 
Here’s what
happens on
the H-R
diagram for
stars with
> 2 M .
Interactive HR Diagram
HR – The Movie
Temperature
[Fig. 12.14]
5