Download Tutorial 3 (Ans Scheme) ERT 317, Sem 1 2015/2016

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project

Document related concepts

Digestion wikipedia , lookup

Drug design wikipedia , lookup

Microbial metabolism wikipedia , lookup

Signal transduction wikipedia , lookup

Fatty acid metabolism wikipedia , lookup

Photosynthesis wikipedia , lookup

Enzyme inhibitor wikipedia , lookup

Nicotinamide adenine dinucleotide wikipedia , lookup

Light-dependent reactions wikipedia , lookup

Multi-state modeling of biomolecules wikipedia , lookup

Glucose wikipedia , lookup

Glyceroneogenesis wikipedia , lookup

Amino acid synthesis wikipedia , lookup

Biosynthesis wikipedia , lookup

Evolution of metal ions in biological systems wikipedia , lookup

Phosphorylation wikipedia , lookup

Size-exclusion chromatography wikipedia , lookup

Enzyme wikipedia , lookup

Oxidative phosphorylation wikipedia , lookup

Photosynthetic reaction centre wikipedia , lookup

Metabolism wikipedia , lookup

Adenosine triphosphate wikipedia , lookup

Citric acid cycle wikipedia , lookup

Glycolysis wikipedia , lookup

Biochemistry wikipedia , lookup

Transcript
School of Bioprocess Engineering
ERT 317/4
Biochemical Engineering
Sem 1 2015/2016
TUTORIAL 3
(Ans Scheme)
1. Consider the following reaction sequence:
k1
k2
S  E 
ES 
PE
k-1
Derive a rate expression for production formation using:
a) rapid equilibrium approach.
b) quasi-steady-state approach
Please state any assumption for the derivation.
Ans:
a) rapid equilibrium approach.
Assumption:
1) The ES complex is established very rapidly
2) The rate of the reverse reaction of the second step is negligible (i.e k-2~0)
(Assumption 2 is typically only valid when product (P) accumulation is negligible, at
the beginning of the reaction)
Assumption using The Rapid Equilibrium Assumption
Assuming equilibrium in the first part of the reaction (E+S forms ES), we can use the
equilibrium coefficient to express [ES] in terms of [S]
The equilibrium constant is:
Since
, if the enzyme is conserved, then
c) quasi-steady-state approach
Quasi-Steady-State Assumption
•
Briggs and Haldane first proposed Quasi-steady-state assumption
•
In a batch reactor at closed system, [E0] is considered very small compared S
Therefore, d(ES)/dt ≈0
From equation
2. The pathway of glycolysis can be seen as consisting of two separate phases. The first is
the chemical priming phase requiring energy in the form of ATP, and the second is
considered the energy-yielding phase.
(i) Demonstrate the individual reactions of glycolysis by the aid of diagram.
(ii)
Briefly explain the pathway of glycolysis from glucose into pyruvate.
Step 1
The enzyme hexokinase phosphorylates (adds a phosphate group to) glucose in the
cell's cytoplasm. In the process, a phosphate group from ATP is transferred to
glucose producing glucose 6-phosphate.
Glucose (C6H12O6) + hexokinase + ATP → ADP + Glucose 6-phosphate
(C6H11O6P1)
Step 2
The enzyme phosphoglucoisomerase converts glucose 6-phosphate into its isomer
fructose 6-phosphate. Isomers have the same molecular formula, but the atoms of
each molecule are arranged differently.
Glucose 6-phosphate (C6H11O6P1) + Phosphoglucoisomerase → Fructose 6phosphate (C6H11O6P1)
Step 3
The enzyme phosphofructokinase uses another ATP molecule to transfer a
