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Do Now 1.) If there are initially 100 fruit flies in a sample, and the number of fruit flies decreases by one-half each hour, How many fruit flies will be present after 5 hours? 4 - 26 - 2012 2.) Sara bought 4 fish. Every month the number of fish she has doubles. After 6 months she will have how many fish. 4 - 27 - 2012 1.) Simplify. 2573(1 0.92) Do Now 2.) 0.0292 40001 4 3 18,211.40582 3.) P 1 r t 4 4118.08 Evaluate using this formula when P is 1219, r is 0.12, and t is 5. 12191 .12 5 2148.29 Do Now 1.) How many half-lives would it take to have a 700 gram sample of uranium reduce to under 3 grams of uranium ? 4 - 30 - 2012 2.) If there are initially 10 bacteria in a culture, and the number of bacteria double each hour, find the number of bacteria after 24 hours. 5 - 4 - 2012 Do Now When a person takes a dosage of I milligrams of a medicine, the amount A ( in milligrams) of medication remaining in the person’s bloodstream after t hours can be modeled by the equation . A I (0.71) t Using the formula, Find the amount of medication remaining in a person’s bloodstream if the dosage was 500 mg and 2.5 hours has lapsed. 5 - 4 - 2012 Compound Interest Do Now A P(1 ) r nt n You want to have $ 20,000 in your account after 18 years. Find the amount your initial deposit should be if the account pays 4.5% annual interest compounded monthly. Identify: A= P= r= n= t= 5 - 4 - 2012 Compound Interest Do Now A P(1 ) r nt n You want to have $ 20,000 in your account after 18 years. Find the amount your initial deposit should be if the account pays 4.5% annual interest compounded monthly. A = 20,000 P= ? r = .045 20000 P(1 n = 12 .045 (12)(18) 12 ) 20000 P(2.2445) 8,910 P t = 18 5 - 8 - 2012 Do Now y 350(1 .75) In the equation , which of the following is true? 10 a) There is a Growth Rate? g) The initial amount is 350? b) There is a Decay Rate? h) The time period is 10 ? c) The Decay Rate is 75% ? I) “y” is the final amount? d) The Decay Rate is 25% ? j) This is an Exponential ….Growth ….Decay e) The Decay Factor is .25 ? f) The Decay Factor is (1 - .75) ? Do Now 1.) If you invested $ 2,000 at a rate of 0.6% compounded continuously, find the balance in the account after 5 years, use the formula (.006)( 5 ) rt 5 - 9 - 2012 A Pe A 2000e $ 2,060.91 2. ) Simplify the Expression 25 18e 12 6e 13 3e Do Now 5 - 10 - 2012 y P(1 r ) t Exponential Growth y P(1 r ) t r A P 1 n a Pe rt Exponential Decay nt Compounded Interest ex) Compounded daily Compounded monthly Compounded quarterly Continuously Compounded Interest 5 - 11 - 2012 Do Now 1.) RE-Write log 6 36 2 2.) RE-Write 10 1 3.) Evaluate log 4 245 4.) Graph 0 y log 4 x in Exponential form in Logarithmic form p. 478 Ch 7.1 Exponential Growth What you should learn: Graph and use Exponential Growth functions. Write an Exponential Growth model that describes the situation. A2.5.2 7.1 Graph Exponential Growth Functions Exponential Function • f(x) = bx where the base b is a positive number other than one. • Graph f(x) = 2x Notice the end behavior • As x → ∞ f(x) → ∞ • As x → -∞ f(x) → 0 • y = 0 is an asymptote What is an Asymptote? • A line that a graph approaches as you move away from the origin The graph gets closer and closer to the line y = 0 ……. But NEVER reaches it 2 raised to any power Will NEVER be zero!! y=0 Example 1 • Graph y 3 1 2 x • Plot (0, ½) and (1, 3/2) • Then, from left to right, draw a curve that begins just above the xaxis, passes thru the 2 points, and moves up to the right What do you think the Asymptote is? y=0 Example 2 • Graph y = - (3/2)x • • • • • • • y=0 Plot (0, -1) and (1, -1.5) Connect with a curve Mark asymptote D = ?? All reals R = ??? All reals < 0 Example 3 Graph y = 3·2x-1 - 4 • Lightly sketch y = 3·2x • Passes thru (0,3) & (1,6) • h = 1, k = -4 • Move your 2 points to the right 1 and down 4 • AND your asymptote k units (4 units down in this case) Now…you try one! Example 4 • Graph y = 2·3x-2 +1 • State the Domain and Range! • D = all reals • R = all reals >1 y=1 When a real-life quantity increases by a fixed percent each year, the amount y of the quantity after t years can be modeled by the equation t y a(1 r ) where • • • • a - Initial principal r – percent increase expressed as a decimal t – number of years y – amount in