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Question (a) Find the constants a,b,c so that the force feild defined by (x + 2y + az)i + (bx − 3y − z)j + (4x + cy + 2z)k is conservative. (b) What is the potential associated with this force field when a, b, c are chosen to make it conservative. Answer We require ∇ × F = 0 0 = ¯ ¯ i ¯ ¯ ∂ ¯ ∂x ¯ ¯ (x + 2y + az) j k ∂ ∂y (bx − 3y − z) = i(c + 1) + j(a − 4) + k(b − 2) ¯ ¯ ¯ ¯ ∂ ¯ ∂z ¯ (4x + cy + 2z) ¯ Therefore a = 4, b = 2, c = −1. F = (x + 2y + 4z)i + (2x − 3y − z)j + (4x − 1y + 2z)k ∂U ∂U ∂U i− j− k = − ∂x ∂y ∂z ∂u = −(x + 2y + 4z) ∂x ⇒ U = − 12 x2 − 2xy − 4xz + f1 (y, z) (1) − ∂U = −(2x − 3y − 2) ∂y ⇒ U = −2xy + 32 y 2 + yz + f2 (x, z) − (2) ∂U = −(4x − y + 2z) ∂z ⇒ U = −4xz + yz + 21 z 2 + f3 (x, z) (3) Comparing: (1) and (2) ⇒ f1 (y, z) = 23 y 2 + yz + g(z) f2 (x, z) = −4xz − 21 x2 g(z) (2) and (3) ⇒ f3 (x, y) = −2xy + 32 y 2 − 12 x2 , g(z) = − 12 z 2 Therefore U = −4x2 + y 2 − 2xy − 12 x2 + 23 y 2 − 21 z 2 − 1