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Algorithms and Data Structures
(CSC112)
Handout -4
List
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List Data Structure
List operations
List Implementation
Array
Linked List

A list is collection of items that are all of the same type (grocery items, integers, names)
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The items, or elements of the list, are stored in some particular order

It is possible to insert new elements into various positions in the list and remove any
element of the list
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List is a set of elements in a linear order.
For example, data values a1, a2, a3, a4 can be arranged in a list:
(a3, a1, a2, a4)
In this list, a3, is the first element, a1 is the second element, and so on

The order is important here; this is not just a random collection of elements, it is an
ordered collection
List Operations
Useful operations
 createList(): create a new list (presumably empty)
 copy(): set one list to be a copy of another
 clear(); clear a list (remove all elments)
 insert(X, ?): Insert element X at a particular position
in the list
 remove(?): Remove element at some position in
the list
 get(?): Get element at a given position
 update(X, ?): replace the element at a given position
with X
 find(X): determine if the element X is in the list
 length(): return the length of the list.
We need to decide what is meant by “particular position”; we have used “?” for this.
 There are two possibilities:
 Use the actual index of element: insert after element 3, get element number 6. This
approach is taken by arrays
 Use a “current” marker or pointer to refer to a particular position in the list.

 If we use the “current” marker, the following four methods would be useful:
 start(): moves the “current” pointer to the first
element.
 tail(): moves the “current” pointer to the last
element.
 next(): move the current position forward one
element
 back(): move the current position backward one
element
Implementing Lists

We have designed the interface for the List; we now must consider how to implement
that interface.

Implementing Lists using an array: for example, the list of integers (2, 6, 8, 7, 1) could be
represented as:

add(9); current position is 3. The new list would thus be: (2, 6, 8, 9, 7, 1)

We will need to shift everything to the right of 8 one place to the right to make place for
the new element ‘9’.

Other operations:
get()
update(X)
length()
back()
start()
end()
 return A[current];
 A[current] = X;
 return size;
 current--;
 current = 1;
 current = size;
List Using Linked Memory

Various cells of memory are not allocated consecutively in memory.

With arrays, the second element was right next to the first element.

Now the first element must explicitly tell us where to look for the second element.

Do this by holding the memory address of the second element

This is what we call Linked List
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