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Faculty Recruitment Material ATOMIC STRUCTURE The word atom is derived from the Greek word atom which means indivisible. The Greeks concluded that matter could be broken down into particles to small to be seen. These particles were called atoms. Dalton believed atom was a solid, indivisible, with different atoms for different elements. But 1 later many research works proved all atoms (except normal hydrogen 1H )are composed of three fundamental particles, namely electrons, protons and neutrons. Fundamental particles (a) Electron: The nature and existence of electron was established by experiments on conduction of electricity through gases, i.e., discovery of cathode rays. J.J. Thomson (1897) 8 determined specific charge (e/m) or the charge to mass ratio of the electron (-1.7588 x 10 coulomb/g) and proved that whatever gas be taken in the discharge tube (Discharge tube consists of a glass tube with metal electrodes fused in the walls), the value of e/m is always the same. From that he concluded that all atoms contained electrons. The name electron was given by Irish physicist, Stoney (b) Proton: A proton is a fundamental particle with a charge equal in magnitude but opposite in sign to the charge on the electron, and having a much larger mass. The nature and existence of proton was established by the discovery of Positive rays (Goldstein in 1886).e/m value of the anode rays is dependent on the nature of the gas taken in the discharge tube, i.e., positive particles are different in different gases. The specific charge (e/m) of the anode rays is found to be maximum when gas present in the discharge tube is Hydrogen. The name proton was given by Ruther ford. Neutron: It is sub-atomic particle, which carries no charge. Although the existence of neutrons was predicted in 1920, the prediction was verified by Chadwick in 1932. The characteristics of fundamental particles are given below. Particle Symbol Mass in amu or u Mass in kg. Charge esu Electron -1e0 0.000548 9.1091x10 –31 -4.803 x 10-10 1 in -1.602 x 10-19 Relative Charge -1 -27 +4.803x 10 +1.602 x 10 +1 –27 0 0 0 Proton +1P 1.00757 1.6725x10 Neutron 1 0n 1.00893 1.6748x10 -10 Charge in coulomb(C) -19 Note: The esu, an abbreviation for electrostatic unit, is the cgs unit of charge. coulomb is the MKS unit of charge. THOMSON’S ATOMIC MODEL: J.J Thomson concluded that all atoms contain electrons from his experiments on conduction of electricity through gases. He proposed that atoms were made up of electrons embedded in a uniform matrix of protons. The total positive charge was balanced by the ©Mathiit learning Pvt Ltd 1 Faculty Recruitment Material Atomic Structure total negative charge. If electrons were removed, the remaining ion was left with excess positive charge. This became known as Thomson’s Plum Pudding model (or watermelon model). The watermelon model was the accepted model for the structure of the atom until Ernest Rutherford’s alpha scattering experiments in 1911.However his model has no experimental evidence. RUTHERFORD’S ATOMIC MODEL: Rutherford (1911) bombarded a thin gold foil with α – particles. It was observed that (a) Most of the α – particles passed undeflected. (b) Very few α – particles underwent small and large deflections. (c) A very very few (1 out of 100,000) even returned on the original path. Based on these observations Rutherford proposed his model of atom. i) Atoms are spherical in shape and mostly hollow (ii) The central part of the atom is positively charged. It is massive and extremely small in size. This part is called the ‘nucleus’ of the atom. (iii) Electrons revolve around the nucleus, like planets around the sun Note: -12 The diameter of the nucleus is of the order of 10 -8 -13 to 10 cm. It is very small as -8 compared to the size of the atom( ≈ 10 cm) [ 1 x 10 cm = 1Å ] Drawbacks of Rutherford Model: 1. According to Classical laws of physics (or classical electrodynamics) a revolving electron should lose energy continuously and fall into the nucleus through a spiral path and the atom must be destroyed, however, the atom is stable. 