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DG7 --- 10 minutes Accel Math III Unit #1: Data Analysis Lesson #10: Calculating Mean, Variance, and Standard Deviation for a Binomial Distribution EQ: How do you calculate mean, variance, and standard deviation of a binomial distribution? How are these used to interpret the data? Recall: Create a probability distribution where the random variable of interest is number of heads occurring when tossing 4 coins. X = number of heads when tossing 4 coins HINT: You can, but you don’t have to create a sample space to complete this task. Work smarter, not harder!! How could you use Lists and binomialpdf to find each value of P(xi) ? 0 0.0625 1 0.25 2 0.375 3 4 0.25 0.0625 Find the expected value for this task. 0(0.0625) + 1(0.25) +2(0.375)+3(0.25) +4(0.0625) E(X) = __________________________ =2 Now calculate (n)(p) ______________ (4)(0.5) = 2 WOW!! **Formula: Mean of a Binomial Distribution (n)(p) µ = __________________ Find the variance for this task. σ2 2(0.0625) + (1 – 2)2(0.25) + (2 – 2)2(0.375) (0 – 2) = ____________________________ + (3 – 2)2(0.25) + (4 – 2)2(0.0625) = 1 (4)(.5)(.5) = 1 Now calculate (n)(p)(q) ______________ WOW!! **Formula: Variance of a Binomial Distribution σ2 (n)(p)(q) = ____________________________ Find the standard deviation for this task. 1 1 σ = _____________________ ( 4)(.5)(.5) 1 **Formula: Standard Deviation of a Binomial Distribution n p q σ = _____________________ Ex 1. A die is rolled 480 times. Find the mean, variance, and standard deviation of the number of 2’s that will be rolled. X = # of twos occurring on 480 rolls of a die Would thistobe a BINOMIAL DISTRIBUTION a this!! I DO NOT want create a probability distributionorfor NORMAL DISTRIBUTION? WHY? WHY? µ (n)(p) = (480)(1/6) = 80 = __________________ σ2 (n)(p)(q) = (480)(1/6)(5/6) = 66.67 = ________________ σ 1 5 n p q 480 8.2 = _____________________ 6 6 Ex 2. The Statistical Bulletin published by Metropolitan Life Insurance Co. reported that 2% of all American births result in twins. If a random sample of 8000 births is taken, find the mean, variance, and standard deviation of the number of births that would result in twins. this be a BINOMIAL DISTRIBUTION X =Would # of twin births occurring 8000 birthsor a NORMAL DISTRIBUTION? WHY? µ = __________________ (n)(p) = (8000)(0.02) = 160 σ2 (n)(p)(q) = (8000)(0.02)(0.98) = 156.8 = ________________ σ n p q 80000.020.98 12.5 = _____________________ Get out a sheet of paper to use for Ex 3. Answer #6 & #7 first. 6. a. b. c. d. Criteria needed to be Binomial Distribution: Fixed # of trials n = 10 restaurants Success --- unsatisfactory Failure --- satisfactory Condition of one restaurant independent of others p = 3/7 remains the same from restaurant to restaurant Yes, this scenario meets the criteria for a binomial distribution. 7. NO, binomial distribution simply means there are only two outcomes, NOT the probabilities are 50% and 50%. Now finish #1 - #5 on your own. 3 1. P( X 3)10 C3 7 3 7 4 0.1879 7 4 6 5 5 3 4 3 4 2. P( X 4) P( X 5)10 C4 10 C5 0.4686 7 7 7 7 3. P( X 1) P( X 1) P( X 2) ... P( X 10) or P( X 1) 1 P( X 0) 3 4." most likely" E ( X ) (10) 4.3 7 Only because it’s a Binomial Distribution 3 4 5. " variable" (10) 2.44897 Only because it’s a 7 7 2 or 3 4 7 7 (10) 1.5649 Binomial Distribution Assignment: Practice Worksheet: Calculating Mean, Variance, and Standard Deviation of Binomial Distributions DG8 --- Tues