account after t years Notice that the quantity (1 + r) is called the Growth Factor Example The amount of money, A, accrued at the end of n years when a certain amount, P, is invested at a compound annual rate, r, is given by A P(1 r ) t If a person invests $310 in an account that pays 8% interest compounded annually, find the approximant balance after 5 years. A 310(1 .08) A = $455.49 5 Compound Interest Consider an initial principal P deposited in an account that pays interest at an annual rate, r, compounded n times per year. A P(1 ) r nt n • P - Initial principal • r – annual rate expressed as a decimal • n – compounded n times a year • t – number of years • A – amount in account after t years Compound Interest example A P(1 ) r nt n • You deposit $1000 in an account that pays 8% annual interest. • Find the balance after 1 year if the interest is compounded with the given frequency. • a) annually b) quarterly c) daily A=1000(1+ .08/1)1x1 = 1000(1.08)1 ≈ $1080 A=1000(1+.08/4)4x1 A=1000(1+.08/365)365x1 =1000(1.02)4 ≈1000(1.000219)365 ≈ $1082.43 ≈ $1083.28 p. 486 Ch 7.2 Exponential Decay What you should learn: Goal 1 Graph and use Exponential Decay functions. Goal 2 Write an Exponential Decay model that describes the situation. A2.5.2 7.2 Graph Exponential decay Functions Discovery Education – Example 3: Exponential Decay-Bloodstream P. 486 7.2 Exponential Decay Exponential Decay • Has the same form as growth functions f(x) = a(b)x • Where • BUT: a>0 0< b<1 (a fraction between 0 & 1) Recognizing growth and decay functions • State whether f(x) is an exponential growth or DECAY function • f(x) = 5(2/3)x • b = 2/3, 0 < b < 1 it is a decay function. • f(x) = 8(3/2)x • b = 3/2, b > 1 it is a growth function. • f(x) = 10(3)-x • rewrite as f(x)= 10(1/3)x so it is decay Recall from 7.1: • The graph of y= abx • Passes thru the point (0,a) (the y intercept is a) • The x-axis is the asymptote of the graph • a tells you up or down • D is all reals (the Domain) • R is y>0 if a>0 and y<0 if a<0 • (the Range) Graph: • y = 3(1/4)x • Plot (0,3) and (1,3/4) • Draw & label asymptote • Connect the dots using the asymptote y=0 Domain = all reals Range = reals>0 Graph • y = -5(2/3)x • Plot (0,-5) and (1,10/3) • Draw & label asymptote • Connect the dots using the asymptote y=0 Domain : all reals Range : y < 0 Now remember: To graph a general Exponential Function: • • • • y = a bx-h + k Sketch y = a bx h= ??? k= ??? Move your 2 points h units left or right …and k units up or down • Then sketch the graph with the 2 new points. Example graph y=-3(1/2)x+2+1 • Lightly sketch y=3·(1/2)x • Passes thru (0,-3) & (1,-3/2) • h=-2, k=1 • Move your 2 points to the left 2 and up 1 • AND your asymptote k units (1 unit up in this case) y=1 Domain : all reals Range : y<1 Using Exponential Decay Models • When a real life quantity decreases by fixed percent each year (or other time period), the amount y of the quantity after t years can be modeled by: • y = a(1-r)t • Where a is the initial amount and r is the percent decrease expressed as a decimal. • The quantity 1-r is called the decay factor Discovery Ed - Using functions to Gauge Filter Eff Ex: Buying a car! • You buy a new car for $24,000. • The value y of this car decreases by 16% each year. • Write an exponential decay model for the value of the car. • Use the model to estimate the value after 2 years. • Graph the model. • Use the graph to estimate when the car will have a value of $12,000. • Let t be the number of years since you bought the car. • The model is: y = a(1-r)t • = 24,000(1-.16)t • = 24,000(.84)t • Note: .84 is the decay factor • When t = 2 the value is y=24,000(.84)2 ≈ $16,934 Now Graph The car will have a value of $12,000 in 4 years!!! p. 492 7.3 Use Functions Involving e What you should learn: Goal 1 Will study functions involving the Natural base e Goal 2 Simplify and Evaluate expressions involving e Goal 3 Graph functions with e A3.2.2 7.3 Use Functions Involving e The Natural base e • Much of the history of mathematics is marked by the discovery of special types of numbers like counting numbers, zero, negative numbers, Л, and imaginary numbers. 7.3 Use Functions Involving e Natural Base e • Like Л and ‘i’, ‘e’ denotes a number. • Called The Euler Number after Leonhard Euler (1707-1783) • It can be defined by: e= 1 + 1 + 1 + 1 + 1 + 1 +… 0! 