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1) 𝑠𝑜𝑦𝑏𝑒𝑎𝑛 + 𝑐𝑜𝑟𝑛𝑚𝑒𝑎𝑙 = 280𝑙𝑏𝑠; 𝑠𝑜𝑙𝑣𝑒 𝑓𝑜𝑟 1 𝑣𝑎𝑟𝑖𝑎𝑏𝑙𝑒 => 𝑐 = 280 − 𝑠 .14𝑠 + .07𝑐 = .12(280) Substitute 280 – s for c, .14𝑠 + .07(280 − 𝑠) = .12(280) .14𝑠 + .07(280 − 𝑠) = .12(280) .14𝑠 + 19.6 − .07𝑠 = 33.6 .07𝑠 = 14 𝑠𝑜𝑦𝑏𝑒𝑎𝑛 = 200 Now substitute 200 for s in the first equation: 200 + 𝑐𝑜𝑟𝑛𝑚𝑒𝑎𝑙 = 280𝑙𝑏𝑠 𝑐𝑜𝑟𝑛𝑚𝑒𝑎𝑙 = 80𝑙𝑏𝑠 2) The domain of an equation is all possible values of x. As we know, fractions are undefined when x = 0. So in this case, the domain would be all values of x, except for those which make the denominator equal to 0. 2 − 5𝑥 = 0 2 = 5𝑥 2 =𝑥 5 So, the correct answer here is B. X cannot equal 2/5. 3) 8𝑥 = −56, divide both sides of the equation by 8 and you get: 𝑥 = −7 4) E(t), where t represents the # of years from 1995. The values for t lie on the x-axis. The values for E will lie on the y-axis. Find the slope of the function using the 2 points given: a. (67.3-64.4)/(6-0) = .5 1995 = year 0. The corresponding life expectancy is 64.4. Plug those values into the y=mx+b equation to find the value for b. b. 𝑦 = 𝑚𝑥 + 𝑏 64.4 = (. 5)(0) + 𝑏 𝑏 = 64.4 The answer is: E(t) = .5t + 64.4 Now, for the 2nd part of the problem, substitute 12 for t: .5(12)+64.4 = 70.4 5) slope = change in y values/change in x values slope = [4-(-4)]/[6-(-1)] = 8/7 To graph the line, plot the 2 points and draw a line to connect them. To plot (6,4), go to 6 on the x-axis and up to 4 on the y-axis To plot (-1,-4) go to -1 on the x-axis and down to -4 on the y-axis 6) Solve by elimination. You need to eliminate 1 of the variables. To do this, multiply both sides of the first equation by 3 and the both sides of the 2nd equation by 4. 3(3𝑟 − 4𝑠) = (−11)(3), 𝑤ℎ𝑖𝑐ℎ 𝑖𝑠 𝑒𝑞𝑢𝑎𝑙 𝑡𝑜 9𝑟 − 12𝑠 = −33 4(4𝑟 + 3𝑠) = (52)(4), 𝑤ℎ𝑖𝑐ℎ 𝑖𝑠 𝑒𝑞𝑢𝑎𝑙 𝑡𝑜 16𝑟 + 12𝑠 = 208 Now add the 2 equations together: 25𝑟 = 175 𝑟=7 Now substitute 7 for r in one of the equations: 3(7) − 4𝑠 = −11 −4𝑠 = −32 𝑠=8 The ordered pair would be (r,s) or (7,8) 7) Solve for y to put the equation into slope-intercept form: 1 𝑦=2− 𝑥 2 The y-intercept is where x=0. Sub in 0 for x, and you get y = 2. Plot a point at (0,2) To find the x-intercept, sub in 0 for y, and solve for x. You get x=4. Plot a point at (4,0). Draw a line connecting the 2 points. 8) 2L + 2W > 82 2(10) + 2W > 82 2W > 62 W > 31 9) Plot a point at (6,-4). Extend the vertical line only in the upward direction since y is greater than -4, and the horizontal line only gets extended to the right since x is greater than 6. 10) A, consistent, dependent 11) D 12) 9(𝑤 − 2) = 18 9𝑤 − 18 = 18 9𝑤 = 36 𝑤=4 13) Count how many units up and to the right the 2 points are apart: Slope = rise/run = 3/2 14) 8𝑥 − 5𝑥 − 6 = 18 3𝑥 = 24 𝑥=8 15) Substitute 39 for x in the given equation and you get 178.73 16) Start in the middle at (0,0) and go up to 8 on the y-axis and draw a horizontal line extending to the right and left. 17) C 18) Graph the points (0,2) and (3,0). Draw a downward sloping line, and shade the area on to the right of the line. 19) Start in the center at (0,0) and go up to 4 and plot the point. 1 20) −7(15)𝑥 > 15 (15) −105𝑥 > 1 1 𝑥<− 105 21) B 22) Convert to slope-intercept form. Since the slopes are negative reciprocals, the lines are perpendicular. Answer is B 23) 24) (3,-3) 25) 26 26) ≥ 11.25 27) 2005 = 18,268 2008 = 12,937 2010 2 28) − 9 29) Plot a point at (0,2). Plot your next point up 5 units and 4 to the right at (4,7). Connect the 2 points. 21 30) 20 31) Plug in the numbers to see if the given ordered pair is a solution. Since 2(-3) – 3(-1) is not equal to 20, (-3,-1) is NOT a solution. Answer is: NO 13 32) − 3 𝑎𝑛𝑑 33) C 34) B 35) B, A 36) f(0) = 0 f(-1) = 6 f(2) = 0 1 3 37) 50 38) D 17 39) − 2 40) Y-intercept (0,-8) For the graph, plot the y-intercept (0.-8), and (8,-16) and connect the 2 points 41) > 42) 0.27y 43) d/6 44) B 45) 1 46) X< 2 47) 90 48) No 49) (-8,5) 50) 91.58 51) 152 52) Plot the points (0,2) and (10,0). Draw a line to connect the 2 points and extend the line in both directions. 53) 3 months service = $100, C, Graph D 54) 6 55) Slope = -4 y-intercept = -8 56) 9r – 5s