2. If the electron loses energy continuously, the atomic spectra should consist of continuous bands. Experimentally, atomic spectra are made up of discrete spectral lines. ATOMIC NUMBER (Z): The number of protons or electrons in an atom is known as its atomic number. The atom as a whole is neutral in nature i, e., total negative charge contributed by electrons is equal to total positive charge contributed by protons, i, e., Number of electrons = Number of protons ©Mathiit learning Pvt Ltd 2 Faculty Recruitment Material Atomic Structure MASS NUMBER (A): Since electrons have negligible mass, the protons and neutrons are mass particles. The sum of number of protons and neutrons in the nucleus of an atom is termed mass number. General symbol for an atom of an element (E) indicating its mass number (A) and atomic number(Z) A ZE ; C Example : 6C12 A (mass number) = Z (Atomic number or Number of protons) + Number of neutrons A-Z = Number of neutrons Note: Mass number is always whole number but mass of proton or a neutron is not a whole number so atomic mass (or) weight is not necessarily a whole number. Atomic mass of an element is not equal to sum of masses of all the protons and neutrons simply. Most of the elements in nature exist as mixture of isotopes. For these elements atomic mass is calculated on the bases of their abundance in nature and atomic masses of individual members. Isotopes: Atoms of same element which have same atomic number but different mass numbers are called isotopes Example: Cl atomic weight is 35.5 due to existence of Cl 35 and Cl 37 , which are present in the ratio of 3:1 in nature Most of our information about the arrangement of electrons in atoms has come from studies of the interaction of matter with light. To understand the nature of these interactions, we shall consider electromagnetic radiations. ELECTROMAGNETIC RADIATIONS The theory of electromagnetic radiations(classical electromagnetism or classical electrodynamics) was developed by James Clerk Maxwell. Electromagnetic radiations are usually treated as wave motions. The electronic and magnetic fields oscillate in directions perpendicular to each other and to the direction of motion of the wave. These waves travel as a continuous sequence of alternating crests and troughs Ordinary light rays, X-rays,γ-rays are some examples of electromagnetic radiations. All types of electromagnetic radiations travel through space with the same velocity i.e. 3 x 1010 cm sec –1 8 –1 or 3 x 10 m sec . There are three fundamental characteristics associated with wave motion. They are i) wavelength (λ) ii) frequency (v) and iii) velocity (c) ©Mathiit learning Pvt Ltd 3 Faculty Recruitment Material Atomic Structure Wavelength. The distance between two consecutive crests or troughs is known as wavelength denoted by λ. Frequency: The number of waves that pass through a given point in 1 second is called its frequency (number of waves per sec) denoted by v. Velocity: The distance traveled by wave in 1 second is its velocity c Velocity= frequency X wavelength c=v λ Electromagnetic spectrum The arrangement of the various types of electromagnetic radiations in order of their increasing(or decreasing)wavelengths or(frequencies)is known as electromagnetic spectrum. Wavelength increases → Cosmic rays γ - rays X-rays UV-rays visible infrared(IR) Micro waves Radio waves Frequency decreases → SPECTRA OR SPECTRUMS Spectrum is the impression produced on a photographic film when the radiations of particular wavelengths are analysed with a spectroscope (a device in which a beam of light is passed through a prism and received on a photograph). It is broadly of two types. Emission spectrum. Spectrum produced by emitted radiation is known as emission spectrum. it is again of two types. i) Continuous spectrum: The spectrum consists of continuous bands of radiations corresponding to different wavelengths. Example: solar spectrum. [Spectrum of sunlight] ii) Line or atomic spectrum: The spectrum consists of a series of sharp lines; each line corresponds to a particular wavelength. Example; if an electric discharge is passed through hydrogen gas taken in a discharge tube under low pressure, the bright light is emitted and the emitted radiation is analysed with spectroscope. It