phosphate group to fructose 6-phosphate to form fructose 1, 6-bisphosphate.
Fructose 6-phosphate (C6H11O6P1) + phosphofructokinase + ATP → ADP +
Fructose 1, 6-bisphosphate (C6H10O6P2)
Step 4
The enzyme aldolase splits fructose 1, 6-bisphosphate into two sugars that are
isomers of each other. These two sugars are dihydroxyacetone phosphate and
glyceraldehyde phosphate.
Fructose 1, 6-bisphosphate (C6H10O6P2) + aldolase → Dihydroxyacetone phosphate
(C3H5O3P1) + Glyceraldehyde phosphate (C3H5O3P1)
Step 5
The enzyme triose phosphate isomerase rapidly inter-converts the molecules
dihydroxyacetone phosphate and glyceraldehyde phosphate. Glyceraldehyde
phosphate is removed as soon as it is formed to be used in the next step of
glycolysis.
Dihydroxyacetone phosphate (C3H5O3P1) → Glyceraldehyde phosphate (C3H5O3P1)
Net result for steps 4 and 5: Fructose 1, 6-bisphosphate (C6H10O6P2) ↔ 2 molecules
of Glyceraldehyde phosphate (C3H5O3P1)
Step 6
The enzyme triose phosphate dehydrogenase serves two functions in this step. First
the enzyme transfers a hydrogen (H-) from glyceraldehyde phosphate to the
oxidizing agent nicotinamide adenine dinucleotide (NAD+) to form NADH. Next
triose phosphate dehydrogenase adds a phosphate (P) from the cytosol to the
oxidized glyceraldehyde phosphate to form 1, 3-bisphosphoglycerate. This occurs
for both molecules of glyceraldehyde phosphate produced in step 5.
A. Triose phosphate dehydrogenase + 2 H- + 2 NAD+ → 2 NADH + 2 H+
B. Triose phosphate dehydrogenase + 2 P + 2 glyceraldehyde phosphate (C3H5O3P1)
→ 2 molecules of 1,3-bisphosphoglycerate (C3H4O4P2)
Step 7
The enzyme phosphoglycerokinase transfers a P from 1,3-bisphosphoglycerate to a
molecule of ADP to form ATP. This happens for each molecule of 1,3bisphosphoglycerate. The process yields two 3-phosphoglycerate molecules and two
ATP molecules.
2 molecules of 1,3-bisphoshoglycerate (C3H4O4P2) + phosphoglycerokinase + 2
ADP → 2 molecules of 3-phosphoglycerate (C3H5O4P1) + 2 ATP
Step 8
The enzyme phosphoglyceromutase relocates the P from 3-phosphoglycerate from
the third carbon to the second carbon to form 2-phosphoglycerate.
2 molecules of 3-Phosphoglycerate (C3H5O4P1) + phosphoglyceromutase → 2
molecules of 2-Phosphoglycerate (C3H5O4P1)
Step 9
The enzyme enolase removes a molecule of water from 2-phosphoglycerate to form
phosphoenolpyruvic acid (PEP). This happens for each molecule of 2phosphoglycerate.
2 molecules of 2-Phosphoglycerate (C3H5O4P1) + enolase → 2 molecules of
phosphoenolpyruvic acid (PEP) (C3H3O3P1)
Step 10
The enzyme pyruvate kinase transfers a P from PEP to ADP to form pyruvic acid
and ATP. This happens for each molecule of PEP. This reaction yields 2 molecules
of pyruvic acid and 2 ATP molecules.
2 molecules of PEP (C3H3O3P1) + pyruvate kinase + 2 ADP → 2 molecules of
pyruvic acid (C3H4O3) + 2 ATP
Summary
In summary, a single glucose molecule in glycolysis produces a total of 2 molecules
of pyruvic acid, 2 molecules of ATP, 2 molecules of NADH and 2 molecules of
water.
Although 2 ATP molecules are used in steps 1-3, 2 ATP molecules are generated in
step 7 and 2 more in step 10. This gives a total of 4 ATP molecules produced. If you
subtract the 2 ATP molecules used in steps 1-3 from the 4 generated at the end of
step 10, you end up with a net total of 2 ATP molecules produced.