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Emf and Terminal Voltage V=emf-Ir emf is voltage battery 'can deliver' to circuit in principle V=emf-Ir is voltage battery 'can deliver' to circuit in practice. This is called the terminal voltage. As current flows, the effective voltage, V, is reduced by Ir emf I Battery V R r (internal resistance of battery) Application of Ohm's Law indicates Emf = terminal voltage when I = 0 since Ir = 0 Example A battery labeled 12.0 V supplies 1.90 A to a 6.00-ohm. What is the terminal voltage of the battery? What is its internal resistance? Solution: emf = 12.0 V I = 1.90 A R = 6.00 ohm V = emf-Ir = IR [like emf = I(r+R)] V=(1.90 A)(6.00 ohm)=11.4 V r = emf − V 12.0 − 11.4 = = 0.32 ohms I 1.90