is found to consist of a series of sharp lines called hydrogen emission spectrum Absorption spectrum. Spectrum produced by the absorbed radiations is called absorption spectrum. QUANTUM THEORY Quantum theory is a fundamental branch of theoretical physics that replaces classical electromagnetism at the atomic and subatomic levels. The discovery(Max planck,1901) that waves could be measured in particle-like small packets of energy called quanta and frequency of radiation(v) is directly proportional to energy of radiation(E) (E=hv where h is called planck’s constant) led to the branch of physics that deals with atomic and subatomic systems which we today call Quantum theory. The foundations of quantum theory were established during the first half of the 20th century by Max Planck, Albert Einstein, Niels Bohr, Werner Heisenberg, Erwin Schrödinger, Max Born, John von Neumann, Paul Dirac, Wolfgang Pauli and others. Some fundamental aspects of the theory are still actively studied ©Mathiit learning Pvt Ltd 4 Faculty Recruitment Material Atomic Structure BOHR’S ATOMIC MODEL Bohr’s atomic model is based on quantum theory of radiation and the classical laws of physics. The important points of Bohr model are: (i) Electrons revolve around the nucleus in closed circular paths called orbits or shells. As long as the electron stays in a given orbit it does not radiate energy. Therefore these orbits called “stationary orbits or stationary shells”. (ii) Each stationary orbit is associated with definite amount of energy. These orbits are designated by K, L, M, N, O-------from the nucleus. The orbit close to nucleus has less energy compared to the orbit away from the nucleus. (iii) Energy is emitted in the form of radiation when an electron jumps from outer orbit to inner orbit. Energy is absorbed when electron jumps from lower orbit to higher orbit Ehigher - Elower =hv Where h is Planck’s constant and v is the frequency of radiation. (iv) The angular momentum of the revolving electron is an integral multiple of momentum of the electron is quantized] i, e., mvr = n h 1 – where, n is integer (n =1,2,3,4…………) + m = mass of the electron Electron in its most stable ‘ground state’ orbit, i.e. principal quantum number 1 v = velocity of the electron r = radius of the circular orbit h = Planck’s constant Advantages of Bohr’s theory : Bohr successfully calculated the radii and energies of various orbits of hydrogen 2 2 n h __ 4π2mZe2 r = 0.529 x 10-8 x n2 cm For hydrogen atom, 2 = 0.529 x n Å rn = r1 x n2 Å or /2π, [Angular 3 etc 2 2π Radius of an orbit = h + 2+ 3+ and for hydrogen-like mono electron species such as He ,Li , Be 2 rn = 0.529 x n Å Z Where Z = Atomic number of the species. 2 4 - 2 π me Energy of an electron in the nth orbit = n2h2 For hydrogen atom -19 En = -21.79 x 10 J per atom 2 n ©Mathiit learning Pvt Ltd 5 Faculty Recruitment Material Atomic Structure = -13.6 eV per atom 2 n = -313.6 kcal per mole n2 2 2 and En = energy of hydrogen first orbit x Z /n for Hydrogen – like mono electron species such as + 2+ He , Li and Be3+. Bohr’s model explains the stability of the atom. The frequencies of spectral lines calculated from Bohr’s equation are in close agreement with the frequencies observed experimentally in hydrogen spectrum. The spectrum of hydrogen-like ions can also be explained. Defects of Bohr’s theory: (i) It fails to explain the spectra of multi – electron atoms. (ii) It fails to explain fine spectrum (spectral lines consist of several closely packed lines) of hydrogen. (iii) It does not provide an explanation why angular momentum of the electron should always be an integral multiple of h/2 π. (iv) It does not explain splitting of spectral lines into a group of finer lines under the influence of magnetic field (Zeeman effect) and electric field (stark effect). MODERN THEORY OF ATOMIC STRUCTURE Louis de Broglie proposed the particle and wave nature (dual nature) of the electron. Based on the dual nature of the electron, the quantization of its angular momentum is explained. According to the uncertainity principle proposed by Heisenberg it is impossible to trace path (orbit) traversed by an electron, the only possibility is maximum