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Transcript
Math Rules
Factorisation:
For factorising a Quadratic Equation by Formula:
βˆ’(𝒃) ± √(𝒃)𝟐 βˆ’ πŸ’(𝒂)(𝒄)
𝑿=
𝟐(𝒂)
Trignometry:
Pythagoras Theorem:
π‘¨πŸ = π‘©πŸ + π‘ͺ𝟐
π‘©πŸ = π‘¨πŸ βˆ’ π‘ͺ𝟐
π‘ͺ𝟐 = π‘¨πŸ βˆ’ π‘©πŸ
B
A
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1
C
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Trignometry of a right angled Triangle:
π‘Άπ’‘π’‘π’π’”π’Šπ’•π’†
𝑺𝑢𝑯: π‘Ίπ’Šπ’πœ½ =
π‘―π’šπ’‘π’π’•π’†π’π’–π’”π’†
𝑨𝒅𝒋𝒂𝒄𝒆𝒏𝒕
π‘ͺ𝑨𝑯: π‘ͺπ’π’”πœ½ =
π‘―π’šπ’‘π’π’•π’†π’π’–π’”π’†
π‘Άπ’‘π’‘π’π’”π’Šπ’•π’†
𝑻𝑢𝑨: π‘»π’‚π’πœ½ =
𝑨𝒅𝒋𝒂𝒄𝒆𝒏𝒕
The Sine rule:
A,B & C are angles
A,b & c are sides
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𝒂
𝒃
𝒄
=
=
π‘Ίπ’Šπ’π‘¨ π‘Ίπ’Šπ’π’ƒ π‘Ίπ’Šπ’π‘ͺ
2
The Sine Rule is used when:
οƒ˜ You are given ONE SIDE and TWO ANGLES, to find the
missing side
οƒ˜ You are given TWO SIDES and ONE ANGLE which is not
between the two sides, to find the missing angle.
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Examples on Sine rule:
1) Find X:
πŸ“
𝑿
=
π‘Ίπ’Šπ’(πŸπŸ–) π‘Ίπ’Šπ’(𝟏𝟎𝟎)
πŸ“ × π‘Ίπ’Šπ’(𝟏𝟎𝟎)
𝑿=
π‘Ίπ’Šπ’(πŸπŸ–)
𝑿 = 𝟏𝟎. πŸ“π’„π’Ž
2) Find 𝜽:
𝟏𝟐. πŸ“
𝟏𝟎. πŸ“
=
π‘Ίπ’Šπ’πœ½ π‘Ίπ’Šπ’(πŸ‘πŸ)
π‘Ίπ’Šπ’(πŸ‘πŸ) × πŸπŸ. πŸ“
π‘Ίπ’Šπ’πœ½ =
𝟏𝟎. πŸ“
βˆ’πŸ
𝜽 = π‘Ίπ’Šπ’
π‘Ίπ’Šπ’(πŸ‘πŸ) × πŸπŸ. πŸ“
(
)
𝟏𝟎. πŸ“
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3
𝜽 = πŸ‘πŸ—. 𝟏°
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The Cosine Rule:
A,B & C are angles
A,b & c are sides
The Cosine Rule is used when:
οƒ˜ You are given TWO SIDES and ONE ANGLE which is
between the two sides, to get the side opposite to the
angle.
οƒ˜ You are given THREE SIDES, to find any angle.
π’‚πŸ = π’ƒπŸ + π’„πŸ βˆ’ 𝟐(𝒃)(𝒄)(π‘ͺπ’π’”πœ½)
𝒃 = π’‚πŸ + π’„πŸ βˆ’ 𝟐(𝒂)(𝒄)(π‘ͺπ’π’”πœ½)
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4
π’„πŸ = π’ƒπŸ + π’‚πŸ βˆ’ 𝟐(𝒃)(𝒂)(π‘ͺπ’π’”πœ½)
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Examples on the Cosine Rule:
1) Find X:
π‘ΏπŸ = πŸ–πŸ + 𝟏𝟐𝟐 βˆ’ 𝟐(πŸ–)(𝟏𝟐)(π‘ͺπ’π’”πŸπŸŽπŸŽ)
𝑿 = πŸπŸ’πŸŽ. πŸπŸ“
𝑿 = πŸπŸ“. πŸ“π’„π’Ž
2) Find 𝜽:
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5
πŸπŸ•πŸ = 𝟏𝟎𝟐 + 𝟏𝟐𝟐 βˆ’ 𝟐(𝟏𝟎)(𝟏𝟐)(π‘ͺπ’π’”πœ½)
πŸπŸ–πŸ— = πŸπŸ’πŸ’ βˆ’ πŸπŸ’πŸŽ(π‘ͺπ’π’”πœ½)
πŸπŸ–πŸ— + πŸπŸ’πŸŽ(π‘ͺπ’π’”πœ½) = πŸπŸ’πŸ’
πŸπŸ’πŸŽ(π‘ͺπ’π’”πœ½) = πŸπŸ’πŸ’ βˆ’ πŸπŸ–πŸ—
πŸπŸ’πŸŽ (π‘ͺπ’π’”πœ½) = βˆ’πŸ’πŸ“
βˆ’πŸ’πŸ“
π‘ͺπ’π’”πœ½ =
πŸπŸ’πŸŽ
βˆ’πŸ’πŸ“
𝜽 = π‘ͺπ’π’”βˆ’πŸ (
)
πŸπŸ’πŸŽ
𝜽 = 𝟏𝟎𝟎. πŸ–°
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Sine Rule of the Area of a triangle:
A,B & C are angles
A,b & c are sides
This Rule is used when:
οƒ˜ You are given TWO SIDES and ONE ANGLE which is
between the two sides.
