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Mechanics 1: Newton’s Laws We now switch our attention from kinematics to dynamics. Let’s recall Newton’s Laws of Motion, which we will take as axioms. Newton’s Axioms. 1. Every particle persists in a state of rest or of uniform motion in a straight line (i.e., with constant velocity) unless acted upon by a force. 2. If F is the force acting on a particle of mass m which as a consequence is moving with velocity v, then F= d dp (mv) = , dt dt (1) where p = mv is called the momentum. If m is independent of time t (1) becomes: F=m dv = ma, dt (2) where a is the acceleration of the particle. 3. If particle 1 acts on particle 2 with a force F12 in a direction along the line joining the two particles, while particle 2 acts on particle 1 with a force F21 , then F21 = −F12 . In other words, to every action there is an equal and opposite reaction. Example. A particle of mass m moves in the x − y plane in such a way that its position vector is given by: r = a cos ωti + b sin ωtj (3) where a, b, and ω are positive constants, with a > b. 1. Show that the particle moves in an ellipse. From the expression for the position vector we have: x = a cos ωt, y = b sin ωt, which are just the parametric equations for an ellipse with semi-major axis of length a and semi-minor axis of length b. Since y2 x2 + 2 = cos2 ωt + sin2 ωt = 1, 2 a b the equation for the ellipse can also be taken as: x2 y2 + = 1. a2 b2 2. Show that the force acting on the particle is always acting towards the origin. We will assume that the mass m is constant. Then = d2 d2 r dv = m 2 = m 2 (a cos ωti + b sin ωtj) , dt dt dt 2 m −ω a cos ωti − ω 2 b sin ωtj , = −mω 2 (a cos ωti + b sin ωtj) = −mω 2 r, F = m from which it follows immediately that the force is directed to the origin. 1 Definitions of Force and Mass. Strictly speaking, force and mass are undefined quantities in Newton’s axioms. Intuitively, I expect most of you to have a good idea of what they are. Mass is a measure of the “quantity of matter” in an object. Force is a measure of the “push or pull” on an object. The question of “what is force” and “what is mass” are deep and fundamental. They are questions of current interest in elementary particle physics and quantum field theory (so beyond the scope of this course). It is possible to “define” force and mass through Newton’s axioms. Some mechanics books take this approach, but fundamentally, it is not satisfactory (you might think “why not”?). Units and Dimensions. It is appropriate at this point to say something about dimensions since we will seeon be encountering a number of new quantities that are measured with respect to specific types of units. We saw earlier, that the basic dimensions that we will encounter in this course are length, mass, and time. There will be two systems of units that we will use to describe each: the centimeter-gram-second (cgs) system and the meter-kilogram-second (mks) system. Units for various quantities are given in Table 1. Physical Quantity Length Mass Time Velocity Acceleration Dimensions L M T LT−1 LT−2 CGS System cm gm sec cm/sec cm/sec2 gm cm/sec2 Force MLT −2 = dyne gm cm/sec MKS System m kg sec m/sec m/sec2 kg m/sec2 = newton kg m/sec Momentum, Impulse MLT−1 = dyne sec ML2 T−2 gm cm2 /sec2 kg m2 /sec2 Energy, Work = dyne cm = erg = nt m = joule gm cm2 /sec3 kg m2 /sec3 Power Volume Density Angle Angular Velocity Angular Acceleration MLT−3 L3 ML−3 none T−1 T−2 = dyne cm/sec = erg/sec cm3 gm/cm3 radian (rad) rad/sec rad/sec2 = joule/sec = watt m3 kg/m3 rad rad/sec rad/sec2 ML2 T−2 ML2 T−1 ML2 gm cm2 /sec2 Torque Angular Momentum Moment of Inertia = dyne cm gm cm2 /sec gm cm2 kg m2 /sec2 = nt m kg m2 /sec kg m2 Pressure −1 gm/(cm sec2 ) 2 kg/(m sec2 ) 2 ML T −2 = dyne/cm = nt sec = nt/m Table 1: Units and Dimensions In terms of units, we can give a definition of force. A dyne is the force that will give a 1 gm mass an acceleration of 1 cm/sec2 . A newton is the force that will give a 1 kg mass an acceleration of 1 m/sec2 . Inertial Frames of Reference and Absolute Motion. It needs to be stated that in the course of reasoning from experience that led to Newton’s axioms it was always assumed that all measurements or observations were made with respect to a coordinate system or frame of reference which was fixed in space, i.e., absolutely at rest. This is the assumption that space or motion is absolute. We show that to observers in two different coordinate systems a particle appears to have the same force acting on it if and only if the coordinate systems are moving at constant velocity with respect to each other. This is sometimes called the classical principle of relativity. 2 z' P y' z r' r j' k' O' i' R = r - r' k i y j O x' x Figure 1: We consider two observers, O and O’, each located at the origin of a different coordinate system, denoted x − y − z and x′ − y ′ − z ′ , respectively. Each observer observes the motion of a particle P in space. The position vector of P in the x − y − z coordinates system is denoted my r and the position vector of P in the x′ − y ′ − z ′ coordinate system is denoted by r′ . The vector R = r − r′ locates the origin of the x′ − y ′ − z ′ coordinate system with respect to the x − y − z coordinate system, se Fig. 1. Relative to observers O and O’ the forces acting on P according to Newton’s laws are given, respectively, by: F=m d2 r , dt2 F′ = m d2 r′ . dt2 (4) The difference in observed forces is: F − F′ = m d2 R d2 ′ (r − r ) = m , dt2 dt2 (5) and this will be zero if and only if: dR d2 R = 0, or = constant, (6) dt2 dt i.e., the coordinate systems are moving at constant velocity relative to each other. Such coordinate systems are called inertial coordinate systems. 3