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Power output of a star
Stars emit massive amounts of energy per second and so the power of a star is
enormous. We assume that a star behaves as a perfectly ‘black body’ in other words it is
a perfect radiator of radiation at its surface temperature.
The Stefan-Boltzmann law states that the power emitted by a black body of surface area
A and with a surface temperature T (K) is given by the equation:
Power = AT4 where  is a constant (5.7x10-8 Wm-2K-4).
(Note: we are assuming here that the temperature of the surroundings (deep space) has a
temperature of 0 K)
If we assume that a star is roughly spherical then A = 4r2 for a star of radius r.
The power of a star is therefore 4r2T4 = 7.16x10-7r2T4.
Consider our Sun. It is a star of surface temperature 6000 K, and a radius 6.96x108 m.
Using the preceding equation we can calculate its power output:
Power output of the Sun
= 7.16x10-7r2T4 = 7.16x10-7x[6.96x108]2x[60004]
= 7.16x10-7x 4.84x1017x1.296x1015
= 4.5x1026 W
An alternative way of finding out the power output of the Sun is to use the solar constant.
(See: 16-19/Thermal physics/Transfer of heat/Text/Solar constant)
It is interesting to compare this power output with that of Canopus ( Carinae). Canopus
has a surface temperature of 7500 K and a radius of 2x1011 m. Using these figures it is
possible to calculate its power output as being about 9x1031 W, about 200 000 times
greater than that of the Sun!