1! 2! 3! 4! 5! = 1 + 1 + ½ + 1/6 + 1/24 + 1/120+... ≈ 2.718281828459…. 7.3 Use Functions Involving e • The number e is irrational – its’ decimal representation does not terminate or follow a repeating pattern. • The previous sequence of e can also be represented: n (1+1/n) • As n gets larger (n→∞), gets closer and closer to 2.71828….. • Which is the value of e. 7.3 Use Functions Involving e Examples 3 e 7 e · 4 e 3 10e 5e2 (3e-4x)2 (-4x)2 9e 2e3-2 9e-8x 2e 9 8x e 7.3 Use Functions Involving e More Examples! 8 24e 5 8e 3e3 -5x -2 (2e ) -2 10x 2 e 10x e 4 7.3 Use Functions Involving e Using a calculator 7.389 2 • Evaluate e using a graphing calculator x • Locate the e button • you need to use the second button 7.3 Use Functions Involving e Evaluate e-.06 with a calculator 7.3 Use Functions Involving e Graphing • f(x) = rx ae is a natural base exponential function • If a > 0 & r > 0 it is a growth function • If a > 0 & r < 0 it is a decay function 7.3 Use Functions Involving e Graphing examples • Graph y = ex • Remember the rules for graphing exponential functions! • The graph goes thru (0,a) and (1,e) (1,2.7) (0,1) 7.3 Use Functions Involving e Graphing cont. • Graph y = e-x (1,.368) (0,1) 7.3 Use Functions Involving e Graphing Example • Graph y = 2e0.75x • State the Domain & Range (1,4.23) (0,2) • Because a=2 is positive and r=0.75, the function is exponential growth. • Plot (0,2)&(1,4.23) and draw the curve. 7.3 Use Functions Involving e Using e in real life. • In 8.1 we learned the formula for compounding interest n times a year. • In that equation, as n approaches infinity, the compound interest formula approaches the formula for continuously compounded interest: A= rt Pe 7.3 Use Functions Involving e Example of Continuously compounded interest You deposit $1000.00 into an account that pays 8% annual interest compounded continuously. What is the balance after 1 year? P = 1000, r = .08, and A= rt Pe t=1 = 1000e.08*1 ≈ $1083.29 7.3 Use Functions Involving e 7.4 Logarithms What you should learn: mathbook p. 499 Goal 1 Evaluate logarithms Goal 2 Graph logarithmic functions A3.2.2 7.4 Evaluate Logarithms and Graph Logarithmic Functions Evaluating Log Expressions • We know 22 = 4 and 23 = 8 • But for what value of y does 2y = 6 ? • Because 22 < 6 < 23 you would expect the answer to be between 2 & 3. • To answer this question exactly, mathematicians defined logarithms. Definition of Logarithm to base a • Let a & x be positive numbers & a ≠ 1. • The logarithm of x with base a is denoted by logax and is defined: logax = y iff y a =x • This expression is read “log base a of x” • The function f(x) = logax is the logarithmic function with base a. • The definition tells you that the equations logax = y and ay = x are equivilant. • Rewriting forms: • To evaluate log3 9 = x ask yourself… • “Self… 3 to what power is 9?” • 32 = 9 so…… log39 = 2 Log form • log216 = 4 • log1010 = 1 • log31 = 0 • log10 .1 = -1 • log2 6 ≈ 2.585 Exp. form • 24 = 16 1 • 10 = 10 0 •3 = 1 • 10-1 = .1 • 22.585 = 6 Evaluate without a calculator • log381 = 4 • Log5125 = 3 • Log4256 = 4 • Log2(1/32) = -5 x •3 = 81 x • 5 = 125 • 4x = 256 x • 2 = (1/32) Evaluating logarithms now you try some! • Log 4 16 = 2 • Log 5 1 = 0 • Log 4 2 = ½ (because 41/2 = 2) • Log 3 (-1) = undefined • (Think of the graph of y=3x) You should learn the following general forms!!! 0 a • Log a 1 = 0 because = 1 1 • Log a a = 1 because a = a • Log a ax = x because ax = ax Natural logarithms •log e x = ln x • ln means log base e Common logarithms •log 10 x = log x • Understood base 10 if nothing is there. Common logs and natural logs with a calculator log10 button ln button • g(x) = log • f(x) = bx b x is the inverse of • f(g(x)) = x and g(f(x)) = x • Exponential and log functions are inverses and “undo” each other • So: g(f(x)) = logb • x b =x log x f(g(x)) = b b = x • 10log2 = 2 x • Log39 = Log3(32)x =Log332x=2x logx • 10 = x x • Log5125 = 3x Finding Inverses • Find the inverse of: • y = log3x • By definition of logarithm, the inverse is x y=3 • OR write it in exponential form and switch the x & y! 3y = x 3x = y Finding Inverses cont. • Find the inverse of : • Y = ln (x +1) • X = ln (y + 1) • ex = y + 1 • ex – 1 = y Switch the x & y Write in exp form solve for y