* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
Download 6.1 Moles and Molar Masses
History of chemistry wikipedia , lookup
Chemistry: A Volatile History wikipedia , lookup
Biochemistry wikipedia , lookup
Computational chemistry wikipedia , lookup
Electrolysis of water wikipedia , lookup
Chemical bond wikipedia , lookup
Debye–Hückel equation wikipedia , lookup
Size-exclusion chromatography wikipedia , lookup
Isotopic labeling wikipedia , lookup
Implicit solvation wikipedia , lookup
Mass spectrometry wikipedia , lookup
Evolution of metal ions in biological systems wikipedia , lookup
Rutherford backscattering spectrometry wikipedia , lookup
Molecular dynamics wikipedia , lookup
Organosulfur compounds wikipedia , lookup
Metalloprotein wikipedia , lookup
Stoichiometry wikipedia , lookup
IUPAC nomenclature of inorganic chemistry 2005 wikipedia , lookup
Gas chromatography–mass spectrometry wikipedia , lookup
6.1 Moles and Molar Masses A mole (mol) is a chemical unit of measurement commonly used in equations and is equal to both... • Avogadro's Number: 6.022e23 particles (602,200,000,000,000,000,000,000) • The molar mass of a substance, found by adding the masses of each atom in that substance's formula. Avogadro's number is similar to a "dozen" in that it refers to a specific number of something. A mol of a substance is just 6.022e23 of that substance, just as a dozen refers to 12 of something. The atomic masses of the periodic table are also molar masses for those elements. Ex. 1.00 mol C = 6.022e23 atoms C = 12.011 g C mol Avo's # Molar Mass ~1~ Molar masses change for each element as 6.022e23 atoms of one element would not have the same mass as 6.022e23 atoms of another. Ex. 1 mol carbon atoms g ≠ 1 mol iron atoms g The same is true for compounds. A mol of CO2 would differ in mass from a mol of NaCl. Ex. 1 mol NaCl (22.99 g+ 35.453 g) 58.443 g ≠ 1 mol CO2 (12.011 g + 32 g) 44.011 g Overall, a mol is just a very large quantity of very small things (atoms, ions, formula units, molecules) which, together, equal a measurable mass in lab. Ex. 1 mol H 1mol Fe2O3 1 mol Cl1 mol H2O = = = = 6.022e23 atoms = 1.008 g H 6.022e23 f.units = 159.69 g Fe2O3 6.022e23 ions = 35.453 g Cl6.022e23 molec. = 18.016 g H2O ~2~ To find the molar mass of an atom, use the atomic mass given on the p. table. Assume ions (+/-) have the same mass as neutral atoms. The gain/loss of electrons has a negligible effect on mass. Ex.1) 1 mol Fe = 6.022e23 atoms Fe = ___________ Ex.2) 1 mol Fe2+ = ________________ = ___________ Ex.3) _______ = 6.022e23 atoms Li = ___________ Ex.4) _______ = _______________ = 14.007 g N3- For compounds, sum up the moles of each atom/ion within the substance. The sum of these masses is the molar mass of the entire compound, M: Ex.5) 1 mol CO2 M(CO2) = = 1 mol C + 2 mol O 12.011 g + 2(16 g) = 44.011 g CO2 ~3~ Ex.6) FeCl2 Contains.... 1 mol Fe and 2 mol Cl M(FeCl2) = Ex.7) Cr(NO3)4 Contains... M(Cr(NO3)4) = Ex.8) (NH4)3N M( (NH4)3N ) = Ex.9) iron (III) chlorate Ex.10) NaC2H3O2 M(NaC2H3O2) = Ex.11) magnesium sulfate Ex.12) Li3PO4 M(Li3PO4) = ~4~ Self-Check Problems: if you are feeling confident, complete these problems and check them against the posted key. Otherwise, we will do them in class. SC.1) Na3N Contains.... M( Na3N ) = SC.2) HClO4 Contains.... M(HClO4 ) = Determine the molar masses of..... SC.3) silver chloride SC.4) zinc phosphate: SC.5) sulfuric acid: ~5~ 6.2 Mass / Mole Conversions When to use it: any time you need to convert between grams and moles. Either as a single DA or as a step within a larger problem. Why we learn it: moles are used like "measuring cups" in chemical reactions. This knowledge allows you to control chemical reactions and create specific amounts of product. Ex.1) Give the mass of 2.40 mol pure iron, Fe(s): Ex.2) How many mol KMnO4 are found in 4.528 g KMnO4? ~6~ Ex.3) What is the mass of 2.00 mol hydrobromic acid, in kg? Ex.4) A reaction calls for 0.032 mol sodium carbonate. How many mg do you need to measure out? Ex.5) On average, you exhale 681 g of carbon dioxide each day. What is this is mol? ~7~ Self-Check Problems: if you are feeling confident, complete these problems and check them against the posted key. Otherwise, we