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Chemistry - Chap 19-20 Study Guide 1.What is the most common oxidation number of combined oxygen? Rule a. –2 c. 0 b. –1 d. +1 2.The algebraic sum of the oxidation numbers of the atoms in a compound Rule a. is always zero. c. is always –1. b. is always +1. d. can be any whole number. 3.What are the oxidation numbers in the compound KCl? Follow Rules a. K = 0, Cl = 0 c. K = +1, Cl = –1 b. K = –1, Cl = +1 d. K = +2, Cl = –2 4.What are the oxidation numbers in the ion SO32–? Follow Rules a. S = +6, O = –2 c. S = +4, O = –2 b. S = +1, O = –1 d. S = 0, O = –1 5.In an oxidation, atoms or ions Definition a. increase their oxidation number. b. decrease their oxidation number. c. do not change their oxidation number. d. have a zero oxidation number after the reaction. 6. In a reduction, atoms or ions Definition a. increase their oxidation number. b. decrease their oxidation number. c. do not change their oxidation number. d. have a zero oxidation number after the reaction. Def by a bunch of ways 7. In the reaction O2 + 4e– → 2 O–2, the species O2 is a. oxidized. c. electrolyzed. b. reduced. d. autooxidized. 8. In the reaction 2K + Br2 → 2K+ + 2Br–, which species is reduced? Gain e- :get smaller charge a. K only c. both K and Br2 b. Br2 only d. neither K nor Br2 9. Which of the following is an oxidation-reduction reaction? H to +1 Cl to -1 a. H2 → 2H+ b. 2O– → O22– c. H2 + Cl2 → 2HCl d. HCl + NaBr → HBr + NaCl 10. In a redox reaction, MnO4– is changed to Mn2+. How many electrons must be lost or gained by Mn? +5 to +2 a. two lost c. five lost b. two gained d. five gained 11. How does the number of electrons lost in an oxidation compare with the number gained in the simultaneous reduction? a. The two numbers are always equal. Rule b. The number lost is always greater than the number gained. c. The number lost is always less than the number gained. d. No relationship exists between the two numbers. 12. During redox reactions, oxidizing agents ox ag cause loss they gain a. increase their oxidation number. c. keep the same oxidation number. b. decrease their oxidation number. d. do not participate. 13. During redox reactions, reducing agents see 12 a. increase their oxidation number. c. keep the same oxidation number. b. decrease their oxidation number. d. do not participate. 14. In redox reactions, see 12,13 a. the oxidizing agent is the substance oxidized. b. the reducing agent is the substance oxidized. c. both oxidizing and reducing agents are oxidized. d. the reducing agent is the substance reduced. 15. In redox reactions, see above a. the oxidizing agent is the substance reduced. b. the reducing agent is the substance reduced. c. the oxidizing agent is the substance oxidized. d. both oxidizing and reducing agents are on the same side of the chemical equation. 16. Which is the most active reducing agent among the elements? Best giver (likes to lose) a. cesium c. fluorine b. iodine d. lithium 17. Which is the most active oxidizing agent among the elements? Opposite of #16 a. cesium c. fluorine b. iodine d. lithium 18. In which system does a spontaneous redox reaction produce electrical energy? def a. electrochemical cell c. electroplating cell b. electrolytic cell d. half-cell 19. Where does oxidation take place in an electrochemical cell? Anox redcat a. the anode c. the anode or the cathode b. the cathode d. the half-cell 20. In which cell does a current drive a nonspontaneous redox reaction? def a. electrolytic cell c. electrochemical cell b. dry cell d. voltaic cell 21. Electrons in a voltaic cell normally flow a to c a. from cathode to anode. b. through a porous barrier. c. in both directions through the external circuit. d. from anode to cathode. 22. For electricity to flow in a voltaic cell, the two half-cells must be rule a. connected by a wire and a porous barrier. c. in the same solution. b. completely isolated from one another. d. connected to a dry cell. 23. Which process deposits metal onto a surface? memory a. electrolysis c. autooxidation b. electroplating d. oxidation 24. In an electroplating cell, the object to be plated is the memory a. external circuit. c. anode. b. electrolyte. d. cathode. 25. A dry cell battery is: memory a. a voltaic cell c. an electrolytic cell b. either voltaic or electrolytic d. non-spontaneous 26. A lead-acid battery: memory a. is a voltaic cell when used to start the engine c. is an electrolytic cell when being charged b. is a reversible REDOX reaction d. all of the above 27. Hydrogen and oxygen reaction in a REDOX reaction to produce electricity in: memory a. an electrolytic cell c. a lead acid battery b. a fuel cell d. a dry cell Determine the oxidation number of each underlined atom in the following 28. C2H3O2-1 29. KNO3 30. Cr2O7-2 31. KMnO4 32. Al2O3 33. K2SO3 0 +5 +6 +7 +3 +4 Use a Standard Reduction Table to prove whether the following reaction is spontaneous or nonspontaneous. Determine the positive or negative potential for each reaction. +2 34. Ni + Cu +2 - + Cu →Ni +/59 = spont 35. - Cl + Br → Cl + Br 2 2 Balance each of the following. Provide the half reactions and the oxidizing and reducing agents. +2 -2 36. 2e- + H2O + 2Cu → Cu O +2H+ +2 -2 . 2H2O + 2Cu + HPO Ox agent 3 H2O + HPO 2 -3 → Cu O 2 + PO -2 -2 H SO + MnO → SO 3 -3 → + PO 4 + 3H+ + 2e- + 5H+ red agent 37. H2O + H2SO3 + → SO4 + 4H+ + 2e2 4 3 2 red agent Ox agent 4 +2 + Mn + H2O +2 2e- + 4H++ MnO → + Mn 2 + 2H2O -.29=non 38. Au Au+3 + 3e4H++ 3e- + NO3- 2H2O + NO + 4H + Au + NO3 Au+3 + NO + 2H2O red agent Ox agent 39. C2H2 +4H2O 2 CO2 + 10H++ 10e- 5e- + 8H+ + MnO4- + Mn+2 + 4H2O 6H++ C2H2 + 2 MnO4- 2CO2 + 2Mn+2 + 4H2O Calculate the potential in volts for each of the following spontaneous reactions. Also determine the: a)anode b) cathode c) direction of electron flow (i.e., for each reaction where do the electrons start from and where do they end up) d) oxidizing agent e) reducing agent f) the overall balanced reaction 40. Cr(s) + Ni2+(aq) Ni(s) + Cr2+(aq) Eo = -.25-(-.41) = 0.16v a) anode = Cr b) cath=Ni c)Cr to Ni d)Ni+2 2+ 2+ e)Cr f) 2Cr(s) + 3 Ni (aq) 3 Ni(s) + 2 Cr (aq) o 41. Al(s) + H+(aq) Al3+(aq) + H2(g) E = 1.66 +0 = 1.66v a) anode =Al + 3+ f) . 2 Al(s) + 6H (aq) 2 Al (aq) + 3H2(g) b) cath=Pt c)Al to H2 o 42. Fe2+(aq) + MnO4-(aq) Fe3+(aq) + Mn2+(aq) b) cath=Pt E = 1.51 +.77 = 2.28v a) anode =Pt 2+ + 2+ d) MnO4 e) Fe f) 8H + 5Fe (aq) + MnO4-(aq) 5 Fe3+(aq) + Mn2+ +4H2O(aq) d)H+1 e)Al c) Fe+2 to MnO4-