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Transcript
Examples
Example 1
First, find all of the nodes in the circuit.
There are four nodes in this circuit.
Next, label the nodes.
Pick a node to be your reference node.
 I will pick the node with the most connections.
 So, V0 will be the reference and I will set its voltage to be
equal to 0 V.
Label the currents
 These are the currents that flow through all of the
components including the voltage and current sources.
Use Kirchhoff’s Current Law
 Current entering a node must be equal to the current
leaving a node.
 But you only need to use it on nodes V1, V2, and V3.
Node V1
I A  I B  IV
Node V2
IV  I C  0 A
Node V3
I D  I I  IC
Apply Ohm’s Law
 To rewrite currents in terms of node voltages.
 The difference in the node voltages across a resistor is
equal to its resistance times the current flowing through
the resistor.
 Ohm’s Law does not apply to current or voltage sources. So
we can not rewrite IV or II.
I A  0V  V 1 / 4k  V 1 / 4k
I B  V 1  0V  / 2k  V 1 / 2k
I C  V 3  V 2 / 3k
I D  0V  V 3 / 2k  V 3 / 2k
Substitute into the KCL equations
KCL Equations
KCL With Ohm’s Law
Node V1: I A  I B  IV
V1 V1
Node V1:

 IV
4k 2k
Node V2 : IV  I C  0 A
V 3 V 2
Node V2 : IV 
 0A
3k
Node V3: I C  I D  I I
V 3 V 2 V 3
Node V3:

 II
3k
2k
Gather other information from circuit
II is equal to 1mA
I I  1mA
The difference in voltage between
V2 and V1 is 5V
V 2  V 1  5V or V 2  5V  V 1
Substitute this information in
3 equations and three unknowns
V1 V1
Node V1:

 IV
4k 2k
V 3  5V  V 1
Node V2 : IV 
 0A
3k
V 3  5V  V 1 V 3
Node V3:

 1mA
3k
2k
Solution methods
 Use MATLAB or other mathematical software package.
 Use a graphing calculator.
 Calculate this by hand.
 You will not have access to MATLAB or other
mathematical software or a graphing calculator at the
final exam. Make sure that you know how to find the
solutions to a set of linear equations by hand.
Example 2: Wheatstone Bridge
 Used in to accurately and precisely determine value of
one unknown component.
 Many times the component’s value changes with an
environmental parameter, which allows you to monitor
the environmental parameter.
 For example, a thermister is a resistor whose value is a
known function of temperature. If we determine the
value of the thermister, we can then calculate the
temperature of the thermistor.

This technique is used to monitor temperature of furnaces,
ovens, refrigerators, and other systems.
Vmeas is a function of RL
Label nodes and let VD = 0V
 Note that Vmeas is the difference in voltage between
nodes VC and VB: Vmeas = VC - VB
Label currents
Write Equations
KCL:
IV  I1  I 2
I1  I 3
I2  I L
Extra Equations:
Ohm’s Law:
I1  VA  VB  / R1
I 2  VA  VC  / R2
I 3  VB  VD  / R3  VB / R3
I L  VC  VD  / RL  VC / RL
Vin  VA  VD  VA
Vmeas  VC  VB
Resistor values
 Usually in Wheatstone Bridge circuits,
 R1 = R2 = R3 = R
 Thus, the solution for Vmeas is:
 RL  1 
  
Vmeas  Vin 
 RL  R  2 
 When RL = R, Vmeas = 0V.
 When RL < R, Vmeas < 0V.
 When RL > R, Vmeas > 0V.
Summary
 Nodal Analysis is used to calculate the voltage at every
node in a circuit and the currents flowing out of or
into the voltage sources using a set of simultaneous
linear equations.
 The currents flowing through each resistor can then be
calculated using the equations written when applying
Ohm’s Law.