probability or relative chance of finding electron in space around the nucleus(orbital). Erwin Schrodinger proposed the wave equation for the electron. From the Schrodinger Wave Equation the basic information about quantum numbers and overall electron behavior have been derived. Atomic orbital is the space around the nucleus in which relative chance (probability) of finding electron is maximum (95%). QUANTUM NUMBERS : Quantum numbers are used to locate a particular electron in an atom and there are four types of quantum number which give a complete picture of an electron. Principal Quantum Number It was proposed by Bohr, denoted by n. It will have any integer value except zero. It gives the size of the orbit and energy of the orbit. As the value of n is increasing the size and energy of the orbit increases. The number of electrons that can present in an orbit is equal to 2n2. ©Mathiit learning Pvt Ltd 6 Faculty Recruitment Material Atomic Structure Azimuthal Quantum Number To explain fine spectrum of hydrogen Sommerfeld introduced the idea of elliptical orbits. The angular momentum of the electron in an elliptical path is quantised mvr=k h/2π, where k is Sommerfeld’s integer called azimuthal quantum number. K= 1,2,3,4…………….n. Bohr quantized the size of the orbit (major axis of the path) and Sommerfeld quantised the shape of the orbit (minor axis) Both the principal quantum number n and azimuthal quantum number k are related to the ellipse by n/k= length of the major axis/length of the minor axis. Sommerfeld proposed that, for a given n value, a set of k values1 to n, are possible means for a given stationary orbit or shell a set of “sub- orbits” or “sub-shells” are present. Minor axis Major axis Note: From quantum mechanics it was found that the azimuthal quantum number can take up values starting from 0 to n-1 but not 1 to n and azimuthal quantum number is represented by ‘l’ instead of k. Azimuthal quantum number gives information regarding the shape of sub orbit or subshell and the number of subshells in a shell. It can have values from 0 to (n-1), i, e., l = 0 (s- subshell), l = 1 (p-subshell), l = 2(d-subshell), l = 3(f-subshell). (i) Magnetic quantum number (m): proposed by Lande to explain Zeeman effect and stark effect.It describes the orientations of the subshells. It can have values from –l to +l including zero, i, e., total (2l+1) values. Each value corresponds to an orbital. a) For l = 0 (s sub – shell) , m = value is 0. Hence there is only one orientation for the s sub – shell. b) For l = 1 (p sub – shell), m = values are 0,-1 and +1. Hence three orientations are possible for the p sub – shell. The three corresponding orbitals are written as px, py and pz. For l = 2 (i.e. d sub – shell), m = values are –2, -1, 0, +1 and +2. Hence d sub – shell can have five different orientations, and orbitals corresponding to these are dxy, dyz, dzx, d x2-y2 dz2 ©Mathiit learning Pvt Ltd 7 Faculty Recruitment Material Atomic Structure Spin Quantum Number It was proposed by Uhlenbeck and Goudsmit. It is denoted by 's'. Electron moving in an orbital can spin on its own axis. The spin of the electron may be clockwise or anti clock wise. The clockwise spin is denoted by +1/2 or and anticlockwise spin is denoted by –1/2 or . Shapes of atomic orbitals S-orbital ©Mathiit learning Pvt Ltd 8 Faculty Recruitment Material Atomic Structure Various Shells, sub-shells and their quantum numbers Principal energy level (n) 1 Total number of sub energy levels and their azimuthal quantum numbers or designation (l) The number of orbitals per sub – level and their magnetic quantum numbers (m) One [0 or 1s] Number of orbitals per energy sublevel (per energy level, 2 n ). One (0) 1] (1) 0 or 2s 1 or 2p One(0) Three (-1, 0,+1) 1 0 or 3s 1 or 3p 2 or 3d One (0) 1 Three (-1, 0,+1) 3 Five (-2, -1, 0, +1, +2) 5 2 Two 3 (4) 3 Three (9) 4 Four 0 or 4s 1 or 4p 2 or 4d 3 or 4f 1 One (0) 3 Three (-1, 0, +1) 5 Five (-2, -1, 0, +1,+2) 7 (16) Seven (-3, -2, -1, 0, +1, +2, +3) ELECTRONIC CONFIGURATION OF ATOMS. Electronic configurations are written in nlx method where n is the principal quantum number, l is the azimuthal quantum number and x is the number of electrons present