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Transcript
Transient Behaviour
Chapter 18
 Introduction
 Charging Capacitors and Energising Inductors
 Discharging Capacitors and De-energising Inductors
 Response of First-Order Systems
 Second-Order Systems
 Higher-Order Systems
Storey: Electrical & Electronic Systems © Pearson Education Limited 2004
OHT 18.‹#›
Introduction
18.1
 So far we have looked at the behaviour of systems in
response to:
– fixed DC signals
– constant AC signals
 We now turn our attention to the operation of circuits
before they reach steady-state conditions
– this is referred to as the transient response
 We will begin by looking at simple RC and RL circuits
Storey: Electrical & Electronic Systems © Pearson Education Limited 2004
OHT 18.‹#›
Charging Capacitors and
Energising Inductors
18.2
Capacitor Charging
 Consider the circuit shown here
– Applying Kirchhoff’s voltage law
iR  v  V
– Now, in a capacitor
i C
dv
dt
– which substituting gives
CR
dv
v V
dt
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OHT 18.‹#›
 The above is a first-order differential equation with
constant coefficients
 Assuming VC = 0 at t = 0, this can be solved to give
v  V (1  e
-
t
t
CR )  V (1  e  )
– see Section 18.2.1 of the course text for this analysis
 Since i = Cdv/dt this gives (assuming VC = 0 at t = 0)
i  Ie
-
t
CR
 Ie
-
t

– where I = V/R
Storey: Electrical & Electronic Systems © Pearson Education Limited 2004
OHT 18.‹#›
 Thus both the voltage and current have an
exponential form
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Inductor energising
 A similar analysis of this circuit gives
v  Ve
-
i  I (1  e
Rt
L
-
 Ve
-
t

Rt
t
L )I (1  e  )
where I = V/R
– see Section 18.2.2 for this analysis
Storey: Electrical & Electronic Systems © Pearson Education Limited 2004
OHT 18.‹#›
 Thus, again, both the voltage and current have an
exponential form
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Discharging Capacitors and
De-energising Inductors
18.3
Capacitor discharging
 Consider this circuit for
discharging a capacitor
– At t = 0, VC = V
– From Kirchhoff’s voltage law
iR  v  0
– giving
CR
dv
v  0
dt
Storey: Electrical & Electronic Systems © Pearson Education Limited 2004
OHT 18.‹#›
 Solving this as before gives
v  Ve
i  Ie
-
-
t
CR
t
CR
 Ve
-
t

-
t

 Ie
– where I = V/R
– see Section 18.3.1 for this analysis
Storey: Electrical & Electronic Systems © Pearson Education Limited 2004
OHT 18.‹#›
 In this case, both the voltage and the current take the
form of decaying exponentials
Storey: Electrical & Electronic Systems © Pearson Education Limited 2004
OHT 18.‹#›
Inductor de-energising
 A similar analysis of this
circuit gives
-
Rt
L
-
Rt
L
v  Ve
i  Ie
 Ve
 Ie
-
-
t

t

– where I = V/R
– see Section 18.3.1
for this analysis
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 And once again, both the voltage and the current
take the form of decaying exponentials
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 A comparison of the four circuits
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Response of First-Order Systems
18.4
 Initial and final value formulae
– increasing or decreasing exponential waveforms (for
either voltage or current) are given by:
v  Vf  (Vi  Vf )e t / 
i  If  (Ii  If )e t / 
–
–
–
–
–
where Vi and Ii are the initial values of the voltage and current
where Vf and If are the final values of the voltage and current
the first term in each case is the steady-state response
the second term represents the transient response
the combination gives the total response of the arrangement
Storey: Electrical & Electronic Systems © Pearson Education Limited 2004
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Example – see Example 18.3 from course text
The input voltage to the following CR network undergoes a
step change from 5 V to 10 V at time t = 0. Derive an
expression for the resulting output voltage.
Storey: Electrical & Electronic Systems © Pearson Education Limited 2004
OHT 18.‹#›
Here the initial value is 5 V and the final value is 10 V. The time
constant of the circuit equals CR = 10  103 20  10-6 = 0.2s.
Therefore, from above, for t  0
v  Vf  (Vi  Vf )e t / 
 10  (5  10)e t / 0.2
 10  5e t / 0.2 volts
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The nature of exponential curves
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Response of first-order
systems to a square
waveform
– see Section 18.4.3
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Response of first-order
systems to a square
waveform of different
frequencies
– see Section 18.4.3
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Second-Order Systems
18.5
 Circuits containing both capacitance and inductance
are normally described by second-order differential
equations. These are termed second-order systems
– for example, this circuit is described by the equation
LC
d2vC
dt 2
 RC
dv C
 vC  V
dt
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 When a step input is applied to a second-order
system, the form of the resultant transient depends
on the relative magnitudes of the coefficients of its
differential equation. The general form of the
response is
1 d2 y 2 dy

y  x
2
2
 n dt
n dt
– where n is the undamped natural frequency in rad/s
and  (Greek Zeta) is the damping factor
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Response of second-order systems
 =0 undamped
 <1 under damped
 =1 critically damped
 >1 over damped
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Higher-Order Systems
18.6
 Higher-order systems are those that are described
by third-order or higher-order equations
 These often have a transient response similar to that
of the second-order systems described earlier
 Because of the complexity of the mathematics
involved, they will not be discussed further here
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OHT 18.‹#›
Key Points
 The charging or discharging of a capacitor, and the
energising and de-energising of an inductor, are each
associated with exponential voltage and current waveforms
 Circuits that contain resistance, and either capacitance or
inductance, are termed first-order systems
 The increasing or decreasing exponential waveforms of
first-order systems can be described by the initial and final
value formulae
 Circuits that contain both capacitance and inductance are
usually second-order systems. These are characterised by
their undamped natural frequency and their damping factor
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OHT 18.‹#›