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Transcript
Addressing the
Network IPv4
CCNA Exploration Semester 1
Chapter 6
IP addressing – works at


OSI model layer 3
TCP/IP model Internet layer
Application
Presentation
Session
Transport
Network
Data link
Physical
M Rajab - 2008
Data
stream
HTTP, FTP,
TFTP, SMTP
etc
Segment
TCP, UDP
Packet
IP
Frame
Ethernet,
WAN
technologies
Bits
Application
Transport
Internet
Network Access
2
Addressing topics






Binary and decimal
Types of IP addresses
Assigning addresses
Network part and subnet masks
Calculating addresses
Ping and Traceroute Utilities
M Rajab - 2008
3
Binary and decimal








Convert to 8-bit binary
248
187
89
Convert to decimal
00110100
01010101
11001111
M Rajab - 2008
4
248 to binary
128
64
32
16
8
4
2
1
1
1
1
1
1
0
0
0
120
-64
56
56
-32
24
24
-16
8
248
-128
120
M Rajab - 2008
5
187 to binary
128
64
32
16
8
4
2
1
1
0
1
1
1
0
1
1
59
-32
27
27
-16
11
187
-128
59
M Rajab - 2008
11
-8
3
3
-2
1
6
89 to binary
128
64
32
16
8
4
2
1
0
1
0
1
1
0
0
1
89
-64
25
M Rajab - 2008
25
-16
9
9
-8
1
7
00110100 to decimal
128
64
32
16
8
4
2
1
0
0
1
1
0
1
0
0
32
16
32
+16
+ 4
52
M Rajab - 2008
4
52
8
01010101 to decimal
128
64
32
16
8
4
2
1
0
1
0
1
0
1
0
1
64
64
+16
+ 4
+ 1
85
M Rajab - 2008
16
4
1
85
9
11001111 to decimal
128
64
32
16
8
4
2
1
1
1
0
0
1
1
1
1
128
64
8
4
2
1
M Rajab - 2008
128
+ 64
+ 8
+ 4
+ 2
+ 1
207
207
10
Binary and decimal








Convert to 8-bit binary
248
11111000
187
10111011
89
01011001
Convert to decimal
00110100
52
01010101
85
11001111
207
M Rajab - 2008
11
IPv4 address
192.
168.
21.
17
11000000
10101000
00010101
00010001
octet
octet
octet
octet
network part
host part
Prefix /24 Subnet mask:
255.
255.
255.
0
11111111
11111111
11111111
00000000
M Rajab - 2008
12
Find the network address
192.
168.
21.
17
11000000
10101000
00010101
00010001
In a network address, all the host bits are 0.
192.
168.
21.
0
11000000
10101000
00010101
00000000
The router needs to do this for every packet.
M Rajab - 2008
13
Logical AND
192.
168.
21.
17
11000000
10101000
00010101
00010001
255.
255.
255.
0
11111111
11111111
11111111
00000000
192.
168.
21.
0
11000000
10101000
00010101
00000000
Do a logical AND at each position
M Rajab - 2008
14
Find the broadcast address
192.
168.
21.
17
11000000
10101000
00010101
00010001
In a broadcast address, all the host bits are 1.
192.
168.
21.
255
11000000
10101000
00010101
11111111
The broadcast is the last address in the network.
M Rajab - 2008
15
3 types of address




Every network has:
Network address – the first one
Broadcast address – the last one
Host addresses – everything in between
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16
Classful addressing
A
10.
17.
network part
172.
B
53.
host part
16.
38.
network part
C
192.
201
host part
168.
network part
M Rajab - 2008
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21.
17
host part
17
Classful addressing





Easy to work out but very wasteful.
Routers and hosts still assume class subnet
masks by default
Class A /8
255.0.0.0
Class B /16 255.255.0.0
Class C /24 255.255.255.0
M Rajab - 2008
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Classless addressing



Any suitable prefix can be used
We (and devices) need to know what the
prefix is.
More flexible, less wasteful.
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19
Classless addressing /16


172.16.0.0/16 mask 255.255.0.0
Broadcast address 172.16.255.255
172.
16.
0.
0
10101100
00010000
00000000
00000000


Hosts 172.16.0.1 to 172.16.255.254
65534 host addresses
M Rajab - 2008
20
Classless addressing /24


172.16.0.0/24 mask 255.255.255.0
Broadcast address 172.16.0.255
172.
16.
0.
0
10101100
00010000
00000000
00000000