in it .To describe the arrangement and distribution of electrons, following selective principles are required. Pauli’s Exlusion Principle: No two electrons in an atom can have all four quantum numbers same: e.g correct for ns2 e.g incorrect for ns 2 Following results can be inferred from Pauli’s exclusion principle. ©Mathiit learning Pvt Ltd 9 Faculty Recruitment Material Atomic Structure 2 a). Maximum number of electrons in an orbit can be 2n b). Maximum number of electrons in a sub-shell can be 2, 6, 10, 14 in s, p, d, f respectively. c). Maximum number of electrons in an orbital is 2 only. Aufbau Principle: Aufbau is a German word meaning building up. This gives us a sequence in which various subshells are filled up depending on the relative order of the energy of orbitals. “Electrons are added progressively to the various orbitals in the order of increasing energy starting with the orbital of lowest energy” (n + l) rule: a. The orbital with lower values of (n + 1) possesses lower energy relative and should be filled first. 1s2 2s2 2p6 3s2 3p6 3d1 e.g 19K 2 2 6 2 6 1s 2s 2p 3s 3p wrong 1 4s correct n + 1 of 4s = 4 + 0 = 4 n + 1 of 3d = 3 + 2 = 5 b. If (n + 1) is same for two orbitals the orbital with lower values of ‘n’ possess and should be filled first. e.g 21Sc 1s2 2s2 2p6 3s2 3p6 4s2 4p1 2 2 6 2 6 2 1 1s 2s 2p 3s 3p 4s 3d lower energy wrong correct n + 1 of 4p = 4 + 1 = 5 n + 1 of 3d = 3 + 2 = 5 Thus, 3d should be filled first ‘n’ of 3d < ‘n’ of 4p A sub-shell having nearly full filled or nearly half filled configuration tends to acquire exactly full filled or exactly half filled nature in order to attain stability Example L e.g 24Cr [Ar] 3d4 4s2 wrong 1 5 9 2 [Ar] 4s 3d e. g 29Cu [Ar] 3d 4s 1 10 [Ar] 4s 3d e. g 46Pd 9 2 [Kr] 4d 5s 1 10 [Kr] 5s 4d Correct wrong Correct wrong Correct Note: Most of the exceptions to the electron configuration predicted from the aufbau principle occur among elements with atomic numbers larger than 40 Ground state and Excited state of atom: when all the electrons present in atom are in the lowest possible energy states, it is called as ground state of atom. When the electrons jump from a lower shell to higher, it comes in a higher energy state and is said to be in excited state. Hund’s Rule: In an atom electron pairing takes place only, after all the available degenerate orbitals are half-filled with electrons of parallel spin. ©Mathiit learning Pvt Ltd 10 Faculty Recruitment Material Atomic Structure WORKED EXAMPLES 1. An oil drop has 6.39 x 10-19 C charge. Find out the number of electrons in this drop. -19 charge on oil drop = 6.39 x 10 -19 1.602 x 10 . C now we know that C is charge on one electron -19 . . 6.39 x 10 -19 C will be charge on = 6 .39 x 10 -19 1.602 x 10 = 4 electrons 2. (a) Write the electronic configuration of elements with atomic numbers 19, 28 and 29. (b) Calculate the atomic number and name the element that corresponds to each of the following electronic configuration. 2 2 6 2 6 1 (i) 1s 2s 2p 3s 3p 4s (ii) 1s2 2s2 2p6 3s2 3p6 4s1 3d5 (iii) 1s2 2s2 2p6 3s2 3p6 4s1 3d10 (a) Electronic configuration of elements with atomic number 19 1s2 2s2 2p6 3s2 3p6 4s1 28 1s2 2s2 2p6 3s2 3p6 4s2 3d8 29 1s2 2s22p6 3s2 3p6 4s1 3d10 (b) (i) Atomic number of the element is 2 + 2 + 6 + 2 + 6 + 1 = 19 Therefore, the element is potassium. (ii) Atomic number of the element is 2 + 2 + 6 + 2 + 6 +5 + 1= 24 Therefore, the element is chromium. (iii) Atomic number of element is 2 + 2 + 6 + 2 + 6 +10 + 1 = 29 Therefore, the element is copper. 3. (a) An electron is in a 4f orbital. What possible values for the quantum numbers n, l,m and can it have? (b) What designation is given to an orbital having (i) n = 2, l = 1 and (ii) n = 4, l = 0? (a) For an electron in a 4f orbital, n = 4, l = 3, m = -3, -2, –1, 0, 1, +2, +3, s = +1/2 and –1/2 for each value of m. (b) For an orbital having n = 2, l = 1 designation is 2p. For an orbital having n = 4, l = 0 designation is 4s. 4. A neutral atom has 2K, 8L, 5M electrons. Find out the following from the data: a) atomic number (b) total number of s electrons (c) total number of p electrons (d) number of protons in the nucleus. (a) Atomic number = Number of protons = Number of electrons Total number of electrons = 2 + 8 + 5 = 15 Hence atomic number = 15 ©Mathiit learning Pvt Ltd 11 Faculty Recruitment Material Atomic Structure (b) Total number of s electrons. To find out it, we are to write electronic configuration of Atomic number = 15. 