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Instructor’s Copy Lab Worksheet: Ohmmmmm, Ohmmmmm Observations: Circuit Table 1: Lamps In Series and Parallel Dim or Bright Did lamp light when one bulb was loosened? One lamp Bright XXXXXXXXXXXXXXXXX Two lamps in series Dim No- other went out Two lamps in parallel Bright Yes – other lamp stayed lit One battery Table 2: Batteries In Series and Parallel Dim or Bright Did lamp light with one battery disconnected? XXXXXXXXXXXXXXXXX Dim Two batteries in series Bright No – light went out Two batteries in parallel Dim Yes – lamp stayed lit Circuit Potential Difference (experimental - volts) 6V Table 3: Ohm’s Law Current (amperes) Resistance (ohms) 2.5 2 Potential Difference (calculated – volts) 5.0 6V 1.2 5 6.0 6V .6 10 6.0 12V 1.2 10 12.0 CONCLUSIONS/RELATED QUESTIONS (2 points each) 1. Compare the light given off by two lamps connected in parallel to the light produced when they are connected in series. Two lamps connected in parallel are brighter. 2. Why is the amount of light different when the lamps are connected in parallel? Electricity only has to go through one lamp – less resistance. 3. What happened when you loosened one bulb in the series circuit? Both bulbs went out. 4. Explain why this happened. The circuit was opened and no electricity could get through. 5. What happened when you loosened one bulb in the parallel circuit? Only that bulb went out, the other one stayed lit. 6. Explain why this happened. There was still a complete path (through the other bulb). 7. A 9-volt battery (such as those used in radios) consists simply of six 1.5-volt batteries connected together. Are they connected in series or parallel? (Hint: check which battery setup on the front gave more power.) Series – bulbs were brighter in series – more “power”. 8. List one advantage of connecting batteries in series. Brighter bulbs. 9. List one advantage of connecting batteries in parallel. Backup battery source – bulb stayed lit. 10. List one advantage of connecting bulbs in parallel. Only the bulb loosened went out. 11. What is the difference between an open and a closed electric circuit? Open circuit – path is not complete, no electricity flows. Closed circuit – path is complete, electricity flows. 12. Why should you leave the switch open while all connections in a circuit are being made? So that you don’t risk damaging equipment or draining the battery. 13. In a series circuit, current must travel through all resistors. 14. Why are all appliances connected in parallel circuits in the home? So that everything doesn’t turn off or on at the same time. 15. Some Christmas lights are wired in a series circuit. If one bulb burns out, all bulbs turn off. 16. From Table 3, what happens to the current as the resistance is increased? Current decreases. 17. What happens to the potential difference when the resistance is increased? Potential difference remains unchanged. 18. What happens to the current as the potential difference is increased? It increases. 19. What happens to the resistance as the potential difference is increased? It remains unchanged. 20. How do you account for the difference in the experimental and the calculated potential difference? Friction, old resistors, ammeter not accurate, etc. 21. The relationship between current, potential difference, and resistance is called Ohm’s Law. It may be written as: Current = potential difference/resistance Current may be abbreviated as I, potential difference V, and resistance R. Substituting these symbols in the formula above gives I = V/R Now place the symbols I, V, and R correctly in the triangle below and use this triangle to solve the following problems. 22. Find the current when a 12 volt battery is connected through a resistance of 50 ohms. V = 12 volts I = V/R I = .24 amps R = 50 ohms I = 12 volts/50 ohms 23. Calculate the potential difference in a circuit if the resistance is 200 ohms and the current is 10 amperes. R = 200 ohms V = IR V = 2000 volts I = 10 amperes V = (200 ohms)(10 amperes) 24. If the current is 10 amperes and the voltage is 120 volts, what is the resistance? I = 10 amperes R = V/I R = 12 ohms V = 120 volts R = 120 volts/10 amperes 25. What is the voltage if the current is 35 amperes and the resistance is 20 ohms? I = 35 amperes V = IR V = 700 volts R = 20 ohms V = (35 amperes)(20 ohms)