will do them in class. SC.1) What is the mass of 3.50 mol Li2O, in kg? SC.2) How many moles are contained by 240 mg of silver metal? SC.3) What is the mass, in g, of 7.61 mol sodium chloride? ~8~ SC.4) An equation calls for 4.00 g plutonium metal. What is this in moles? SC.5) Calculate the mass of gold (IV) nitrate, in grams, necessary for an equation if 2.50 mol are required. ~9~ 6.3 Mole and Particle Conversions When to use it: any time you need to convert between moles and particles. Particles = atoms, ions, formula units, or molecules. Why we learn it: particles are part of the abstract "idea" of chemistry. Through moles, we can link the ideas of chemistry to the real-world. Conversions between moles and particles of the same substance are easy, one-step problems which require you to use Avogadro's number: 6.022e23. Ex.1) How many atoms of gold are in 0.30 mol Au? ~ 10 ~ Ex.2) Convert 2.00e5 molecules of OF2 into moles: Ex.3) How many formula units of Fe2O3 are in 0.9 mol? Some problems are more complex and involve atoms/ions within larger compounds. These are typically two-step problems involving Avo's number and a whole number conversion: Ex.4) How many ions of Na+ are found in 3.4 mol Na2S ? ~ 11 ~ Ex.5) How many H+ ions are in 7 mol H3PO4? Ex.6) How many molecules of carbon dioxide could be assembled from 280 atoms of oxygen? Ex.7) Calculate the number of moles of rust, Fe3O4 , which could be formed from 8.25e25 oxygen ions: ~ 12 ~ Self-Check Problems: if you are feeling confident, complete these problems and check them against the posted key. Otherwise, we will do them in class. SC.1) How many molecules of oxygen gas, O2, would be contained by 54.0 mol O2? SC.2) How many oxygen atoms are contained by 0.200 mol O2 gas? ~ 13 ~ SC.3) Calculate the number of moles of iron metal found in 7.2e20 iron atoms: SC.4) Determine the number of oxygen ions contained by 120 formula units of iron (III) nitrate: SC.5) Given 0.400 mol carbonic acid, how many atoms of carbon do you have? ~ 14 ~ 6.4 Multi-Step Conversions When to use it: any time you are attempting to convert between mass and particles. You'll have to use moles as the "bridge" between these measurements. Your Conversion Cheat Sheet is an excellent tool for this chapter. Why we learn it: you can now connect the theory (particles) of chemistry to the real world (mass). Ex.1) What is the mass of a single atom of gold? Ex.2) How many atoms of fluorine are found in 34 g ArF2? ~ 15 ~ Ex.3) After walking through the desert, you find you've lost 172 g of mass. Assuming this is completely water, how many molecules of water have you lost? Ex.4) Calculate the mass of a single oxygen molecule, O2: Ex.5) A gallon of water is equal to 3.78 L and water has a density of 1.00 g = 1.00 mL. Knowing this, how many water molecules are found in a gallon of water? ~ 16 ~ Self-Check Problems: if you are feeling confident, complete these problems and check them against the posted key. Otherwise, we will do them in class. SC.1) A pure copper penny (before 1982) has a mass of 3.1 g. Calculate the number of copper atoms used to make a single pure copper penny. SC.2) How many oxygen atoms are found in 1.600 kg of sodium oxalate, Na2C2O4? ~ 17 ~ SC.3) Determine the mass, in mg, of 1.05e19 formula units of silver oxide: SC.4) My skeleton has a dry mass of 20.45 kg and is composed of calcium phosphate. How many calcium ions are contained by my skeleton? SC.5) How many mg of sulfuric acid could be manufactured from 1.6e22 atoms of sulfur? ~ 18 ~ 6.5 Percent Composition Percent composition is a way of breaking down a compound to show the percentage of each atom, ion, or (for hydrates) molecule by mass. % Composition = Total Mass of Substance x 100% Molar Mass of Compound Calculate the % composition of sugar, C12H22O11 Carbon: 12 x 12.011 g x 100% 342.31 g % Carbon = 42.1% Hydrogen: 22 x 1.008 g 342.31 g x 100% % Hydrogen = 6.5 % Oxygen: 11 x 16 g 342.31 g x 100% % Oxygen = 51.4 % ~ 19 ~ The most common use of percent composition is to determine the percent, by mass, of individual elements within the compound: Ex.1) Give the % composition (both Na and Cl) for table salt, NaCl: Ex.2) What is the percent composition of carbon within