1s2 2s2 2p6 3s2 3p3 Total number of s electrons = 6 (c) Total number of p electrons = 9 (d) Number of protons in the nucleus = Number of electrons number of protons = 15 5. Why chlorine has fractional atomic weight? 35 The fractional atomic weight (35.5) of chlorine is due to the fact that in the ordinary chlorine Cl 37 and Cl isotopes are present in the ratio of 3:1 Average atomic weight of Cl = 3 x 35 + 1 x 37 4 = 35.5 amu. (approximately) 6. When α- particles are sent through a thin metal foil, very few α- particles returned on the original path explain. The whole of the atomic mass is concentrated in the nucleus i.e. the central nucleus is rigid and hence α- particles which strike on it are returned to the original path. 7. An element has two naturally occurring isotopes of atomic masses 63 and 65 its atomic weight is 63.55. Find out the percentage abundances for two isotopes? Let the percentage abundance of the isotope of mass 63 be x. Therefore, the percentage abundance of the other isotope is 100 – x. Thus we have 63 x x+ 65 (100 – x ) = 63.55 100 63x + 6500 – 65x = 6355 x = 72. 5 Thus, the percentage abundance of the isotope of atomic mass 63 is 72.5% and the percentage abundance of the isotope of atomic mass 65 is 27.5 % . 8. Calculate the radius of the 4th Bohr’s orbit in hydrogen atom? From Bohr’s theory rn = 0.529 x n2 Å Given n = 4 9. 2 = 0.529 x 4 Å = 8.464 Å According to Sommerfeld how many elliptical orbits are possible for the fourth orbit electron. Given electron is present in 4th orbit n=4 ©Mathiit learning Pvt Ltd 12 Faculty Recruitment Material Atomic Structure For given ‘n’ k values are k = 1 --------- n n = 4 , k = 1,2,3,4 n length of major axis We know = k length of minor axis if n = 4,k = 4 i.e, length of major axis = length of minor axis then electron path is circular. In remaining cases for n = 4, k = 1, n = 4 k = 2 & n = 4 k = 3 path of the electron is elliptical Total 3 elliptical paths are possible for the given electron. 10. The first excited state refers to the electronic configuration with energy closest to but higher than that of ground state. Write electronic configurations of the first excited state of the following (a) C (b) Ne (c) Li For carbon z is 6 Ground state 1s2 2s2 2p2 First excited state 1s2 2s1 2p3 For Neon z is 10 Ground state 1s2 2s2 2p6 First excited state 1s2 2s2 2p5 3s1 For Lithium z is 3 Ground state 1s2 2s1 First excited state 1s1 2s2 11. a) What values are permitted for the orbital Azimuthal quantum number l for an electron with principal quantum number n =3? b) How many different values for the magnetic quantum number are possible for an electron with Azimuthal quantum number l = 3? c) How many electrons can be placed in each of the following subshells: s, p, d, f ? d) What is the lowest shell, which has an f subshell? a) 2,1,0 b) seven (-3, -2, -1, 0, +1, +2, +3) c) s: 2, p:6, d:10 ,f: 14. d) Fourth 12. Which shell would be the first to have a g subshell? Since the azimuthal quantum number l must be less than the principal quantum number, n, and since the g subshell designation represents an l value of 4, the minimum n value possible is 5. In literal notation (K, L, M, N, O) the fifth shell is designed the O shell. ©Mathiit learning Pvt Ltd 13 Faculty Recruitment Material Atomic Structure LEVEL – I 1. 