Hosts 172.16.0.1 to 172.16.0.254
254 host addresses
M Rajab - 2008
21
Classless addressing /22


172.16.0.0/22 mask 255.255.252.0
Broadcast address 172.16.3.255
172.
16.
0.
0
10101100
00010000
00000000
00000000


Hosts 172.16.0.1 to 172.16.3.254
1022 host addresses
M Rajab - 2008
22
Classless addressing /26


172.16.0.0/22 mask 255.255.255.192
Broadcast address 172.16.0.63
172.
16.
0.
0
10101100
00010000
00000000
00000000


Hosts 172.16.0.1 to 172.16.0.62
62 host addresses
M Rajab - 2008
23
Classless addressing /28


172.16.0.0/28 mask 255.255.255.240
Broadcast address 172.16.0.15
172.
16.
0.
0
10101100
00010000
00000000
00000000


Hosts 172.16.0.1 to 172.16.0.14
14 host addresses
M Rajab - 2008
24
Calculating addresses





A host has IP address 192.168.1.70/24
What is the subnet mask?
What is the network address?
What is the broadcast address?
What is the range of host addresses in the
network?
M Rajab - 2008
25
192.168.1.70/24 – fill in the table
Last octet
binary
Last octet
decimal
Full
Host
Subnet mask
Network
Broadcast
First host
Last host
M Rajab - 2008
26
192.168.1.70/24
Host
Last octet
binary
01000110
Subnet mask
00000000
0
255.255.255.0
Network
00000000
0
192.168.1.0
Broadcast
11111111
255
First host
00000001
1
Last host
11111110
254
M Rajab - 2008
Last octet
Full
decimal
70
192.168.1.70
192.168.1.255
192.168.1.1
192.168.1.254
27
Calculating addresses





A host has IP address 192.168.1.70/26
What is the subnet mask?
What is the network address?
What is the broadcast address?
What is the range of host addresses in the
network?
M Rajab - 2008
28
192.168.1.70/26 fill in the table
Last octet
binary
Last octet
decimal
Full
Host
Subnet mask
Network
Broadcast
First host
Last host
M Rajab - 2008
29
192.168.1.70/26
Host
Last octet
binary
01000110
Subnet mask
11000000
192
255.255.255.192
Network
01000000
64
192.168.1.64
Broadcast
01111111
127
192.168.1.127
First host
01000001
65
192.168.1.65
Last host
01111110
126
192.168.1.126
M Rajab - 2008
Last octet
Full
decimal
70
192.168.1.70
30
Calculating addresses





A host has IP address 192.168.1.70/28
What is the subnet mask?
What is the network address?
What is the broadcast address?
What is the range of host addresses in the
network?
M Rajab - 2008
31
192.168.1.70/28 fill in the table
Last octet
binary
Last octet
decimal
Full
Host
Subnet mask
Network
Broadcast
First host
Last host
M Rajab - 2008
32
192.168.1.70/28
Host
Last octet
binary
01000110
Subnet mask
11110000
240
255.255.255.240
Network
01000000
64
192.168.1.64
Broadcast
01001111
79
192.168.1.79
First host
01000001
65
192.168.1.65
Last host
01001110
78
192.168.1.78
M Rajab - 2008
Last octet
Full
decimal
70
192.168.1.70
33
Unicast, Multicast, Broadcast



Unicast – a message addressed to one host
Broadcast – a message addressed to all
hosts on a network. Uses network’s
broadcast address or 255.255.255.255 locally
Multicast – a message addressed to a group
of hosts. Uses an address starting 224 - 239
M Rajab - 2008
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Private IP addresses




Unrestricted use on private networks. Not
routed across the Internet.
10.0.0.0 – 10.255.255.255 (10.0.0.0/8)
172.16.0.0 – 172.31.255.255 (172.16.0.0/20)
192.168.0.0 – 192.168.255.255
(192.168.0.0/24)
M Rajab - 2008
35
Public IP addresses





Routed over the Internet
Master holder is IANA
Assigned to regional registries and then to
ISPs
ISPs allocate them to organisations and
individual users
Use is strictly controlled as duplicate
addresses are not allowed
M Rajab - 2008
36
Special addresses





0.0.0.0 “all addresses” in default route. Hosts
cannot be given addresses starting 0.
127.0.0.1 is loopback. Hosts cannot be given
addresses starting 127.
240.0.0.0 and higher – reserved for
experimental purposes.
169.254.0.0 - 169.254.255.255 local only
192.0.2.0 to 192.0.2.255 for teaching
M Rajab - 2008
37
Network address translation