sodium carbonate? ~ 20 ~ You can also determine the percent water within larger compounds, such as hydrates. Instead of single elements, compare the mass of the dry compound (anhydrate) against the mass of water. Ex.3) What is the mass percentage of water in calcium chloride dihydrate? Ex.4) Determine the % by mass of the anhydrate in cobalt (II) chloride tetrahydrate: ~ 21 ~ Self-Check Problems: if you are feeling confident, complete these problems and check them against the posted key. Otherwise, we will do them in class. SC.1) What is the % composition of perchloric acid? SC.2) What is the % water within magnesium sulfate pentahydrate? ~ 22 ~ 6.6 Empirical and Molecular Formulas When to use it: as a method to predict the formula of an unknown compound in lab. Why we learn it: you can use your lab data to determine chemical formulas. Historically, much of what we know about chemical bonding and compounds was developed using empirical formulas. An empirical formula represents the simplest whole number ratios between elements within a compound. Essentially, it's a simplified version of a molecular (full, covalent) formula: Glucose: Ex.1) Octane: Oxalic Acid: Fructose: C6H12O6 (Molecular) → C8H18 H 2 C2 O 4 C5H10O5 → → → ~ 23 ~ CH2O (Empirical) Ionic compounds are already simplified. Their normal formulas ARE their empirical formulas: Ex.2) Table Salt: NaCl Iron (III) oxide: Fe2O3 Zinc phosphate: Zn3(PO4)2 → → → You can convert between molecular and empirical formulas if you have the molar mass of the original compound: Ex.3) A compound's empirical formula is C2H5 and the molar mass is experimentally determined to be approximately 58 g. Give the molecular formula for this compound: Ex.4) Empirical: N2O CH4 CH2O M: 176 g 16 g 180 g ~ 24 ~ Molecular: Empirical formulas can be calculated from lab data, allowing us to identify unknown compounds: STEP 1: Assume mass percentages represent masses, in g: STEP 2: Divide each element's mass by their respective molar masses, turning them into moles. STEP 3: Divide all moles by the lowest number of moles in the formula thus far. These numbers will give you the ratios in the empirical formula. You may have to multiply to get whole numbers. Ex.5) Determine the empirical formula for a compound known to be 75% carbon and 25% hydrogen: ~ 25 ~ Ex.6) A compound contains 13.5 g Ca, 10.8 g O, and 0.675 g hydrogen. What is its empirical formula? Occasionally, your mole ratios (after step 3) will be fractional instead of whole numbers. Ends in 0.25 multiply by 4. Ends in 0.50, multiply by 2. Ends in 0.33 or 0.67, multiply by 3. Ex.7) Give the empirical formula for a compound which is 71.98% carbon, 6.71% hydrogen, and 21.3% oxygen. ~ 26 ~ Ex.8) Analysis of an aspirin tablet gives 60.00% C, 4.48% H, and 35.52% O. Give the empirical formula for aspirin: You can combine empirical formula calculations with molar masses to "scale up" and determine the original molecular formulas for a substance: Ex.9) Determine the molecular formula for a compound if it contains 50.05% sulfur and 49.95% oxygen by mass and has a molar mass of 192 g/mol. ~ 27 ~ These calculations can also be applied to determine the number of water molecules within a hydrate. Instead of individual elements, compare the ratio of the compound to that of water. Ex.10) Copper (II) sulfate exists as a hydrate. In lab, a 2.60 g sample of the hydrate is heated in a crucible for several minutes, allowing the water to be vaporized from the sample. When cooled, the mass of the sample is now 1.66 g. Calculate the empirical formula of this hydrate and name it: ~ 28 ~ Self-Check Problems: if you are feeling confident, complete these problems and check them against the posted key. Otherwise, we will do them in class. SC.1) Calculate the empirical formula for a compound which is 13.6% phosphorus and 86.4% selenium: SC.2) Determine the empirical and molecular formulae for a compound which is 39.14% carbon and 60.86% nitrogen if it has a molar mass of 460 g/mol: ~ 29 ~ SC.3) A 5.00 g sample of a sodium sulfate hydrate is placed in a crucible and heated to drive off the water. If the dry (anhydrous) compound has a mass of 2.20 g, give the formula and name of this hydrate: ~ 30 ~ ~ 31 ~