2. The two electron occupying the same orbital are distinguished by: a) principal quantum number b) azimuthal quantum number c) magnetic quantum number d) spin quantum number Filling 3d completely for copper, the next electron enters in a) 4p – orbital 3. b) 3d – orbital b) 1 and 2 th c) 4.77 Å d) 2.12 Å th b) 1: 4: 9 c) 1: 4: 6 d) 1: 2: 3 th According to Bohr’s theory, the angular momentum for an electron of 5 orbit is: b) 2.5h/ c) 5/h d) 25h/ The maximum number of electrons in a subshell is given by the Expression: a) 4l + 2 8. d) 6 and 1 The ratio of radii of 2 , 4 and 6 orbits of hydrogen atom is: a) 5h/ 7. b) 1.06 Å nd a) 2: 4: 6 6. c) 2 and 0 The Bohr orbit radius for the hydrogen atom (n = 1) is approximately 0.530 Å. The radius for the first excited state (n = 2) orbit is: a) 0.13 Å 5. d) 4d – orbital For the sixth electron the values of principal and orbital quantum numbers are respectively a) 2 and 1 4. c) 4s – orbital b) 4l – 2 c) 2l + 1 d) 2n2 The combination of quantum numbers that are allowed for an electron in an atom is a) n = 2, l = 2, m = 1, s = 1/2 b) n = 3, l = 1, m = 1, s = ½ c) n = 5, l = 1, m = 2, s = ½ d) n = 4, l = -1, m = 0, s = ½ 9. Four electrons were shown with a set of quantum numbers each. Which set of quantum number show an electron with highest energy? 10. a) . n = 3, l = 2, m = +1, s = +1/2 b) n = 4, l = 1, m = 0, s = -1/2 c) n = 4, l = 2, m = -1, s = +1/2 d) n = 5, l = 0, m = 0, s = -1/2 The highest value of e/m of anode rays has been observed when the discharge tube is filled with: a) Nitrogen 11. d) helium b) –4.5eV c) –6.8 e V d) +6.8 e V Which of the following properties of an element is a whole number? a) atomic mass 13. c) hydrogen The energy of an electron in the first Bohr orbit of H atom is –13.6 eV. The possible energy values (s) of the excited state (s) for electron is Bohr orbits of hydrogen is (are) : a) –3.4 e V 12. b) oxygen b) atomic number c) atomic radii d) atomic volume 7 If the nitrogen atom had electronic configuration 1s , it would have energy lower than that of the 2 2 3 normal ground state configuration 1s 2s 2p , because the electrons would be closer to the nucleus, yet 1s7 is not observed because it violates a) Heisenberg uncertainty principal b) Hund’s rule c) Pauli exclusion principle d) Bohr postulate of stationary orbit ©Mathiit learning Pvt Ltd 14 Faculty Recruitment Material 14. For a particular value of azimuthal quantum number (1), the total number of magnetic quantum number (m) is given by s. (SAT, 1998) a) l = (m+1)/2 15. Atomic Structure b) l = (2m+1)/2 c) l = (m – 1)/2 d) m = (2l –1)/2 Two electrons A and B in an atom have the following set of quantum numbers : A : 3, 2, –2, +1/2 B : 3, 0, 0, +1/2 Which statement is correct for A and B ? a) A and B have same energy c) B has more energy than A 16. As we move away from the nucleus, the difference between the adjacent energy levels a) Increases 17. b) Remains constant c) Decreases d) None of these Existence of fundamental particles violates : a) Dalton’s atomic theory c) Mendeleef’s theory 18. b) A has more energy than B d) A and B represents same electron b) be Broglie’s theory d) Newland’s theory Which statement does not form part of Bohr’s model of the hydrogen atom ? a) Energy of the electrons in the orbit is quantized b) The electron in the orbit nearest the nucleus is in the lowest energy c) Electrons revolve in different obits around the nucleus d) The position and velocity of the electrons in the orbit cannot be determined simultaneously 19. The ratio of specific charge (e/m) of an electron to that of a hydrogen ion is a) 1 : 1 20. b) 1840 : 1 c) 1 : 1840 d) 2 : 1 The specific charge for positive rays is much less than the specific charge for cathode rays. This is because a) Positive rays are positively charged b) Charge on positive rays is less c) Positive rays comprise ionised atoms whose mass is much higher d) Experimental method for determination is wrong 21. The configuration 1s2, 2s2 2p5, 3s1 shows a) Ground state of fluorine c) Excited state of neon atom 22. Which are isoelectronic with each other? a) Na+ and Ne 23. b) K+ and O c) Ne and O d) Na+ and K+ Which atom has as many as s-electron as p-electrons? a) H 24. b) Excited state of fluorine d) Excited state of O2– ion b) Mg c) N d) Na The number f orbitals that could be associated with a principal quantum number are a) n2 b) 2n2 c) n2 + 2 ©Mathiit learning Pvt Ltd d) n2 – 2 15 Faculty Recruitment Material 25. The atomic weight of an element is 23 and atomic number is 11. The number of protons, electrons and neutrons respectively present in the atom of the elements are a) 11, 11, 12 26. b) 12, 12, 11 b) 1 4 c) 4 3 b) 18 d) 3 2 c) 12 d) 20 The ratio of radius of III and IV Bohr’s orbits in hydrogen atom is a) 3 : 4 29. d) 12, 11, 12 Maximum number of electrons