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Find the Thévenin equivalent circuit at the terminals U, V. Note that we have dependent sources exclusively here. Therefore, we can’t use the lookback method to find Thévenin resistance. Since we have no independent sources, the circuit is purely resistive and Vt = 0. Finally, we must use an external circuit to activate our circuit to find Vr. This circuit is equivalent to a single resistor between U and V. Applying a 1V test voltage causes a current Irt through Rt. By Ohm’s law, the voltage is Rt * It. So the Thévenin ressitance is the reciprocal of Irt. Begin by applying a 1V source and arranging the current according to passive sign convention. So it should enter the terminal associated with the positive voltage. This means that Va is 1V, so our left dependent source is 2 V. We want the current that flows through this mesh, specifically current Ib. Write a KVL equation around the mesh. Gather like terms, gather constants on the right side, and solve for Ib. We get Ib = 52.6 mA. Ib becomes a known value. The current through the 20 Ω resistor is also known since it’s V / R by Ohm’s law. Irt must be the sum of those two currents by KCL. So Irt is 103 mA. So Rt is 1 / 103 mA, which is 9.74 Ω.

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