𝟏
𝑨𝒓𝒆𝒂 = × π’ƒ × π’„ × π‘Ίπ’Šπ’π‘¨
𝟐
𝟏
𝑨𝒓𝒆𝒂 = × π’ƒ × π’‚ × π‘Ίπ’Šπ’π‘ͺ
𝟐
𝟏
𝑨𝒓𝒆𝒂 = × π’‚ × π’„ × π‘Ίπ’Šπ’π‘©
𝟐
Examples on the Sine Rule of Area:
Find the area of this shape:
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𝑨𝒓𝒆𝒂 = πŸπŸ–πŸ”πŸ”. πŸ‘πŸπ’ŽπŸ
6
𝟏
𝟏
𝑨𝒓𝒆𝒂 = ( × πŸπŸπŸŽ × πŸ’πŸŽ × π‘Ίπ’Šπ’(𝟏𝟐𝟎)) + ( × πŸπŸŽ × πŸ–πŸŽ × π‘Ίπ’Šπ’(𝟏𝟎𝟎))
𝟐
𝟐
Sine Curve Rule:
π‘Ίπ’Šπ’πœ½ = π‘Ίπ’Šπ’(πŸπŸ–πŸŽ βˆ’ 𝜽)
Examples:
π‘Ίπ’Šπ’πŸπŸŽπŸŽ = π‘Ίπ’Šπ’πŸ–πŸŽ
π‘Ίπ’Šπ’πŸ•πŸ’ = π‘Ίπ’Šπ’πŸπŸŽπŸ”
And so on…
Example on Sine Curve rule:
Calculate angle 𝜽 given that it is obtuse.
𝟏𝟐
𝟏𝟎
=
π‘Ίπ’Šπ’πœ½ π‘Ίπ’Šπ’πŸ’πŸŽ
π‘Ίπ’Šπ’πœ½ =
𝟏𝟐 × π’”π’Šπ’πŸ’πŸŽ
𝟏𝟎
𝟏𝟐 × π’”π’Šπ’πŸ’πŸŽ
𝜽 = π‘Ίπ’Šπ’βˆ’πŸ (
)
𝟏𝟎
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Back Bearing:
If the bearing of B from A is 𝜽, then the bearing of A from
B {Back Bearing} is:
𝜽 + πŸπŸ–πŸŽ°(π’Šπ’‡ 𝜽 π’Šπ’” 𝒍𝒆𝒔𝒔 𝒕𝒉𝒂𝒏 πŸπŸ–πŸŽ)
𝜽 βˆ’ πŸπŸ–πŸŽ°(π’Šπ’‡ 𝜽 π’Šπ’” π’Žπ’π’“π’† 𝒕𝒉𝒂𝒏 πŸπŸ–πŸŽ)
7
𝜽 = πŸ“πŸŽ. πŸ’πŸ• … ° which is obtuse. We have to find the other angle
which has the same sine.
πŸπŸ–πŸŽ βˆ’ πŸ“πŸŽ. πŸ’πŸ• … = πŸπŸπŸ—. πŸ“
Co-ordinate Geometry and straight lines:
To calculate the distance between two given points:
π‘«π’Šπ’”π’•π’‚π’π’„π’† = √(π‘ΏπŸ βˆ’ π‘ΏπŸ )𝟐 + (π’€πŸ βˆ’ π’€πŸ )𝟐
To calculate the Co-ordinates of the mid-point between
two given points:
π‘ΏπŸ + π‘ΏπŸ π’€πŸ + π’€πŸ
(
,
)
𝟐
𝟐
To calculate the gradient of a straight line:
we must have two points on the line (X1,Y1) and (X2,Y2)
the gradient (m) is:
π’€πŸ βˆ’ π’€πŸ
π’Ž=
𝑿 𝟐 βˆ’ π‘ΏπŸ
Matrices:
Multiplication of two Matrices |𝑴|:
π‘¨πŸ + π‘©πŸ‘ π‘¨πŸ + π‘©πŸ’
𝑨 𝑩 𝟏 𝟐
(
)(
)=(
)
π‘ͺ𝟏 + π‘«πŸ‘ π‘ͺ𝟐 + π‘«πŸ’
π‘ͺ 𝑫 πŸ‘ πŸ’
Determinant of a Matrix:
𝑨 𝑩
) β†’ |𝑴| = 𝑨𝑫 βˆ’ 𝑩π‘ͺ
π‘ͺ 𝑫
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𝑴=(
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Multiplicative Inverse of a Matrix (M-1):
𝑨
𝑴=(
π‘ͺ
𝟏
𝑩
𝑫 βˆ’π‘©
βˆ’πŸ
) β†’ |𝑴| = 𝑨𝑫 βˆ’ 𝑩π‘ͺ β†’ 𝑴 =
×(
)
|𝑴|
βˆ’π‘ͺ 𝑨
𝑫
NOTE: M x M-1 = Identity Martix
Any matrix multiplied by its multiplicative inverse will give you
𝟏 𝟎
the identity matrix which is:(
)
𝟎 𝟏
Variations:
Direct proportion equation:
𝒀 = 𝑲(𝑿)
Y and X are the two variables and K is the constant of
variation which you will be given information to find.
Indirect proportion equation:
𝑲
𝒀=
𝑿
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9
Polygons:
To calculate the sum of interior angles of a regular
polygon:
(𝒏 βˆ’ 𝟐) × πŸπŸ–πŸŽ
Where n is the number of sides in the polygon.
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To calculate one interior angle of a regular polygon:
(𝒏 βˆ’ 𝟐)πŸπŸ–πŸŽ
𝒏
To calculate the one exterior angle of a regular polygon:
πŸ‘πŸ”πŸŽ
𝒏
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Note: the sum of exterior angles of any polygon is always
360.
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