A large number of hosts on a network use
private addresses to communicate with each
other.
The ISP allocates one or a few public
addresses.
NAT allows the hosts to share the public
addresses when they want to use the Internet
M Rajab - 2008
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Addressing hosts




Static addressing – address is configured by
an administrator
Servers, printers, routers, switches need
static addresses
Dynamic addressing – address is allocated
automatically by DHCP by leasing addresses
from a pool
Dynamic addressing is best for workstations
M Rajab - 2008
39
Blocks of addresses
Use
Address range
Network address 192.168.1.0
Summary
192.168.1.0/25
User hosts
192.168.1.1-127
Servers
192.168.1.128 - 191 192.168.1.128/26
Peripherals
192.168.1.192 - 223 192.168.1.192/27
Network devices 192.168.1.224 - 253 192.168.1.224/27
Router
192.168.1.254
Broadcast
192.168.1.255
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40
Subnetting 192.168.1.0/24
Last octet binary
Address
192.168.1.0
00000000
Subnet mask
255.255.255.0
00000000
Borrow 1 bit from host part, give it to network part, /25
Addresses
Subnet mask
M Rajab - 2008
192.168.1.0
192.168.1.128
255.255.255.128
00000000
10000000
10000000
41
Subnetting 192.168.1.0/24
Borrow 2 bits from host part, give to network part, /26
Addresses
Subnet mask
M Rajab - 2008
192.168.1.0
192.168.1.64
192.168.1.128
192.168.1.192
255.255.255.192
00000000
01000000
10000000
11000000
11000000
42
Subnetting 192.168.1.0/24
Borrow 3 bits from host part, give to network part, /27
Addresses
Subnet mask
M Rajab - 2008
192.168.1.0
192.168.1.32
192.168.1.64
192.168.1.96
192.168.1.128
192.168.1.160
192.168.1.192
192.168.1.224
255.255.255.224
00000000
00100000
01000000
01100000
10000000
10100000
11000000
11100000
11100000
43
Subnetting 192.168.1.0/24
Borrow 4 bits from host part, give to network part, /28
192.168.1.0
192.168.1.128
00000000
10000000
192.168.1.16 192.168.1.144
00010000
10010000
192.168.1.32 192.168.1.160
00100000
10100000
192.168.1.48 192.168.1.176
00110000
10110000
192.168.1.64 192.168.1.192
01000000
11000000
192.168.1.80 192.168.1.208
01010000
11010000
192.168.1.96 192.168.1.224
01100000
11100000
192.168.1.112 192.168.1.240
01110000
11110000
Subnet mask 255.255.255.240
11110000
And so on…
M Rajab - 2008
44
Subnetting 192.168.1.0/24



Every time you borrow another bit you:
 Double the number of subnets
 Halve the size of the subnets
Each subnet has a network address, a
broadcast address, and everything in
between is a host address.
Here are some ways of visualising the
process.
M Rajab - 2008
45
Subnetting 192.168.1.0/24
Bits borrowed
1
2
3
4
5
6
No of networks 2
4
8
16
32
64
Prefix
/25
/26
/27
/28
/29
/30
Bit value/
network size
No of hosts
128
64
32
16
8
4
126
62
30
14
6
2
Subnet mask
128
192
224
240
248
252
M Rajab - 2008
46
Address space


Make a spreadsheet or table with numbers 0
to 255
Link to show table
M Rajab - 2008
47
Subnet chart
M Rajab - 2008
48
Subnetting




There are many subnet calculators, but you
will not be able to use them in exams.
Start with the biggest subnet and work down
to the smallest.
Make sure the subnets are valid sizes with
valid subnet masks.
Make sure that there are no overlaps.
M Rajab - 2008
49
Ping and traceroute


Ping sends an ICMP message. If all is well,
the destination replies. If not, a router may
reply to say the destination is unreachable, or
the ping may time out.
Traceroute sends a series of messages so
that each router along the path replies. You
get a list of addresses of all the routers.
M Rajab - 2008
50
IPv6






Development started in 1990s because of
concerns about IPv4 addresses running out
A whole new protocol suite – not just layer 3
Uses 128-bit hierarchical addressing, written
using hexadecimal
Simpler header
Integrated security – authentication, privacy
Quality of service mechanisms
M Rajab - 2008
51
The End