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LESSON 6: LAWS OF LOGARITHMS I
Learning Outcomes:
ļ‚·
To develop the laws of logarithms
ļ‚·
To determine an equivalent form of a logarithmic expression using the laws of
logarithms
Investigating the Laws of Logarithms
1. Show that log (1000 x 100) ā‰  (log 1000)(log 100).
2. Evaluate the following:
a. i. log 6 + log 5
ii. Log 30
b. i. log 7 + log 3
ii. Log 21
3. Based on the results in the previous section, suggest a possible law for log M + log N, where
M and N are positive numbers.
4. Use your conjecture to express log 1000 + log 100 as a single logarithm.
5. Show that š‘™š‘œš‘”
1000
100
ā‰ 
š‘™š‘œš‘”1000
š‘™š‘œš‘”100
.
6. Evaluate the following:
a. i. log 12
ii. log 48 ā€“ log 4
b. i. log 7
ii. log 35 ā€“ log 5
7. Based on the results in the previous section, suggest a possible law for log M - log N, where M
and N are positive numbers.
8. Use your conjecture to express log 1000 ā€“ log 100 as a single logarithm.
9. Show that log 10002 ā‰  (log 1000)2
10. Evaluate the following:
a. i. 3 log 5
ii. log 125
b. i. 4 log 2
ii. log 16
11. Based on the results in the previous section, suggest a possible law for Plog M, where M and
N are positive numbers.
12. Use your conjecture to express 2 log 1000 as a logarithm without a coefficient
13. The laws of common logarithms are also true for any logarithm with a base that is a positive
real number other than 1. Without technology, evaluate each of the following:
a. š‘™š‘œš‘”6 18 + š‘™š‘œš‘”6 2
b. š‘™š‘œš‘”2 40 āˆ’ š‘™š‘œš‘”2 5
c. 4š‘™š‘œš‘”9 3
Since logarithms are exponents, the laws of logarithms are related to the laws of powers
Product Law of Logarithms
š‘™š‘œš‘”š‘ š‘€š‘ = š‘™š‘œš‘”š‘ š‘€ + š‘™š‘œš‘”š‘ š‘
Proof:
Let š‘™š‘œš‘”š‘ š‘€ = š‘„ and š‘™š‘œš‘”š‘ š‘ = š‘¦.
Turn each equation into exponential form as š‘€ = š‘ š‘„ and š‘ = š‘ š‘¦ .
š‘€š‘ = (š‘ š‘„ )(š‘ š‘¦ )
š‘€š‘ = š‘ š‘„+š‘¦
Write in logarithmic form
š‘™š‘œš‘”š‘ š‘€š‘ = š‘„ + š‘¦
š‘™š‘œš‘”š‘ š‘€š‘ = š‘™š‘œš‘”š‘ š‘€ + š‘™š‘œš‘”š‘ š‘
Substitute for x and y
Quotient Law of Logarithms
š‘™š‘œš‘”š‘
š‘€
= š‘™š‘œš‘”š‘ š‘€ āˆ’ š‘™š‘œš‘”š‘ š‘
š‘
Proof
Let š‘™š‘œš‘”š‘ š‘€ = š‘„ and š‘™š‘œš‘”š‘ š‘ = š‘¦.
Turn each equation into exponential form as š‘€ = š‘ š‘„ and š‘ = š‘ š‘¦
š‘€ š‘š‘„
=
š‘ š‘š‘¦
š‘€
š‘
= š‘ š‘„āˆ’š‘¦
š‘€
š‘™š‘œš‘”š‘ š‘ = š‘„ āˆ’ š‘¦
Write in logarithmic form
š‘€
š‘™š‘œš‘”š‘ š‘ = š‘™š‘œš‘”š‘ š‘€ āˆ’ š‘™š‘œš‘”š‘ š‘
Substitute for x and y
Power Law of Logarithms
š‘™š‘œš‘”š‘ š‘€š‘ƒ = š‘ƒš‘™š‘œš‘”š‘ š‘€
Proof
Let š‘™š‘œš‘”š‘ š‘€ = š‘„, where M and c are positive real numbers with cā‰ 1.
Write the equation in exponential form as š‘€ = š‘ š‘„
Let P be a real number.
š‘€ = š‘š‘„
š‘€š‘ƒ = (š‘ š‘„ )š‘ƒ
Substitute in power law
(multiply by an exponent)
š‘€š‘ƒ = š‘ š‘„š‘ƒ
š‘™š‘œš‘”š‘ š‘€š‘ƒ = š‘„š‘ƒ
š‘™š‘œš‘”š‘ š‘€š‘ƒ = (š‘™š‘œš‘”š‘ š‘€)š‘ƒ
š‘™š‘œš‘”š‘ š‘€š‘ƒ = š‘ƒš‘™š‘œš‘”š‘ š‘€
Write in logarithmic form
Substitute for x and y
Ex. Write each expression in terms of individual logarithms of x, y and z.
š‘„
a. š‘™š‘œš‘”6 š‘¦
b. š‘™š‘œš‘”5 āˆšš‘„š‘¦
c. š‘™š‘œš‘”3 3
9
āˆšš‘„ 2
d. š‘™š‘œš‘”7
š‘„5š‘¦
āˆšš‘§
Assignment: pg. 400-403 #1-6