Download Geometry 2: Trigonometry Name Unit Review Period Date G.SRT.6

Geometry 2: Trigonometry
Unit Review
Name ______________________________________
Period _______________ Date _________________
G.SRT.6 Learning Target: Understand that by
similarity, side ratios in right triangles are properties of
the angles in the triangle, leading to definitions of
trigonometric ratios for acute ratios.
4) Darren started with a 5-12-13 right triangle
( HKI ) and then reflected it horizontally to get
a congruent triangle, JKI . The length of HK
1) Given the following trig ratios, what is the length
of AC?
is 5 cm.
A
C
36
12
13
5
cos A 
13
12
tan A 
5
sin A 
B
H
K
J
Answer: ______________
2). Complete the following trig ratios for
I
ACB
Then, Darren claimed the following:
-
Since HK is 5 cm, then JK is also 5 cm.
and KI is 12 cm.
-
Using the Pythagorean Theorem, the length
of HI and JI is 13 cm.
-
The length of HJ is 10 cm.
-
Therefore, tan ( IHK ) =
5
 0.42
12
(rounded)
sin A =
cos A =
3) Given ABO
= 20, what is the
length of LK?
Answer:
______________
tan A =
KLJ . If the cos A = 0.6 and JK
Sadly, Darren went wrong somewhere in his
assumptions. Find his mistake and correct it.
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G.SRT.7 Learning Target: Explain and use the
G.SRT.8 Learning Target: Use trigonometric
relationship between the sine and cosine of
complementary angles.
ratios and the Pythagorean Theorem to solve right
triangles in applied problems
5. Write sin 50° in terms of cosine. Then, explain
how cosine and sine are related in a given triangle.
Answer: _______
8) Which
expression(s) can be
used to find the value
of x in the triangle?
There may be more
than one.
Explanation:
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(a) cos 59 
6) In the right triangle ABC, A and B are
complementary angles. Which statement is TRUE?
C
20
48
A
B
(b) cos 59  x
14
14
(c) sin 59 
x
x
(d) sin 59 
14
(e) sin 31 
52
14
x
14
x
(f) tan 59  14
a) The cos A and the sin B are both equal to
x
12 .
13
5
b) The cos A= 12 and the sin B =
.
13
13
c) The cos A and the sin B are both equal to 5
13
5
12
d) The cos A=
and the sin B =
.
13
13
Answer: ______________
7). What is the solution to the following
equation? Round your answer to the nearest
tenth.
cos (2x + 18)° = sin (4x + 5)°
Answer: ______________
Answer(s)______________
9). Which expression CANNOT be used to find the
length of LM ?
(a) tan 55 
8.6
x
(b) sin 35 =
x
8.6
(c) cos 55 =
x
12.5
(d) tan 35 
x
8.6
Answer: ________
10) A tower is anchored to the ground by a wire.
How far away is the wire from the base of the
tower if it is attached to the top of a 50-ft
antenna and makes a 70° angle with the
ground? Round to the nearest tenth.
12) If the length of each side of the square sign
shown below is 15 inches, how long is the diagonal?
(Round to the nearest inch.)
Answer: ______________
11). You are flying a kite!! The angle of depression
is 23º. If your eyes are five feet high, how high off
the ground is the kite? Round your answer to the
nearest tenth.
Answer: ________________
Answer: ________________