Download (6 grade) second term (p.126- 129)

Math Department
6th primary
The Egyptian Language School
(6th grade) second term
(p.126- 129)
28) The dimensions of the cuboid are length, width & height.
Length + width + height =
= 34 cm, Height 1 dcm = 10 cm
Length + width = 34 – 10 = 24cm
Width
:
Length
:
Sum
3
:
5
:
8
?
:
?
:
24
Width =
= 9cm,
Length = =
= 15 cm
Perimeter of the base = (L+w) x 2 = ( 15 + 9) x 2 = 48 cm
Lateral Area = Perimeter of base x height = 48 x 10 = 480 cm2
Area of base = Length x width = 15 x 9 = 135 cm2
Total Area = Lateral area + Area base x 2 = 480 + 135 x 2= 750 cm2
The Volume of a cuboid = Length x width x height = 15 x 9 x 10 = 1350 cm2
29) Perimeter of the base = (L+w) x 2 = ( 4.5 + 3.5) x 2 = 16 cm
Lateral Area = Perimeter of base x height = 16 x 3 = 48 cm2
Area of base = Length x width = 4.5 x 3.5 = 15.75 cm2
Total Area = Lateral area + Area base = 48 + 15.75= 63.75 cm2
The total area of the painted part of the room= 63.75 – 8 = 55.75 cm2
The cost of painting = 55.75 x 16 = 892 L.E.
30) Height = 3 cm, Height is half the width, then the width = 3 x 2 = 6 cm
Length is double its width = 6 x 2= 12 cm
[L = 12 cm, W = 6 cm, H = 3cm]
Perimeter of the base = (L + w) x 2 = ( 12 + 6) x 2 = 36 cm
Lateral Area = perimeter of base x height = 36 x 3 = 108 cm2
32) The total area of the remained part of the cube = the total area of the
original cube
The total area of the cube = side x side x 6 = 12 x 12 x 6 = 864 cm2
Perimeter of the base = (L+w) x 2 = ( 3 + 2) x 2 = 10 cm
Lateral Area = Perimeter of base x height = 10 x 1 = 10 cm2
Math Department
6th primary
The Egyptian Language School
Area of base = Length x width = 3 x 2 = 6 cm2
Total Area = Lateral area + Area base = 10 + 6 = 16 cm2
The total area of the remained part of the cube = the total area of the original
cube – the total area of the cuboid = 864 – 16 = 848 cm2
34) First: The probability the arrow hits area D =
Second: The probability the arrow hits area A =
Third: The probability the arrow hits area B or C =
35) First : divisible by 10 = [10, 20, 30, 40, 50] =
Second : divisible by 11 = [ 11, 22, 33, 44] =
=
=
Third: divisible by 10 or 11 =[10, 20, 30, 40, 50, 11, 22, 33, 44] =
Fourth: (square root) [ 4, 9, 16, 25, 36, 49] 50 – 6 = 43
Not perfect square =
36) First : the probability that the pupil play football =
Second : Number of pupils who plays other games =
=
= x 600 = 200
pupils.
37) The probability that the first player scores =
The probability that the second player scores =
≻
=
=
Then the best is choosing the second player because the probability is
greater.
38) a) The probability that her fridge size 6 feet =
=
b) The probability that her fridge size 10 feet =
=
c) The probability that her fridge size 12 feet =
=
d) The probability that her fridge size 14 feet =
=
e) The probability that her fridge size 16 feet =
=
Math Department
6th primary
The Egyptian Language School
41) a) Complete the following:
1) The random experiment is an experiment in which we can determine all its
possible outcomes before carrying it out, but we can’t predict in certainty
which of these outcomes will occur when the experiment is carried out.
2) The sample space is the set of all possible outcomes for a random
experiment.
b) Sample space = [1, 2, 3, 4, 5, 6, 7, 8 , 9, 10, 11, 12, 13, 14, 15]
First : P (A) =
Second : P (B) =
Third: P (C) =
=
=
42) The probability that this pupil got good =
=
43 ) The number of girls participating in this competition = x 45 = 20 girls.
1)
a)
b)
c)
d)
e)
2)
a)
b)
c)
d)
Model Test (1)
Complete each of the following:
{ -11} ⊄ Z+
7, 15, 23, 31, 39, 47, 55
(-5) x [7+(-5)] = (-5) x 2 = (-10)
The image of the point (4, 5) by translation (-2, 1) is (2, 6) [x = 4 + (-2) = 2
y = 5+1= 6 ]
Perimeter of the base = (Length + width) x 2 = (8 + 12) x 2 = 40 cm
Height = Lateral area ÷ perimeter of base = 200 ÷ 40 = 5 cm
Choose the correct answer:
-24 (d)
The closest expected number = 124
F2+ F
Π+4
Math Department
6th primary
The Egyptian Language School
3) a) X = -42 ÷ 7, Then X = -6
b) 79 ÷ 77= 72 = 49
4) The area of the piece of card cartoon = L x W = 240 x 160 = 38400 cm2.
The total area of the cubic case = S x S x 6 = 60 x 60 x 6 = 21600 cm2.
The area of the remained part after designing the case = 38400 – 21600 =
16800 cm2.
5) First : The probability of prime number =
=
Second : The probability of even number = =
Math Department
6th primary
The Egyptian Language School