which can be accommodated in a g sub-shell is a) 14 28. c) 11, 12, 11 Which transition of electron in the hydrogen atom emits maximum energy? a) 2 1 27. Atomic Structure b) 3 : 8 c) 9 : 16 2 2 6 1 d) 8 : 9 1 The electronic configuration 1s , 2s 2p , 3s , 3p correctly describes : a) Ground state of Na b) Ground state of Si + c) Excited state of Mgd) Excited state of Al3+ 30. Which represent the correct set up of the four quantum numbers of 4s-electron? a) 4, 3, 2, +1/2 31. b) 4, 2, 1, 0 b) 4p c) 5g b) – 5.40 eV c) – 0.85 eV d) – 2.72 eV An electron has a spin quantum number + ½ and a magnetic quantum number – 1. It can not be present in a) d – orbital 35. b) n = 2, l = 1, m = 1 d) n = 3, l = 0, m ,= 0 The energy of hydrogen atom in its ground states is – 13.6eV. The energy of the level corresponding to the to the quantum number n = 5 is a) – 0.54 eV 34. d) 4d The correct set of quantum numbers for the unpaired electron of chlorine atom is a) n = 2, l = 1, m = 0 c) n = 3, l = 1 , m = 1 33. d) 4, 0, 0, 1/2 The atomic orbital not allowed in quantum theory is a) 3f 32. c) 4, 3, –2, +1/2 b) f – orbital c) p – orbital d) s – orbital Assertion A: The angular momentum of an electron in an atom is quantized. Reason R: In an atom only those orbits are permitted in which angular momentum of the electron is whole number multiple of h/2π. 1. Both A and R are true and R is the correct explanation of A 2. Both A and R are true and R is not the correct explanation of A 3. A is true R is false 4) A is true R is false 36. Ground state electronic configuration of nitrogen atom can be represented by a) b) ©Mathiit learning Pvt Ltd 16 Faculty Recruitment Material Atomic Structure c) d) 37. Which of the following electronic configuration is against to Pauli’s exclusion principle & Aufbau principle a) b) c) d) 38. Which of the following electronic configuration is against to Aufbau & Hund’s rule a) b) c) d) LEVEL – II 2+ 4+ 1. Write down the electronic configuration of Cr present? and Mn . How many unpaired electrons are 2. An element X has two isotopes of atomic masses 16 and 18. Its overall atomic weight is 6.4. The proportion of the isotope 16 in X ? 3. Which transitions among the adjacent orbits in hydrogen spectrum show larger difference in energy? ©Mathiit learning Pvt Ltd 17 Faculty Recruitment Material Atomic Structure 4. What values are assigned to quantum numbers n, l and m for (i) 2s orbital (ii) 2p orbital (iii) 4d orbital 5. Fourth shell (n = 4) may contain upto 32 electrons. Explain this fact with the help of quantum numbers. 6. Bohr’s atomic model is superior than the Rutherford’s atomic model, explain, 1997) 7. What do you expect in between two electronic orbits of an atom? 8. Differentiate orbit and orbital. (SAT, 2000) (SAT, KEY TO LEVEL – I 1–D 2–C 3–A 4–D 5–B 6–B 7–A 8–B 9–C 10 – C 11 – A 12 – B 13 – C 14 – C 15 – B 16– C 17 – A 18 – D 19 – B 20 – C 21 – C 22 – A 23 – B 24– A 25 – A 26 – A 27 – B 28 – C 29 – C 30 – D 31 – A 32 –C 33 – A 34 – D 35 – A 36 – A 37 – B 38 – B. WORK SHEET th 1. Calculate the 10 Bohr’s orbit in hydrogen atom? Give the formula of rn ? 2. What are quantum numbers and explain it? 3. Differentiate orbit and orbital? 4. Calculate the wave number corresponding to the following wane lengths? 5. Cal. The frequency and energy of a photan, wave length is 6200A0 (Plank’s constant h 6.625 1027 ) 6. What is the relation between velocity, frewney and wave length? 7. Cal. the frewney of a radiation whose wave length is 2000A 8. What is the ratio between energies of two radiations whose wave lengths are 6000A0 and 0 2000A ? 9. Write electronic configaration of cu? 10. Write electronic configaration of cromivm? 11. A liquid drop has 6 10 12. What is 180 topes and give example of hydrogen and also names of hydrogen? 13. Carbon occurs in nature of c 40 0 c charge find out the number of electrons in this drop? 12 12 percentatage abundance of c 13 and c the average atomic mass of ‘c’ is 13.022. what is 13 and c in nature? 14. The atomic weight of an element 3 and atomic number is 1. the number of protons, electrons neutrons are ------------------------------- 15. What is the mass of 1 mole of electrons? ©Mathiit learning Pvt Ltd 18