Download x2 + 4x – 1 = 4 x2 – 6x – 16 = 0 a.) 3x2 + x – 6 = 0 2x2 – 7x + 5 = 0

Name: __________________________________
Algebra I
Ch. 9.5-9.7 Quadratics
Block: ____-____
Unit 7
Evidence #2
*REVIEW*
Organize & show all work for full credit. Give exact answers (& approximate to nearest hundredth if needed).
1.) Solve the given quadratic equations by completing the square.
a.)
x2 + 4x – 1 = 4
b.)
_______________
x2 – 6x – 16 = 0
________________
2.) Solve the given quadratic equations by using the Quadratic Formula. Write answer(s) in exact form. Also, write the
approximate solutions (when applicable) rounded to the nearest hundredth.
a.)
3x2 + x – 6 = 0
________________
b.)
2x2 – 7x + 5 = 0
c.)
________________
x2 – 3x + 4 = 0
________________
3.) Factor each quadratic expression completely to solve.
a.)
x2 + x – 6 = 0
______________
b.)
𝟔𝒙𝟐 – 7x – 5 = 0
______________
c.)
2𝒙𝟐 + 1𝟖𝒙 + 36 = 0
_____________
4.) Tell whether each statement is TRUE or FALSE. If the statement is false, change the right side to make it true.
Give the corrected right side in the same form as the incorrect original.
Ex.) If the right side is given in factored form, write the corrected version in factored form.
Recall:
General form
Vertex form
Factored form
2
2
y = ax + bx + c
y = a(x – h) + k
y = a(x – r1)(x – r2)
True or False?
a.) _____
True or False?
x2 + 5x – 24 = (x + 3)(x – 8)
x2 + 5x – 24 =
c.) _____
2(x – 1)2 + 3 = 2x2 – 4x + 5
2(x – 1)2 + 3 =
________________
(x + 3)2 = x2 + 9
(x + 3)2 =
b.) _____
d.) _____
_________________
_________________
(x + 2)(x – 5) = x2 – 10
(x + 2)(x – 5) =
_________________
5.) The width of a rectangle is 8cm less than the length. The area of the rectangle is 240cm2.
a.)
Write an equation for width (w) in terms of length (l).
w = ____________
b.)
Write an equation for the area of the rectangle in terms of the length, l.
c.)
Solve algebraically for the length of this rectangle.
d.)
Give the dimensions of this rectangle. _____cm. by _____ cm.
l = ________
A = ________________